如果字符串的大小相对较大(数百字节或更多)，并且c++17可用，您可能需要使用Boyer-Moore-Horspool搜索器(示例来自cppreference.com):

#include <iostream>
#include <string>
#include <algorithm>
#include <functional>

int main()
{
    std::string in = "Lorem ipsum dolor sit amet, consectetur adipiscing elit,"
                     " sed do eiusmod tempor incididunt ut labore et dolore magna aliqua";
    std::string needle = "pisci";
    auto it = std::search(in.begin(), in.end(),
                   std::boyer_moore_searcher(
                       needle.begin(), needle.end()));
    if(it != in.end())
        std::cout << "The string " << needle << " found at offset "
                  << it - in.begin() << '\n';
    else
        std::cout << "The string " << needle << " not found\n";
}

#include <algorithm>        // std::search
#include <string>
using std::search; using std::count; using std::string;

int main() {
    string mystring = "The needle in the haystack";
    string str = "needle";
    string::const_iterator it;
    it = search(mystring.begin(), mystring.end(), 
                str.begin(), str.end()) != mystring.end();

    // if string is found... returns iterator to str's first element in mystring
    // if string is not found... returns iterator to mystring.end()

if (it != mystring.end())
    // string is found
else
    // not found

return 0;
}

如果不想使用标准库函数，下面是一种解决方案。

#include <iostream>
#include <string>

bool CheckSubstring(std::string firstString, std::string secondString){
    if(secondString.size() > firstString.size())
        return false;

    for (int i = 0; i < firstString.size(); i++){
        int j = 0;
        // If the first characters match
        if(firstString[i] == secondString[j]){
            int k = i;
            while (firstString[i] == secondString[j] && j < secondString.size()){
                j++;
                i++;
            }
            if (j == secondString.size())
                return true;
            else // Re-initialize i to its original value
                i = k;
        }
    }
    return false;
}

int main(){
    std::string firstString, secondString;

    std::cout << "Enter first string:";
    std::getline(std::cin, firstString);

    std::cout << "Enter second string:";
    std::getline(std::cin, secondString);

    if(CheckSubstring(firstString, secondString))
        std::cout << "Second string is a substring of the frist string.\n";
    else
        std::cout << "Second string is not a substring of the first string.\n";

    return 0;
}

我们可以用这个方法代替。 这是我项目中的一个例子。 参考代码。 一些额外的费用也包括在内。

看看if语句!

/*
Every C++ program should have an entry point. Usually, this is the main function.
Every C++ Statement ends with a ';' (semi-colon)
But, pre-processor statements do not have ';'s at end.
Also, every console program can be ended using "cin.get();" statement, so that the console won't exit instantly.
*/

#include <string>
#include <bits/stdc++.h> //Can Use instead of iostream. Also should be included to use the transform function.

using namespace std;
int main(){ //The main function. This runs first in every program.

    string input;

    while(input!="exit"){
        cin>>input;
        transform(input.begin(),input.end(),input.begin(),::tolower); //Converts to lowercase.

        if(input.find("name") != std::string::npos){ //Gets a boolean value regarding the availability of the said text.
            cout<<"My Name is AI \n";
        }

        if(input.find("age") != std::string::npos){
            cout<<"My Age is 2 minutes \n";
        }
    }

}

实际上，你可以尝试使用boost库，我认为std::string没有提供足够的方法来做所有常见的字符串操作。在boost中，你可以只使用boost::algorithm::包含:

#include <string>
#include <boost/algorithm/string.hpp>

int main() {
    std::string s("gengjiawen");
    std::string t("geng");
    bool b = boost::algorithm::contains(s, t);
    std::cout << b << std::endl;
    return 0;
}

是什么

string response = "hello world";
string findMe = "world";

if(response.find(findMe) != string::npos)
{
     //found
}