我翻遍了苹果的iBook,找不到任何关于它的定义:
有人能解释一下dispatch_after的结构吗?
dispatch_after(<#when: dispatch_time_t#>, <#queue: dispatch_queue_t?#>, <#block: dispatch_block_t?#>)
我翻遍了苹果的iBook,找不到任何关于它的定义:
有人能解释一下dispatch_after的结构吗?
dispatch_after(<#when: dispatch_time_t#>, <#queue: dispatch_queue_t?#>, <#block: dispatch_block_t?#>)
当前回答
Swift 4有一个很短的方法来做到这一点:
Timer.scheduledTimer(withTimeInterval: 2, repeats: false) { (timer) in
// Your stuff here
print("hello")
}
其他回答
我经常使用dispatch_after,所以我写了一个顶级实用函数来简化语法:
func delay(delay:Double, closure:()->()) {
dispatch_after(
dispatch_time(
DISPATCH_TIME_NOW,
Int64(delay * Double(NSEC_PER_SEC))
),
dispatch_get_main_queue(), closure)
}
现在你可以这样说:
delay(0.4) {
// do stuff
}
哇,一种你可以改进的语言。还有什么比这更好的呢?
更新Swift 3, Xcode 8种子6
看起来几乎不值得费心,现在他们已经改进了调用语法:
func delay(_ delay:Double, closure:@escaping ()->()) {
let when = DispatchTime.now() + delay
DispatchQueue.main.asyncAfter(deadline: when, execute: closure)
}
现在在Swift的中央调度(GCD)中异步调度不仅仅是语法糖。
添加Podfile
pod 'AsyncSwift'
然后,你可以这样使用它。
let seconds = 3.0
Async.main(after: seconds) {
print("Is called after 3 seconds")
}.background(after: 6.0) {
print("At least 3.0 seconds after previous block, and 6.0 after Async code is called")
}
在Swift 3.0中
调度队列
DispatchQueue(label: "test").async {
//long running Background Task
for obj in 0...1000 {
print("async \(obj)")
}
// UI update in main queue
DispatchQueue.main.async(execute: {
print("UI update on main queue")
})
}
DispatchQueue(label: "m").sync {
//long running Background Task
for obj in 0...1000 {
print("sync \(obj)")
}
// UI update in main queue
DispatchQueue.main.sync(execute: {
print("UI update on main queue")
})
}
5秒后调度
DispatchQueue.main.after(when: DispatchTime.now() + 5) {
print("Dispatch after 5 sec")
}
在Swift 5中,在下面使用:
DispatchQueue.main.asyncAfter(deadline: .now() + 0.2, execute: closure)
// time gap, specify unit is second
DispatchQueue.main.asyncAfter(deadline: .now() + .seconds(2)) {
Singleton.shared().printDate()
}
// default time gap is second, you can reduce it
DispatchQueue.main.asyncAfter(deadline: .now() + 0.2) {
// just do it!
}
保留当前队列!
除了很好地回答这个问题之外,您还可以考虑保留当前队列以防止不必要的主队列操作(例如,当您试图延迟一些异步操作时)。
func after(_ delay: TimeInterval,
perform block: @escaping ()->(),
on queue: DispatchQueue = OperationQueue.current?.underlyingQueue ?? .main) { // So this `queue` preserves the current queue and defaulted to the `main`. Also the caller can pass in the desired queue explicitly
queue.asyncAfter(deadline: .now() + delay, execute: block)
}
用法:
after(3) {
// will be executed on the caller's queue
print(Date())
}