我正在寻找一种更好的模式,用于处理每个元素的列表,然后根据结果从列表中删除。
你不能在foreach (var element in X)中使用.Remove(element)(因为它会导致Collection被修改;枚举操作可能无法执行。例外)……你也不能使用for (int I = 0;i < elements.Count();i++)和. removeat (i),因为它破坏了你在集合中相对于i的当前位置。
有没有一种优雅的方式来做到这一点?
我正在寻找一种更好的模式,用于处理每个元素的列表,然后根据结果从列表中删除。
你不能在foreach (var element in X)中使用.Remove(element)(因为它会导致Collection被修改;枚举操作可能无法执行。例外)……你也不能使用for (int I = 0;i < elements.Count();i++)和. removeat (i),因为它破坏了你在集合中相对于i的当前位置。
有没有一种优雅的方式来做到这一点?
当前回答
Using Remove or RemoveAt on a list while iterating over that list has intentionally been made difficult, because it is almost always the wrong thing to do. You might be able to get it working with some clever trick, but it would be extremely slow. Every time you call Remove it has to scan through the entire list to find the element you want to remove. Every time you call RemoveAt it has to move subsequent elements 1 position to the left. As such, any solution using Remove or RemoveAt, would require quadratic time, O(n²).
如果可以,使用RemoveAll。否则,下面的模式将在线性时间O(n)内就地过滤列表。
// Create a list to be filtered
IList<int> elements = new List<int>(new int[] {1, 2, 3, 4, 5, 6, 7, 8, 9, 10});
// Filter the list
int kept = 0;
for (int i = 0; i < elements.Count; i++) {
// Test whether this is an element that we want to keep.
if (elements[i] % 3 > 0) {
// Add it to the list of kept elements.
elements[kept] = elements[i];
kept++;
}
}
// Unfortunately IList has no Resize method. So instead we
// remove the last element of the list until: elements.Count == kept.
while (kept < elements.Count) elements.RemoveAt(elements.Count-1);
其他回答
你不能使用foreach,但是当你删除一个项目时,你可以向前迭代并管理你的循环索引变量,如下所示:
for (int i = 0; i < elements.Count; i++)
{
if (<condition>)
{
// Decrement the loop counter to iterate this index again, since later elements will get moved down during the remove operation.
elements.RemoveAt(i--);
}
}
注意,一般来说,所有这些技术都依赖于被迭代的集合的行为。这里显示的技术将与标准List(T)一起工作。(很有可能编写自己的集合类和迭代器,允许在foreach循环期间删除项。)
List<T> TheList = new List<T>();
TheList.FindAll(element => element.Satisfies(Condition)).ForEach(element => TheList.Remove(element));
使用属性跟踪要删除的元素,并在处理后将它们全部删除。
using System.Linq;
List<MyProperty> _Group = new List<MyProperty>();
// ... add elements
bool cond = false;
foreach (MyProperty currObj in _Group)
{
// here it is supposed that you decide the "remove conditions"...
cond = true; // set true or false...
if (cond)
{
// SET - element can be deleted
currObj.REMOVE_ME = true;
}
}
// RESET
_Group.RemoveAll(r => r.REMOVE_ME);
我将从一个过滤掉您不想保留的元素的LINQ查询中重新分配列表。
list = list.Where(item => ...).ToList();
除非列表非常大,否则这样做应该不会有明显的性能问题。
我会这样做
using System.IO;
using System;
using System.Collections.Generic;
class Author
{
public string Firstname;
public string Lastname;
public int no;
}
class Program
{
private static bool isEven(int i)
{
return ((i % 2) == 0);
}
static void Main()
{
var authorsList = new List<Author>()
{
new Author{ Firstname = "Bob", Lastname = "Smith", no = 2 },
new Author{ Firstname = "Fred", Lastname = "Jones", no = 3 },
new Author{ Firstname = "Brian", Lastname = "Brains", no = 4 },
new Author{ Firstname = "Billy", Lastname = "TheKid", no = 1 }
};
authorsList.RemoveAll(item => isEven(item.no));
foreach(var auth in authorsList)
{
Console.WriteLine(auth.Firstname + " " + auth.Lastname);
}
}
}
输出
Fred Jones
Billy TheKid