我的JQuery方法使用扩展方法:

public static MvcHtmlString SubmitButtonFor<TController>(this HtmlHelper helper, Expression<Action<TController>> action, string value) where TController : Controller
{
    RouteValueDictionary routingValues = Microsoft.Web.Mvc.Internal.ExpressionHelper.GetRouteValuesFromExpression(action);

    var onclick = string.Format("$('form').first().attr('action', '/{0}')", string.Join("/", routingValues.Values.ToArray().Where(x => x != null).Select(x => x.ToString()).ToArray()));
    var html = "<input type=\"submit\" value=\"" + value + "\" onclick=\"" + onclick + "\" />";

    return MvcHtmlString.Create(html);
}

你可以这样使用它:

@(Html.SubmitButtonFor<FooController>(c => c.Save(null), "Save"))

它是这样渲染的:

<input type="submit" value="Save" onclick="$('form').first().attr('action', '/Foo/Save')" >

这个脚本允许指定一个data-form-action属性，它将在所有浏览器中作为HTML5 formaction属性(以一种不引人注目的方式):

$(document).on('click', '[type="submit"][data-form-action]', function(event) {
    var $this = $(this),
    var formAction = $this.attr('data-form-action'),
    $form = $($this.closest('form'));
    $form.attr('action', formAction);             
});

包含按钮的表单将被发送到data-form-action属性中指定的URL:

<button type="submit" data-form-action="different/url">Submit</button>   

这需要jQuery 1.7。对于以前的版本，您应该使用live()而不是on()。

我也遇到过这个“问题”，但通过添加name属性找到了一个相当合理的解决方案。我不记得在其他语言中有这个问题。

http://www.w3.org/TR/html401/interact/forms.html#h-17.13.2

.．. 如果表单包含多个提交按钮，则只有激活的提交按钮是成功的。 .．.

这意味着以下代码值属性可以被更改、本地化、国际化，而不需要额外的代码检查强类型资源文件或常量。

<% Html.BeginForm("MyAction", "MyController", FormMethod.Post); %>
<input type="submit" name="send" value="Send" />
<input type="submit" name="cancel" value="Cancel" />
<input type="submit" name="draft" value="Save as draft" />
<% Html.EndForm(); %>`

在接收端，您只需要检查是否有任何已知的提交类型不是空

public ActionResult YourAction(YourModel model) {

    if(Request["send"] != null) {

        // we got a send

    }else if(Request["cancel"]) {

        // we got a cancel, but would you really want to post data for this?

    }else if(Request["draft"]) {

        // we got a draft

    }

}

它短小而紧凑:

Jeroen Dop回答了这个问题

<input type="submit" name="submitbutton1" value="submit1" />
<input type="submit" name="submitbutton2" value="submit2" />

在后面的代码中这样做

 if( Request.Form["submitbutton1"] != null)
{
    // Code for function 1
}
else if(Request.Form["submitButton2"] != null )
{
       // code for function 2
}

祝你好运。

//model
    public class input_element
        {
         public string Btn { get; set; }
        }   

//views--submit btn can be input type also...
    @using (Html.BeginForm())
    {
            <button type="submit" name="btn" value="verify">
             Verify data</button>
            <button type="submit" name="btn" value="save">
             Save data</button>    
            <button type="submit" name="btn" value="redirect">
                 Redirect</button>
    }

//controller

    public ActionResult About()
        {
            ViewBag.Message = "Your app description page.";
            return View();
        }

        [HttpPost]
        public ActionResult About(input_element model)
        {
                if (model.Btn == "verify")
                {
                // the Verify button was clicked
                }
                else if (model.Btn == "save")
                {
                // the Save button was clicked
                } 
                else if (model.Btn == "redirect")
                {
                // the Redirect button was clicked
                } 
                return View();
        }

当使用ajax表单时，我们可以使用ActionLinks与POST HttpMethod和 在AjaxOptions中序列化表单。OnBegin事件。

假设你有两个动作，InsertAction和UpdateAction:

<form>
    @Html.Hidden("SomeField", "SomeValue")

    @Ajax.ActionLink(
        "Insert",
        "InsertAction",
        null,
        new AjaxOptions { 
            OnBegin = "OnBegin", 
            UpdateTargetId = "yourDiv", 
            HttpMethod = "POST" })
    @Ajax.ActionLink(
        "Update",
        "UpdateAction",
        null,
        new AjaxOptions { 
            OnBegin = "OnBegin", 
            UpdateTargetId = "yourDiv", 
            HttpMethod = "POST" })
</form>

Javascript

function OnBegin(xhr, settings) {
    settings.data = $("form").serialize();
}