实际上，你可以尝试使用boost库，我认为std::string没有提供足够的方法来做所有常见的字符串操作。在boost中，你可以只使用boost::algorithm::包含:

#include <string>
#include <boost/algorithm/string.hpp>

int main() {
    std::string s("gengjiawen");
    std::string t("geng");
    bool b = boost::algorithm::contains(s, t);
    std::cout << b << std::endl;
    return 0;
}

这是一个简单的函数

bool find(string line, string sWord)
{
    bool flag = false;
    int index = 0, i, helper = 0;
    for (i = 0; i < line.size(); i++)
    {
        if (sWord.at(index) == line.at(i))
        {
            if (flag == false)
            {
                flag = true;
                helper = i;
            }
            index++;
        }
        else
        {
            flag = false;
            index = 0;
        }
        if (index == sWord.size())
        {
            break;
        }
    }
    if ((i+1-helper) == index)
    {
        return true;
    }
    return false;
}

如果字符串的大小相对较大(数百字节或更多)，并且c++17可用，您可能需要使用Boyer-Moore-Horspool搜索器(示例来自cppreference.com):

#include <iostream>
#include <string>
#include <algorithm>
#include <functional>

int main()
{
    std::string in = "Lorem ipsum dolor sit amet, consectetur adipiscing elit,"
                     " sed do eiusmod tempor incididunt ut labore et dolore magna aliqua";
    std::string needle = "pisci";
    auto it = std::search(in.begin(), in.end(),
                   std::boyer_moore_searcher(
                       needle.begin(), needle.end()));
    if(it != in.end())
        std::cout << "The string " << needle << " found at offset "
                  << it - in.begin() << '\n';
    else
        std::cout << "The string " << needle << " not found\n";
}

使用std::regex_search也不错。让搜索更通用的垫脚石。下面是一个带有注释的例子。

//THE STRING IN WHICH THE SUBSTRING TO BE FOUND.
std::string testString = "Find Something In This Test String";

//THE SUBSTRING TO BE FOUND.
auto pattern{ "In This Test" };

//std::regex_constants::icase - TO IGNORE CASE.
auto rx = std::regex{ pattern,std::regex_constants::icase };

//SEARCH THE STRING.
bool isStrExists = std::regex_search(testString, rx);

需要包含#include <regex>

出于某种原因，假设输入字符串被观察到类似于“在这个示例字符串中查找一些东西”，并且有兴趣搜索“在这个测试中”或“在这个示例中”，那么可以通过简单地调整如下所示的模式来增强搜索。

//THE SUBSTRING TO BE FOUND.
auto pattern{ "In This (Test|Example)" };

如果不想使用标准库函数，下面是一种解决方案。

#include <iostream>
#include <string>

bool CheckSubstring(std::string firstString, std::string secondString){
    if(secondString.size() > firstString.size())
        return false;

    for (int i = 0; i < firstString.size(); i++){
        int j = 0;
        // If the first characters match
        if(firstString[i] == secondString[j]){
            int k = i;
            while (firstString[i] == secondString[j] && j < secondString.size()){
                j++;
                i++;
            }
            if (j == secondString.size())
                return true;
            else // Re-initialize i to its original value
                i = k;
        }
    }
    return false;
}

int main(){
    std::string firstString, secondString;

    std::cout << "Enter first string:";
    std::getline(std::cin, firstString);

    std::cout << "Enter second string:";
    std::getline(std::cin, secondString);

    if(CheckSubstring(firstString, secondString))
        std::cout << "Second string is a substring of the frist string.\n";
    else
        std::cout << "Second string is not a substring of the first string.\n";

    return 0;
}

你可以试试这个

string s1 = "Hello";
string s2 = "el";
if(strstr(s1.c_str(),s2.c_str()))
{
   cout << " S1 Contains S2";
}