如果您需要在多个文件上运行shell命令，这对我来说很有用。

import os
import subprocess

# Define a function for running commands and capturing stdout line by line
# (Modified from Vartec's solution because it wasn't printing all lines)
def runProcess(exe):    
    p = subprocess.Popen(exe, stdout=subprocess.PIPE, stderr=subprocess.STDOUT)
    return iter(p.stdout.readline, b'')

# Get all filenames in working directory
for filename in os.listdir('./'):
    # This command will be run on each file
    cmd = 'nm ' + filename

    # Run the command and capture the output line by line.
    for line in runProcess(cmd.split()):
        # Eliminate leading and trailing whitespace
        line.strip()
        # Split the output 
        output = line.split()

        # Filter the output and print relevant lines
        if len(output) > 2:
            if ((output[2] == 'set_program_name')):
                print filename
                print line

编辑:刚刚看到Max Persson的解决方案和J.F. Sebastian的建议。继续把它整合进去。

改进以获得更好的日志记录。 为了获得更好的输出，可以使用迭代器。 从下面开始，我们变得更好

from subprocess import Popen, getstatusoutput, PIPE
def shell_command(cmd):
    result = Popen(cmd, shell=True, stdout=PIPE, stderr=PIPE)

    output = iter(result.stdout.readline, b'')
    error = iter(result.stderr.readline, b'')
    print("##### OutPut ###")
    for line in output:
        print(line.decode("utf-8"))
    print("###### Error ########")
    for line in error:
        print(error.decode("utf-8")) # Convert bytes to str

    status, terminal_output = run_command(cmd)
    print(terminal_output)

shell_command("ls") # this will display all the files & folders in directory

使用getstatusoutput的其他方法(容易理解)

from subprocess import Popen, getstatusoutput, PIPE

status_Code, output = getstausoutput(command)
print(output) # this will give the terminal output

# status_code, output = getstatusoutput("ls") # this will print the all files & folder available in the directory

如果您需要在多个文件上运行shell命令，这对我来说很有用。

import os
import subprocess

# Define a function for running commands and capturing stdout line by line
# (Modified from Vartec's solution because it wasn't printing all lines)
def runProcess(exe):    
    p = subprocess.Popen(exe, stdout=subprocess.PIPE, stderr=subprocess.STDOUT)
    return iter(p.stdout.readline, b'')

# Get all filenames in working directory
for filename in os.listdir('./'):
    # This command will be run on each file
    cmd = 'nm ' + filename

    # Run the command and capture the output line by line.
    for line in runProcess(cmd.split()):
        # Eliminate leading and trailing whitespace
        line.strip()
        # Split the output 
        output = line.split()

        # Filter the output and print relevant lines
        if len(output) > 2:
            if ((output[2] == 'set_program_name')):
                print filename
                print line

编辑:刚刚看到Max Persson的解决方案和J.F. Sebastian的建议。继续把它整合进去。

在Python 3.7+中，使用subprocess.run并传递capture_output=True:

import subprocess
result = subprocess.run(['echo', 'hello', 'world'], capture_output=True)
print(repr(result.stdout))

这将返回字节:

b'hello world\n'

如果你想把字节转换成字符串，添加text=True:

result = subprocess.run(['echo', 'hello', 'world'], capture_output=True, text=True)
print(repr(result.stdout))

这将读取字节使用您的默认编码:

'hello world\n'

如果你需要手动指定不同的编码，使用encoding="your encoding"而不是text=True:

result = subprocess.run(['echo', 'hello', 'world'], capture_output=True, encoding="utf8")
print(repr(result.stdout))

对于相同的问题，我有一个稍微不同的需求:

捕获并返回STDOUT消息，因为它们在STDOUT缓冲区中累积(即实时)。 @vartec用python方法解决了这个问题，他使用生成器和“yield” 上面的字 打印所有STDOUT行(即使进程在STDOUT缓冲区可以完全读取之前退出) 不要浪费CPU周期以高频轮询进程 检查子流程的返回代码 如果得到非零错误返回码，则打印STDERR(与STDOUT分开)。

我综合了之前的答案，得出了以下结论:

import subprocess
from time import sleep

def run_command(command):
    p = subprocess.Popen(command,
                         stdout=subprocess.PIPE,
                         stderr=subprocess.PIPE,
                         shell=True)
    # Read stdout from subprocess until the buffer is empty !
    for line in iter(p.stdout.readline, b''):
        if line: # Don't print blank lines
            yield line
    # This ensures the process has completed, AND sets the 'returncode' attr
    while p.poll() is None:                                                                                                                                        
        sleep(.1) #Don't waste CPU-cycles
    # Empty STDERR buffer
    err = p.stderr.read()
    if p.returncode != 0:
       # The run_command() function is responsible for logging STDERR 
       print("Error: " + str(err))

这段代码的执行方式与前面的答案相同:

for line in run_command(cmd):
    print(line)

我想建议你考虑一下simppl。它是一个可以通过pypi: pip install simppl获得的模块，运行在python3上。

Simppl允许用户运行shell命令并从屏幕上读取输出。

开发人员建议使用三种类型的用例:

最简单的用法是这样的: 从simppl。simple_pipeline导入simepipeline sp = SimplePipeline(start=0, end=100): sp.print_and_run(“< YOUR_FIRST_OS_COMMAND >”) sp.print_and_run(“< YOUR_SECOND_OS_COMMAND >”)' ' '

要同时运行多个命令，请使用: commands = ['<YOUR_FIRST_OS_COMMAND>'， '<YOUR_SECOND_OS_COMMAND>'] Max_number_of_processes = 4 max_number_of_processes sp.run_parallel(命令)' ' '

最后，如果你的项目使用cli模块，你可以直接运行另一个command_line_tool作为管道的一部分。另一个工具会 从相同的进程中运行，但它将从日志中显示为 管道中的另一个命令。这使得调试和 重构调用其他工具的工具。 从example_module导入example_tool Sp.print_and_run_clt (example_tool.run， ['first_number'， 'second_nmber']， {'-key1': 'val1'， '-key2': 'val2'}， {“——国旗”})' ' '

请注意，打印到STDOUT/STDERR是通过python的日志模块。

下面是simppl工作原理的完整代码:

import logging
from logging.config import dictConfig

logging_config = dict(
    version = 1,
    formatters = {
        'f': {'format':
              '%(asctime)s %(name)-12s %(levelname)-8s %(message)s'}
        },
    handlers = {
        'h': {'class': 'logging.StreamHandler',
              'formatter': 'f',
              'level': logging.DEBUG}
        },
    root = {
        'handlers': ['h'],
        'level': logging.DEBUG,
        },
)
dictConfig(logging_config)

from simppl.simple_pipeline import SimplePipeline
sp = SimplePipeline(0, 100)
sp.print_and_run('ls')