您还可以查看DataContractJsonSerializer

另一个本地解决方案是JavaScriptSerializer，它不需要任何第三方库，只需要对System.Web.Extensions的引用。这不是一个新功能，而是一个自3.5以来非常不为人知的内置功能。

using System.Web.Script.Serialization;

..

JavaScriptSerializer serializer = new JavaScriptSerializer();
objectString = serializer.Serialize(new MyObject());

和背部

MyObject o = serializer.Deserialize<MyObject>(objectString)

System.Text.Json

. net core 3.0内置了System.Text.Json，这意味着你可以在不使用第三方库的情况下反序列化/序列化JSON。

Serialize / Deserialize

序列化你的类到JSON字符串:

var json = JsonSerializer.Serialize(model);

将JSON反序列化为强类型类:

var model = JsonSerializer.Deserialize<Model>(json);

解析(。6)净

. net 6引入了System.Text.Json.Nodes命名空间，使DOM能够以类似于Newtonsoft的方式进行解析、导航和操作。Json使用新的类JsonObject, JsonArray, JsonValue和JsonNode。

// JsonObject parse DOM
var jsonObject = JsonNode.Parse(jsonString).AsObject();
// read data from DOM
string name = jsonObject["Name"].ToString();
DateTime date = (DateTime)jsonObject["Date"];
var people = jsonObject["People"].Deserialize<List<Person>>();

类似的方法也适用于JsonArray。这个答案提供了关于JsonObject的更多细节。

需要注意的一点是，System.Text.Json在使用自己的代码时不会自动处理camelCase JSON属性(然而，当使用MVC/WebAPI请求和模型绑定器时，它会自动处理)。

要解决这个问题，你需要传递JsonSerializerOptions作为参数。

JsonSerializerOptions options = new JsonSerializerOptions
{        
    PropertyNamingPolicy = JsonNamingPolicy.CamelCase,  // set camelCase       
    WriteIndented = true                                // write pretty json
};

// pass options to serializer
var json = JsonSerializer.Serialize(order, options);
// pass options to deserializer
var order = JsonSerializer.Deserialize<Order>(json, options);

System.Text.Json也可用于.Net Framework和.Net Standard，作为一个nuget包System.Text.Json

Edit

在。net 6中，JsonNode.Parse()提供了解析“未知”json的功能

 using (var ms = new MemoryStream(Encoding.Unicode.GetBytes(user)))
 {
    // Deserialization from JSON  
    DataContractJsonSerializer deserializer = new DataContractJsonSerializer(typeof(UserListing))
    DataContractJsonSerializer(typeof(UserListing));
    UserListing response = (UserListing)deserializer.ReadObject(ms);

 }

 public class UserListing
 {
    public List<UserList> users { get; set; }      
 }

 public class UserList
 {
    public string FirstName { get; set; }       
    public string LastName { get; set; } 
 }

下面是一个使用csc v2.0.0.61501的完整的可运行示例。

包:

nuget install Microsoft.AspNet.WebApi.Core
nuget install Microsoft.Net.Http
nuget install Newtonsoft.Json

代码:

using Newtonsoft.Json;
using System;
using System.Net.Http;
using System.Threading.Tasks;

public static class App
{
    static void Main()
    {
        MainAsync().GetAwaiter().GetResult();
    }

    static async Task MainAsync()
    {
        string url = "https://httpbin.org/get";
        var client = new HttpClient();

        // The verbose way:
        //HttpResponseMessage response = await client.GetAsync(url);
        //response.EnsureSuccessStatusCode();
        //string responseBody = await response.Content.ReadAsStringAsync();

        // Or:
        string responseBody = await client.GetStringAsync(url);

        var obj = JsonConvert.DeserializeObject<dynamic>(responseBody);
        Console.WriteLine(obj);
        Console.WriteLine(obj.headers.Host);
    }
}

编译器命令:

 csc http_request2.cs -r:".\Microsoft.AspNet.WebApi.Core.5.2.9\lib\net45\System.Web.Http.dll" -r:".\Microsoft.Net.Http.2.2.29\lib\net40\System.Net.Http.dll" -r:".\Newtonsoft.Json.13.0.1\lib\net45\Newtonsoft.Json.dll"

输出:

{
  "args": {},
  "headers": {
    "Host": "httpbin.org",
    "X-Amzn-Trace-Id": "Root=1-633dce52-64f923bb42c99bf46f78672c"
  },
  "origin": "98.51.7.199",
  "url": "https://httpbin.org/get"
}
httpbin.org

无法加载Newtonsoft.json文件或程序集。系统无法找到指定的文件，我不得不将Newtonsoft.Json.dll移到已编译的二进制文件旁边。

系统。Json现在工作了…

安装 nuget https://www.nuget.org/packages/System.Json

PM> Install-Package System.Json -Version 4.5.0

示例:

// PM>Install-Package System.Json -Version 4.5.0

using System;
using System.Json;

namespace NetCoreTestConsoleApp
{
    class Program
    {
        static void Main(string[] args)
        {
            // Note that JSON keys are case sensitive, a is not same as A.

            // JSON Sample
            string jsonString = "{\"a\": 1,\"b\": \"string value\",\"c\":[{\"Value\": 1}, {\"Value\": 2,\"SubObject\":[{\"SubValue\":3}]}]}";

            // You can use the following line in a beautifier/JSON formatted for better view
            // {"a": 1,"b": "string value","c":[{"Value": 1}, {"Value": 2,"SubObject":[{"SubValue":3}]}]}

            /* Formatted jsonString for viewing purposes:
            {
               "a":1,
               "b":"string value",
               "c":[
                  {
                     "Value":1
                  },
                  {
                     "Value":2,
                     "SubObject":[
                        {
                           "SubValue":3
                        }
                     ]
                  }
               ]
            }
            */

            // Verify your JSON if you get any errors here
            JsonValue json = JsonValue.Parse(jsonString);

            // int test
            if (json.ContainsKey("a"))
            {
                int a = json["a"]; // type already set to int
                Console.WriteLine("json[\"a\"]" + " = " + a);
            }

            // string test
            if (json.ContainsKey("b"))
            {
                string b = json["b"];  // type already set to string
                Console.WriteLine("json[\"b\"]" + " = " + b);
            }

            // object array test
            if (json.ContainsKey("c") && json["c"].JsonType == JsonType.Array)
            {
                // foreach loop test
                foreach (JsonValue j in json["c"])
                {
                    Console.WriteLine("j[\"Value\"]" + " = " + j["Value"].ToString());
                }

                // multi level key test
                Console.WriteLine("json[\"c\"][0][\"Value\"]" + " = " + json["c"][0]["Value"].ToString());
                Console.WriteLine("json[\"c\"][0][\"Value\"]" + " = " + json["c"][1]["Value"].ToString());
                Console.WriteLine("json[\"c\"][1][\"SubObject\"][0][\"SubValue\"]" + " = " + json["c"][1]["SubObject"][0]["SubValue"].ToString());
            }

            Console.WriteLine();
            Console.Write("Press any key to exit.");
            Console.ReadKey();
        }
    }
}