Swift 4有一个很短的方法来做到这一点:

Timer.scheduledTimer(withTimeInterval: 2, repeats: false) { (timer) in
    // Your stuff here
    print("hello")
}

现在在Swift的中央调度(GCD)中异步调度不仅仅是语法糖。

添加Podfile

pod 'AsyncSwift'

然后，你可以这样使用它。

let seconds = 3.0
Async.main(after: seconds) {
print("Is called after 3 seconds")
}.background(after: 6.0) {
print("At least 3.0 seconds after previous block, and 6.0 after Async code is called")
}

Matt的语法非常好，如果你需要使块失效，你可能想使用这个:

typealias dispatch_cancelable_closure = (cancel : Bool) -> Void

func delay(time:NSTimeInterval, closure:()->Void) ->  dispatch_cancelable_closure? {

    func dispatch_later(clsr:()->Void) {
        dispatch_after(
            dispatch_time(
                DISPATCH_TIME_NOW,
                Int64(time * Double(NSEC_PER_SEC))
            ),
            dispatch_get_main_queue(), clsr)
    }

    var closure:dispatch_block_t? = closure
    var cancelableClosure:dispatch_cancelable_closure?

    let delayedClosure:dispatch_cancelable_closure = { cancel in
        if closure != nil {
            if (cancel == false) {
                dispatch_async(dispatch_get_main_queue(), closure!);
            }
        }
        closure = nil
        cancelableClosure = nil
    }

    cancelableClosure = delayedClosure

    dispatch_later {
        if let delayedClosure = cancelableClosure {
            delayedClosure(cancel: false)
        }
    }

    return cancelableClosure;
}

func cancel_delay(closure:dispatch_cancelable_closure?) {

    if closure != nil {
        closure!(cancel: true)
    }
}

使用方法如下

let retVal = delay(2.0) {
    println("Later")
}
delay(1.0) {
    cancel_delay(retVal)
}

学分

上面的链接似乎坏了。来自Github的原始Objc代码

Swift 3.0版本

以下闭包函数在主线程上执行一些延迟后的任务。

func performAfterDelay(delay : Double, onCompletion: @escaping() -> Void){

    DispatchQueue.main.asyncAfter(deadline: DispatchTime.now() + delay, execute: {
       onCompletion()
    })
}

像这样调用这个函数:

performAfterDelay(delay: 4.0) {
  print("test")
}

我经常使用dispatch_after，所以我写了一个顶级实用函数来简化语法:

func delay(delay:Double, closure:()->()) {
    dispatch_after(
        dispatch_time(
            DISPATCH_TIME_NOW,
            Int64(delay * Double(NSEC_PER_SEC))
        ),
        dispatch_get_main_queue(), closure)
}

现在你可以这样说:

delay(0.4) {
    // do stuff
}

哇，一种你可以改进的语言。还有什么比这更好的呢?

更新Swift 3, Xcode 8种子6

看起来几乎不值得费心，现在他们已经改进了调用语法:

func delay(_ delay:Double, closure:@escaping ()->()) {
    let when = DispatchTime.now() + delay
    DispatchQueue.main.asyncAfter(deadline: when, execute: closure)
}

在Swift 3.0中

调度队列

  DispatchQueue(label: "test").async {
        //long running Background Task
        for obj in 0...1000 {
            print("async \(obj)")
        }

        // UI update in main queue
        DispatchQueue.main.async(execute: { 
            print("UI update on main queue")
        })

    }

    DispatchQueue(label: "m").sync {
        //long running Background Task
        for obj in 0...1000 {
            print("sync \(obj)")
        }

        // UI update in main queue
        DispatchQueue.main.sync(execute: {
            print("UI update on main queue")
        })
    }

5秒后调度

    DispatchQueue.main.after(when: DispatchTime.now() + 5) {
        print("Dispatch after 5 sec")
    }