我翻遍了苹果的iBook,找不到任何关于它的定义:
有人能解释一下dispatch_after的结构吗?
dispatch_after(<#when: dispatch_time_t#>, <#queue: dispatch_queue_t?#>, <#block: dispatch_block_t?#>)
我翻遍了苹果的iBook,找不到任何关于它的定义:
有人能解释一下dispatch_after的结构吗?
dispatch_after(<#when: dispatch_time_t#>, <#queue: dispatch_queue_t?#>, <#block: dispatch_block_t?#>)
当前回答
另一个帮手来延迟你的代码,这是100%的Swift使用,并可选地允许选择一个不同的线程来运行你的延迟代码:
public func delay(bySeconds seconds: Double, dispatchLevel: DispatchLevel = .main, closure: @escaping () -> Void) {
let dispatchTime = DispatchTime.now() + seconds
dispatchLevel.dispatchQueue.asyncAfter(deadline: dispatchTime, execute: closure)
}
public enum DispatchLevel {
case main, userInteractive, userInitiated, utility, background
var dispatchQueue: DispatchQueue {
switch self {
case .main: return DispatchQueue.main
case .userInteractive: return DispatchQueue.global(qos: .userInteractive)
case .userInitiated: return DispatchQueue.global(qos: .userInitiated)
case .utility: return DispatchQueue.global(qos: .utility)
case .background: return DispatchQueue.global(qos: .background)
}
}
}
现在你只需在主线程上延迟你的代码,就像这样:
delay(bySeconds: 1.5) {
// delayed code
}
如果你想延迟你的代码到不同的线程:
delay(bySeconds: 1.5, dispatchLevel: .background) {
// delayed code that will run on background thread
}
如果你喜欢一个框架,也有一些更方便的功能,然后签出handysswift。你可以通过Carthage将它添加到你的项目中,然后像上面的例子一样使用它,例如:
import HandySwift
delay(bySeconds: 1.5) {
// delayed code
}
其他回答
Matt的语法非常好,如果你需要使块失效,你可能想使用这个:
typealias dispatch_cancelable_closure = (cancel : Bool) -> Void
func delay(time:NSTimeInterval, closure:()->Void) -> dispatch_cancelable_closure? {
func dispatch_later(clsr:()->Void) {
dispatch_after(
dispatch_time(
DISPATCH_TIME_NOW,
Int64(time * Double(NSEC_PER_SEC))
),
dispatch_get_main_queue(), clsr)
}
var closure:dispatch_block_t? = closure
var cancelableClosure:dispatch_cancelable_closure?
let delayedClosure:dispatch_cancelable_closure = { cancel in
if closure != nil {
if (cancel == false) {
dispatch_async(dispatch_get_main_queue(), closure!);
}
}
closure = nil
cancelableClosure = nil
}
cancelableClosure = delayedClosure
dispatch_later {
if let delayedClosure = cancelableClosure {
delayedClosure(cancel: false)
}
}
return cancelableClosure;
}
func cancel_delay(closure:dispatch_cancelable_closure?) {
if closure != nil {
closure!(cancel: true)
}
}
使用方法如下
let retVal = delay(2.0) {
println("Later")
}
delay(1.0) {
cancel_delay(retVal)
}
学分
上面的链接似乎坏了。来自Github的原始Objc代码
dispatch_after(dispatch_time(DISPATCH_TIME_NOW, (int64_t)(10 * NSEC_PER_SEC)), dispatch_get_main_queue(), ^{
// ...
});
dispatch_after(_:_:_:)函数有三个参数:
延迟 调度队列 块或闭包
dispatch_after(_:_:_:)函数调用在给定延迟后传递给函数的调度队列上的块或闭包。注意,延迟是使用dispatch_time(_:_:)函数创建的。记住这一点,因为我们在Swift中也使用了这个函数。
我建议你通过Raywenderlich调度教程
我经常使用dispatch_after,所以我写了一个顶级实用函数来简化语法:
func delay(delay:Double, closure:()->()) {
dispatch_after(
dispatch_time(
DISPATCH_TIME_NOW,
Int64(delay * Double(NSEC_PER_SEC))
),
dispatch_get_main_queue(), closure)
}
现在你可以这样说:
delay(0.4) {
// do stuff
}
哇,一种你可以改进的语言。还有什么比这更好的呢?
更新Swift 3, Xcode 8种子6
看起来几乎不值得费心,现在他们已经改进了调用语法:
func delay(_ delay:Double, closure:@escaping ()->()) {
let when = DispatchTime.now() + delay
DispatchQueue.main.asyncAfter(deadline: when, execute: closure)
}
在Swift 5中,在下面使用:
DispatchQueue.main.asyncAfter(deadline: .now() + 0.2, execute: closure)
// time gap, specify unit is second
DispatchQueue.main.asyncAfter(deadline: .now() + .seconds(2)) {
Singleton.shared().printDate()
}
// default time gap is second, you can reduce it
DispatchQueue.main.asyncAfter(deadline: .now() + 0.2) {
// just do it!
}
斯威夫特 3+
这在Swift 3+中是超级简单和优雅的:
DispatchQueue.main.asyncAfter(deadline: .now() + 4.5) {
// ...
}
年长的回答:
为了扩展Cezary的答案,它将在1纳秒后执行,我必须执行以下操作以在4秒半后执行。
let delay = 4.5 * Double(NSEC_PER_SEC)
let time = dispatch_time(DISPATCH_TIME_NOW, Int64(delay))
dispatch_after(time, dispatch_get_main_queue(), block)
编辑:我发现我原来的代码有一点错误。如果不将NSEC_PER_SEC转换为Double类型,隐式类型将导致编译错误。
如果有人能提出一个更优的解决方案,我很乐意听听。