我如何在c#中生成一个随机的8个字符的字母数字字符串?


当前回答

一个包含所有字母字符和数字的解决方案,你可以随心所欲地更改:

public static string RandomString(int length)
{
    Random rand = new Random();
    string charbase = "ABCDEFGHIJKLMNOPQRSTUVWXYZabcdefghijklmnopqrstuvwxyz0123456789";
    return new string(Enumerable.Range(0,length)
           .Select(_ => charbase[rand.Next(charbase.Length)])
           .ToArray());
}

如果你喜欢单行方法;)

public static Random rand = new Random();
public const string charbase = "ABCDEFGHIJKLMNOPQRSTUVWXYZabcdefghijklmnopqrstuvwxyz0123456789";
 

public static string RandomString(int length) =>
        new string(Enumerable.Range(0,length).Select(_ => charbase[rand.Next(charbase.Length)]).ToArray());

其他回答

下面是Eric J的解决方案的一个变体,即加密声音,用于WinRT (Windows商店应用程序):

public static string GenerateRandomString(int length)
{
    var chars = "abcdefghijklmnopqrstuvwxyzABCDEFGHIJKLMNOPQRSTUVWXYZ1234567890";
    var result = new StringBuilder(length);
    for (int i = 0; i < length; ++i)
    {
        result.Append(CryptographicBuffer.GenerateRandomNumber() % chars.Length);
    }
    return result.ToString();
}

如果性能很重要(特别是当长度很高时):

public static string GenerateRandomString(int length)
{
    var chars = "abcdefghijklmnopqrstuvwxyzABCDEFGHIJKLMNOPQRSTUVWXYZ1234567890";
    var result = new System.Text.StringBuilder(length);
    var bytes = CryptographicBuffer.GenerateRandom((uint)length * 4).ToArray();
    for (int i = 0; i < bytes.Length; i += 4)
    {
        result.Append(BitConverter.ToUInt32(bytes, i) % chars.Length);
    }
    return result.ToString();
}
var chars = "ABCDEFGHIJKLMNOPQRSTUVWXYZabcdefghijklmnopqrstuvwxyz0123456789";
var stringChars = new char[8];
var random = new Random();

for (int i = 0; i < stringChars.Length; i++)
{
    stringChars[i] = chars[random.Next(chars.Length)];
}

var finalString = new String(stringChars);

不如Linq解决方案优雅。

(注意:Random类的使用使得它不适用于任何与安全性相关的事情,比如创建密码或令牌。如果你需要强随机数生成器,请使用RNGCryptoServiceProvider类。)

我们也使用自定义字符串随机,但我们实现的是字符串的帮助器,所以它提供了一些灵活性…

public static string Random(this string chars, int length = 8)
{
    var randomString = new StringBuilder();
    var random = new Random();

    for (int i = 0; i < length; i++)
        randomString.Append(chars[random.Next(chars.Length)]);

    return randomString.ToString();
}

使用

var random = "ABCDEFGHIJKLMNOPQRSTUVWXYZ".Random();

or

var random = "ABCDEFGHIJKLMNOPQRSTUVWXYZabcdefghijklmnopqrstuvwxyz0123456789".Random(16);

我简单的一行代码为我工作:)

string  random = string.Join("", Guid.NewGuid().ToString("n").Take(8).Select(o => o));

Response.Write(random.ToUpper());
Response.Write(random.ToLower());

对任意长度的字符串展开

    public static string RandomString(int length)
    {
        //length = length < 0 ? length * -1 : length;
        var str = "";

        do 
        {
            str += Guid.NewGuid().ToString().Replace("-", "");
        }

        while (length > str.Length);

        return str.Substring(0, length);
    }
 public static string RandomString(int length)
    {
        const string chars = "ABCDEFGHIJKLMNOPQRSTUVWXYZabcdefghijklmnopqrstuvwxyz0123456789";
        var random = new Random();
        return new string(Enumerable.Repeat(chars, length).Select(s => s[random.Next(s.Length)]).ToArray());
    }