我有以下代码:

var user = (Dictionary<string, object>)serializer.DeserializeObject(responsecontent);

responsecontent中的输入是JSON,但它没有正确地反序列化为对象。我应该如何正确地反序列化它?


当前回答

正如这里的回答-反序列化JSON到c#动态对象?

使用Json非常简单。NET:

dynamic stuff = JsonConvert.DeserializeObject("{ 'Name': 'Jon Smith', 'Address': { 'City': 'New York', 'State': 'NY' }, 'Age': 42 }");

string name = stuff.Name;
string address = stuff.Address.City;

或者使用Newtonsoft.Json.Linq:

dynamic stuff = JObject.Parse("{ 'Name': 'Jon Smith', 'Address': { 'City': 'New York', 'State': 'NY' }, 'Age': 42 }");

string name = stuff.Name;
string address = stuff.Address.City;

其他回答

         string json = @"{
            'Name': 'Wide Web',
            'Url': 'www.wideweb.com.br'}";

        JavaScriptSerializer jsonSerializer = new JavaScriptSerializer();
        dynamic j = jsonSerializer.Deserialize<dynamic>(json);
        string name = j["Name"].ToString();
        string url = j["Url"].ToString();

下面是一个使用csc v2.0.0.61501的完整的可运行示例。

包:

nuget install Microsoft.AspNet.WebApi.Core
nuget install Microsoft.Net.Http
nuget install Newtonsoft.Json

代码:

using Newtonsoft.Json;
using System;
using System.Net.Http;
using System.Threading.Tasks;

public static class App
{
    static void Main()
    {
        MainAsync().GetAwaiter().GetResult();
    }

    static async Task MainAsync()
    {
        string url = "https://httpbin.org/get";
        var client = new HttpClient();

        // The verbose way:
        //HttpResponseMessage response = await client.GetAsync(url);
        //response.EnsureSuccessStatusCode();
        //string responseBody = await response.Content.ReadAsStringAsync();

        // Or:
        string responseBody = await client.GetStringAsync(url);

        var obj = JsonConvert.DeserializeObject<dynamic>(responseBody);
        Console.WriteLine(obj);
        Console.WriteLine(obj.headers.Host);
    }
}

编译器命令:

 csc http_request2.cs -r:".\Microsoft.AspNet.WebApi.Core.5.2.9\lib\net45\System.Web.Http.dll" -r:".\Microsoft.Net.Http.2.2.29\lib\net40\System.Net.Http.dll" -r:".\Newtonsoft.Json.13.0.1\lib\net45\Newtonsoft.Json.dll"

输出:

{
  "args": {},
  "headers": {
    "Host": "httpbin.org",
    "X-Amzn-Trace-Id": "Root=1-633dce52-64f923bb42c99bf46f78672c"
  },
  "origin": "98.51.7.199",
  "url": "https://httpbin.org/get"
}
httpbin.org

无法加载Newtonsoft.json文件或程序集。系统无法找到指定的文件,我不得不将Newtonsoft.Json.dll移到已编译的二进制文件旁边。

试试下面的代码:

HttpWebRequest request = (HttpWebRequest)WebRequest.Create("URL");
JArray array = new JArray();
using (var twitpicResponse = (HttpWebResponse)request.GetResponse())
using (var reader = new StreamReader(twitpicResponse.GetResponseStream()))
{
    JavaScriptSerializer js = new JavaScriptSerializer();
    var objText = reader.ReadToEnd();

    JObject joResponse = JObject.Parse(objText);
    JObject result = (JObject)joResponse["result"];
    array = (JArray)result["Detail"];
    string statu = array[0]["dlrStat"].ToString();
}

我假设你没有使用Json。净(Newtonsoft。Json NuGet包)。如果是这样的话,你应该试试。

它具有以下特点:

LINQ到JSON JsonSerializer用于快速将.NET对象转换为JSON并再转换回来 Json。NET可以选择生成格式良好、缩进的JSON以供调试或显示 可以将JsonIgnore和JsonProperty等属性添加到类中,以自定义类的序列化方式 能够将JSON转换为XML 支持多种平台:.NET、Silverlight和Compact Framework

请看下面的例子。在本例中,JsonConvert类用于将对象与JSON进行转换。它有两个用于此目的的静态方法。它们是SerializeObject(Object obj)和DeserializeObject<T>(String json):

using Newtonsoft.Json;

Product product = new Product();
product.Name = "Apple";
product.Expiry = new DateTime(2008, 12, 28);
product.Price = 3.99M;
product.Sizes = new string[] { "Small", "Medium", "Large" };

string json = JsonConvert.SerializeObject(product);
//{
//  "Name": "Apple",
//  "Expiry": "2008-12-28T00:00:00",
//  "Price": 3.99,
//  "Sizes": [
//    "Small",
//    "Medium",
//    "Large"
//  ]
//}

Product deserializedProduct = JsonConvert.DeserializeObject<Product>(json);

另一个本地解决方案是JavaScriptSerializer,它不需要任何第三方库,只需要对System.Web.Extensions的引用。这不是一个新功能,而是一个自3.5以来非常不为人知的内置功能。

using System.Web.Script.Serialization;

..

JavaScriptSerializer serializer = new JavaScriptSerializer();
objectString = serializer.Serialize(new MyObject());

和背部

MyObject o = serializer.Deserialize<MyObject>(objectString)