我有以下代码:
var user = (Dictionary<string, object>)serializer.DeserializeObject(responsecontent);
responsecontent中的输入是JSON,但它没有正确地反序列化为对象。我应该如何正确地反序列化它?
我有以下代码:
var user = (Dictionary<string, object>)serializer.DeserializeObject(responsecontent);
responsecontent中的输入是JSON,但它没有正确地反序列化为对象。我应该如何正确地反序列化它?
当前回答
下面是一个使用csc v2.0.0.61501的完整的可运行示例。
包:
nuget install Microsoft.AspNet.WebApi.Core
nuget install Microsoft.Net.Http
nuget install Newtonsoft.Json
代码:
using Newtonsoft.Json;
using System;
using System.Net.Http;
using System.Threading.Tasks;
public static class App
{
static void Main()
{
MainAsync().GetAwaiter().GetResult();
}
static async Task MainAsync()
{
string url = "https://httpbin.org/get";
var client = new HttpClient();
// The verbose way:
//HttpResponseMessage response = await client.GetAsync(url);
//response.EnsureSuccessStatusCode();
//string responseBody = await response.Content.ReadAsStringAsync();
// Or:
string responseBody = await client.GetStringAsync(url);
var obj = JsonConvert.DeserializeObject<dynamic>(responseBody);
Console.WriteLine(obj);
Console.WriteLine(obj.headers.Host);
}
}
编译器命令:
csc http_request2.cs -r:".\Microsoft.AspNet.WebApi.Core.5.2.9\lib\net45\System.Web.Http.dll" -r:".\Microsoft.Net.Http.2.2.29\lib\net40\System.Net.Http.dll" -r:".\Newtonsoft.Json.13.0.1\lib\net45\Newtonsoft.Json.dll"
输出:
{
"args": {},
"headers": {
"Host": "httpbin.org",
"X-Amzn-Trace-Id": "Root=1-633dce52-64f923bb42c99bf46f78672c"
},
"origin": "98.51.7.199",
"url": "https://httpbin.org/get"
}
httpbin.org
无法加载Newtonsoft.json文件或程序集。系统无法找到指定的文件,我不得不将Newtonsoft.Json.dll移到已编译的二进制文件旁边。
其他回答
正如这里的回答-反序列化JSON到c#动态对象?
使用Json非常简单。NET:
dynamic stuff = JsonConvert.DeserializeObject("{ 'Name': 'Jon Smith', 'Address': { 'City': 'New York', 'State': 'NY' }, 'Age': 42 }");
string name = stuff.Name;
string address = stuff.Address.City;
或者使用Newtonsoft.Json.Linq:
dynamic stuff = JObject.Parse("{ 'Name': 'Jon Smith', 'Address': { 'City': 'New York', 'State': 'NY' }, 'Age': 42 }");
string name = stuff.Name;
string address = stuff.Address.City;
如果JSON是动态的,如下所示
{
"Items": [{
"Name": "Apple",
"Price": 12.3
},
{
"Name": "Grape",
"Price": 3.21
}
],
"Date": "21/11/2010"
}
然后,一旦你安装了NewtonSoft。Json从NuGet和包括它在你的项目,你可以序列化它为
string jsonString = "{\"Items\": [{\"Name\": \"Apple\",\"Price\": 12.3},{\"Name\": \"Grape\",\"Price\": 3.21}],\"Date\": \"21/11/2010\"}";
dynamic DynamicData = JsonConvert.DeserializeObject(jsonString);
Console.WriteLine( DynamicData.Date); // "21/11/2010"
Console.WriteLine(DynamicData.Items.Count); // 2
Console.WriteLine(DynamicData.Items[0].Name); // "Apple"
来源:如何在c#中读取JSON数据(使用控制台应用程序和ASP的例子)。净MVC) ?
您还可以查看DataContractJsonSerializer
另一个本地解决方案是JavaScriptSerializer,它不需要任何第三方库,只需要对System.Web.Extensions的引用。这不是一个新功能,而是一个自3.5以来非常不为人知的内置功能。
using System.Web.Script.Serialization;
..
JavaScriptSerializer serializer = new JavaScriptSerializer();
objectString = serializer.Serialize(new MyObject());
和背部
MyObject o = serializer.Deserialize<MyObject>(objectString)
using (var ms = new MemoryStream(Encoding.Unicode.GetBytes(user)))
{
// Deserialization from JSON
DataContractJsonSerializer deserializer = new DataContractJsonSerializer(typeof(UserListing))
DataContractJsonSerializer(typeof(UserListing));
UserListing response = (UserListing)deserializer.ReadObject(ms);
}
public class UserListing
{
public List<UserList> users { get; set; }
}
public class UserList
{
public string FirstName { get; set; }
public string LastName { get; set; }
}