我有一个std::string类型的变量。我想检查它是否包含一个特定的std::字符串。我该怎么做呢?
是否有一个函数,如果找到字符串返回true,如果没有找到则返回false ?
我有一个std::string类型的变量。我想检查它是否包含一个特定的std::字符串。我该怎么做呢?
是否有一个函数,如果找到字符串返回true,如果没有找到则返回false ?
当前回答
还可以使用System命名空间。 然后可以使用contains方法。
#include <iostream>
using namespace System;
int main(){
String ^ wholeString = "My name is Malindu";
if(wholeString->ToLower()->Contains("malindu")){
std::cout<<"Found";
}
else{
std::cout<<"Not Found";
}
}
其他回答
如果不想使用标准库函数,下面是一种解决方案。
#include <iostream>
#include <string>
bool CheckSubstring(std::string firstString, std::string secondString){
if(secondString.size() > firstString.size())
return false;
for (int i = 0; i < firstString.size(); i++){
int j = 0;
// If the first characters match
if(firstString[i] == secondString[j]){
int k = i;
while (firstString[i] == secondString[j] && j < secondString.size()){
j++;
i++;
}
if (j == secondString.size())
return true;
else // Re-initialize i to its original value
i = k;
}
}
return false;
}
int main(){
std::string firstString, secondString;
std::cout << "Enter first string:";
std::getline(std::cin, firstString);
std::cout << "Enter second string:";
std::getline(std::cin, secondString);
if(CheckSubstring(firstString, secondString))
std::cout << "Second string is a substring of the frist string.\n";
else
std::cout << "Second string is not a substring of the first string.\n";
return 0;
}
从c++ 23开始,你可以使用std::string::contains
#include <string>
const auto haystack = std::string("haystack with needles");
const auto needle = std::string("needle");
if (haystack.contains(needle))
{
// found!
}
使用std::string::find如下所示:
if (s1.find(s2) != std::string::npos) {
std::cout << "found!" << '\n';
}
注意:如果s2是s1的子字符串,则打印"found!", s1和s2都是std::string类型。
我们可以用这个方法代替。 这是我项目中的一个例子。 参考代码。 一些额外的费用也包括在内。
看看if语句!
/*
Every C++ program should have an entry point. Usually, this is the main function.
Every C++ Statement ends with a ';' (semi-colon)
But, pre-processor statements do not have ';'s at end.
Also, every console program can be ended using "cin.get();" statement, so that the console won't exit instantly.
*/
#include <string>
#include <bits/stdc++.h> //Can Use instead of iostream. Also should be included to use the transform function.
using namespace std;
int main(){ //The main function. This runs first in every program.
string input;
while(input!="exit"){
cin>>input;
transform(input.begin(),input.end(),input.begin(),::tolower); //Converts to lowercase.
if(input.find("name") != std::string::npos){ //Gets a boolean value regarding the availability of the said text.
cout<<"My Name is AI \n";
}
if(input.find("age") != std::string::npos){
cout<<"My Age is 2 minutes \n";
}
}
}
你可以尝试使用find函数:
string str ("There are two needles in this haystack.");
string str2 ("needle");
if (str.find(str2) != string::npos) {
//.. found.
}