我也遇到了同样的问题，但我想出了一个非常简单的方法:

import subprocess
output = subprocess.getoutput("ls -l")
print(output)

注意:此解决方案是特定于Python3的subprocess.getoutput()在Python2中不起作用

可以将输出重定向到文本文件，然后将其读回来。

import subprocess
import os
import tempfile

def execute_to_file(command):
    """
    This function execute the command
    and pass its output to a tempfile then read it back
    It is usefull for process that deploy child process
    """
    temp_file = tempfile.NamedTemporaryFile(delete=False)
    temp_file.close()
    path = temp_file.name
    command = command + " > " + path
    proc = subprocess.run(command, shell=True, stdout=subprocess.PIPE, stderr=subprocess.PIPE, universal_newlines=True)
    if proc.stderr:
        # if command failed return
        os.unlink(path)
        return
    with open(path, 'r') as f:
        data = f.read()
    os.unlink(path)
    return data

if __name__ == "__main__":
    path = "Somepath"
    command = 'ecls.exe /files ' + path
    print(execute(command))

改进以获得更好的日志记录。 为了获得更好的输出，可以使用迭代器。 从下面开始，我们变得更好

from subprocess import Popen, getstatusoutput, PIPE
def shell_command(cmd):
    result = Popen(cmd, shell=True, stdout=PIPE, stderr=PIPE)

    output = iter(result.stdout.readline, b'')
    error = iter(result.stderr.readline, b'')
    print("##### OutPut ###")
    for line in output:
        print(line.decode("utf-8"))
    print("###### Error ########")
    for line in error:
        print(error.decode("utf-8")) # Convert bytes to str

    status, terminal_output = run_command(cmd)
    print(terminal_output)

shell_command("ls") # this will display all the files & folders in directory

使用getstatusoutput的其他方法(容易理解)

from subprocess import Popen, getstatusoutput, PIPE

status_Code, output = getstausoutput(command)
print(output) # this will give the terminal output

# status_code, output = getstatusoutput("ls") # this will print the all files & folder available in the directory

这里有一个解决方案，如果你想在进程运行或不运行时打印输出。

我还添加了当前工作目录，这对我来说很有用不止一次。

希望这个解决方案能帮助到别人:)。

import subprocess

def run_command(cmd_and_args, print_constantly=False, cwd=None):
"""Runs a system command.

:param cmd_and_args: the command to run with or without a Pipe (|).
:param print_constantly: If True then the output is logged in continuous until the command ended.
:param cwd: the current working directory (the directory from which you will like to execute the command)
:return: - a tuple containing the return code, the stdout and the stderr of the command
"""
output = []

process = subprocess.Popen(cmd_and_args, shell=True, stdout=subprocess.PIPE, stderr=subprocess.PIPE, cwd=cwd)

while True:
    next_line = process.stdout.readline()
    if next_line:
        output.append(str(next_line))
        if print_constantly:
            print(next_line)
    elif not process.poll():
        break

error = process.communicate()[1]

return process.returncode, '\n'.join(output), error

就像这样:

def runProcess(exe):    
    p = subprocess.Popen(exe, stdout=subprocess.PIPE, stderr=subprocess.STDOUT)
    while(True):
        # returns None while subprocess is running
        retcode = p.poll() 
        line = p.stdout.readline()
        yield line
        if retcode is not None:
            break

注意，我将stderr重定向到stdout，这可能不是你想要的，但我也想要错误消息。

这个函数一行一行地输出(通常你必须等待子进程完成才能得到完整的输出)。

对于你的情况，用法是:

for line in runProcess('mysqladmin create test -uroot -pmysqladmin12'.split()):
    print line,

Vartec的答案不读取所有的行，所以我做了一个版本:

def run_command(command):
    p = subprocess.Popen(command,
                         stdout=subprocess.PIPE,
                         stderr=subprocess.STDOUT)
    return iter(p.stdout.readline, b'')

用法与公认的答案相同:

command = 'mysqladmin create test -uroot -pmysqladmin12'.split()
for line in run_command(command):
    print(line)