对于我的应用程序，我们也通过下载小文件进行测试。

string remoteUri = "https://www.microsoft.com/favicon.ico"

WebClient myWebClient = new WebClient();

try
{
    byte[] myDataBuffer = myWebClient.DownloadData (remoteUri);
    if(myDataBuffer.length > 0) // Or add more validate. eg. checksum
    {
        return true;
    }
}
catch
{
    return false;
}

也。有些ISP可能使用中间服务器缓存文件。添加未使用的随机参数。https://www.microsoft.com/favicon.ico?req=random_number 可以防止缓存。

public static bool CheckForInternetConnection(int timeoutMs = 10000, string url = null)
{
    try
    {
        url ??= CultureInfo.InstalledUICulture switch
        {
            { Name: var n } when n.StartsWith("fa") => // Iran
                "http://www.aparat.com",
            { Name: var n } when n.StartsWith("zh") => // China
                "http://www.baidu.com",
            _ =>
                "http://www.gstatic.com/generate_204",
        };

        var request = (HttpWebRequest)WebRequest.Create(url);
        request.KeepAlive = false;
        request.Timeout = timeoutMs;
        using (var response = (HttpWebResponse)request.GetResponse())
            return true;
    }
    catch
    {
        return false;
    }
}

你绝对没有办法可靠地检查是否有互联网连接(我想你的意思是访问互联网)。

但是，您可以请求几乎从未离线的资源，例如ping google.com或类似的东西。我认为这是有效的。

try { 
    Ping myPing = new Ping();
    String host = "google.com";
    byte[] buffer = new byte[32];
    int timeout = 1000;
    PingOptions pingOptions = new PingOptions();
    PingReply reply = myPing.Send(host, timeout, buffer, pingOptions);
    return (reply.Status == IPStatus.Success);
}
catch (Exception) {
    return false;
}

根据@ChaosPandion的回答，为了尽可能确保结果是正确的，你可以像其他人指出的那样，包括多个大网站。但是，这应该异步完成，以避免太长的等待时间。此外，WebRequest、HttpWebRequest和HttpWebResponse类现在已经过时，应该被HttpClient取代。以下示例考虑了上述因素:

public static async Task<bool> CheckForInternetConnection(TimeSpan? timeoutMs = null, List<string> urls = null)
{
    if (timeoutMs == null)
    {
        timeoutMs = TimeSpan.FromSeconds(10);
    }

    var culture = CultureInfo.InstalledUICulture;
    if (urls == null)
    {
        urls = new List<string>();

        if (culture.Name.StartsWith("fa"))      // Iran
            urls.Add("http://www.aparat.com");
        else if (culture.Name.StartsWith("zh")) // China
            urls.Add("http://www.baidu.com");
        else
        {
            urls.Add("https://www.apple.com/");
            urls.Add("https://www.gstatic.com/generate_204");
        }
    }

    var client = new HttpClient();
    client.Timeout = (TimeSpan)timeoutMs;
    List<Task<string>> tasks = new List<Task<string>>();
    int unresponsiveUrlCount = 0;

    foreach (var url in urls)
    {   
        tasks.Add(client.GetStringAsync(url));             
    }

    Task aggregationTask = null;
    try
    {
        aggregationTask = Task.WhenAll(tasks);
        await aggregationTask;
    }
    catch (Exception)
    {  
        if (aggregationTask?.Exception?.InnerExceptions != null && aggregationTask.Exception.InnerExceptions.Any())
        {
            foreach (var innerEx in aggregationTask.Exception.InnerExceptions)
            {
                unresponsiveUrlCount++;
            }
        }      
    }

    return unresponsiveUrlCount < urls.Count;
}

该方法检查列表中的所有url，如果它们都不可访问，则返回false。我已经添加了苹果的url，因为在我的情况下，它加载相当快，但它可以替换为任何url。

public static bool HasConnection()
{
    try
    {
        System.Net.IPHostEntry i = System.Net.Dns.GetHostEntry("www.google.com");
        return true;
    }
    catch
    {
        return false;
    }
}

工作

ping google.com会引入一个DNS解析依赖。ping 8.8.8.8很好，但谷歌离我很远。我所需要做的就是在互联网上ping离我最近的东西。

我可以使用Ping的TTL功能来Ping跳#1，然后跳#2，等等，直到我从一个可路由地址上的某个东西得到回复;如果该节点在一个可路由地址上，那么它就在因特网上。对于我们大多数人来说，跳点1将是我们的本地网关/路由器，跳点2将是光纤连接或其他设备的另一侧的第一个点。

这段代码对我有用，比这个线程中的其他一些建议反应更快，因为它是在互联网上ping离我最近的任何东西。

using System.Diagnostics;
using System.Net;
using System.Net.NetworkInformation;
using System.Net.Sockets;
using System.Threading.Tasks;
    
public static async Task<bool> IsConnectedToInternetAsync()
{
    const int maxHops = 30;
    const string someFarAwayIpAddress = "8.8.8.8";
    
    // Keep pinging further along the line from here to google 
    // until we find a response that is from a routable address
    for (int ttl = 1; ttl <= maxHops; ttl++)
    {
        var options = new PingOptions(ttl, true);
        byte[] buffer = new byte[32];
        PingReply reply;
        try
        {
            using (var pinger = new Ping())
            {
                reply = await pinger.SendPingAsync(someFarAwayIpAddress, 10000, buffer, options);
            }
        }
        catch (PingException pingex)
        {
            Debug.Print($"Ping exception (probably due to no network connection or recent change in network conditions), hence not connected to internet. Message: {pingex.Message}");
            return false;
        }
    
        string address = reply.Address?.ToString() ?? null;
        Debug.Print($"Hop #{ttl} is {address}, {reply.Status}");
    
        if (reply.Status != IPStatus.TtlExpired && reply.Status != IPStatus.Success)
        {
            Debug.Print($"Hop #{ttl} is {reply.Status}, hence we are not connected.");
            return false;
        }
    
        if (IsRoutableAddress(reply.Address))
        {
            Debug.Print("That's routable, so we must be connected to the internet.");
            return true;
        }
    }
    
    return false;
}
    
private static bool IsRoutableAddress(IPAddress addr)
{
    if (addr == null)
    {
        return false;
    }
    else if (addr.AddressFamily == AddressFamily.InterNetworkV6)
    {
        return !addr.IsIPv6LinkLocal && !addr.IsIPv6SiteLocal;
    }
    else // IPv4
    {
        byte[] bytes = addr.GetAddressBytes();
        if (bytes[0] == 10)
        {   // Class A network
            return false;
        }
        else if (bytes[0] == 172 && bytes[1] >= 16 && bytes[1] <= 31)
        {   // Class B network
            return false;
        }
        else if (bytes[0] == 192 && bytes[1] == 168)
        {   // Class C network
            return false;
        }
        else
        {   // None of the above, so must be routable
            return true;
        }
    }
}