你如何创建一个目录www在/srv上基于debian的系统使用Ansible剧本?
当前回答
enter code here
- name: creating directory in ansible
file:
path: /src/www
state: directory
owner: foo
你可以参考可靠的文档
其他回答
您需要文件模块。要创建目录,您需要指定选项状态:directory:
- name: Creates directory
file:
path: /src/www
state: directory
你可以在https://docs.ansible.com/ansible/latest/collections/ansible/builtin/file_module.html上看到其他选项
您甚至可以扩展文件模块,甚至可以通过它设置所有者、组和权限。(参考:Ansible文件文档)
- name: Creates directory
file:
path: /src/www
state: directory
owner: www-data
group: www-data
mode: 0775
甚至,你可以递归地创建目录:
- name: Creates directory
file:
path: /src/www
state: directory
owner: www-data
group: www-data
mode: 0775
recurse: yes
这样,如果这两个目录不存在,它将创建它们。
你可以用以下方法之一来做这件事:
例1:如果父目录已经存在:
- name: Create a new directory www at given path
ansible.builtin.file:
path: /srv/www/
state: directory
mode: '0755'
例2:父目录不存在:
- name: Create a new directory www at given path recursively
ansible.builtin.file:
path: /srv/www/
state: directory
mode: '0755'
recurse: yes
在示例2中,如果两个目录都不存在,它将递归地创建它们。
有关file_module的更多信息,您可以查看官方文档
在这种情况下,您需要使用文件模块。下面的剧本,你可以使用你的参考。
---
- hosts: <Your target host group>
name: play1
tasks:
- name: Create Directory
files:
path=/srv/www/
owner=<Intended User>
mode=<Intended permission, e.g.: 0750>
state=directory
使用文件模块创建一个目录,并使用命令“ansible-doc file”获取文件模块的详细信息
这里有一个选项“state”解释:
If directory, all immediate subdirectories will be created if they do not exist, since 1.7 they will be created with the supplied permissions. If file, the file will NOT be created if it does not exist, see the [copy] or [template] module if you want that behavior. If link, the symbolic link will be created or changed. Use hard for hardlinks. If absent, directories will be recursively deleted, and files or symlinks will be unlinked. Note that file will not fail if the path does not exist as the state did not change. If touch (new in 1.4), an empty file will be created if the path does not exist, while an existing file or directory will receive updated file access and modification times (similar to the way touch works from the command line).