是否有一些简单的方法来处理来自同一个表单的多个提交按钮?例如:

<% Html.BeginForm("MyAction", "MyController", FormMethod.Post); %>
<input type="submit" value="Send" />
<input type="submit" value="Cancel" />
<% Html.EndForm(); %>

知道如何在ASP中做到这一点吗?NET框架测试版?我在谷歌上搜索的所有例子中都有单个按钮。


当前回答

你应该能够为按钮命名并赋予它们一个值;然后将此名称映射为操作的参数。或者,使用2个单独的动作链接或2个表单。

其他回答

我来派对已经很晚了,但现在开始… 我的实现借用了@mkozicki,但需要更少的硬编码字符串来出错。需要4.5+框架。实际上,控制器方法名应该是路由的关键。

标记。按钮名称必须以“action:[controllerMethodName]”为键

(注意使用c# 6的API名称,提供了对希望调用的控制器方法名称的特定类型引用。

<form>
    ... form fields ....
    <button name="action:@nameof(MyApp.Controllers.MyController.FundDeathStar)" type="submit" formmethod="post">Fund Death Star</button>
    <button name="action:@nameof(MyApp.Controllers.MyController.HireBoba)" type="submit" formmethod="post">Hire Boba Fett</button>
</form>

控制器:

namespace MyApp.Controllers
{
    class MyController
    {    
        [SubmitActionToThisMethod]
        public async Task<ActionResult> FundDeathStar(ImperialModel model)
        {
            await TrainStormTroopers();
            return View();
        }

        [SubmitActionToThisMethod]
        public async Task<ActionResult> HireBoba(ImperialModel model)
        {
            await RepairSlave1();
            return View();
        }
    }
}

属性的魔法。注意使用CallerMemberName功能。

[AttributeUsage(AttributeTargets.Method, AllowMultiple = false, Inherited = true)]
public class SubmitActionToThisMethodAttribute : ActionNameSelectorAttribute
{        
    public SubmitActionToThisMethodAttribute([CallerMemberName]string ControllerMethodName = "")
    {
        controllerMethod = ControllerMethodName;
        actionFormat = string.Concat(actionConstant, ":", controllerMethod);
    }
    const string actionConstant = "action";
    readonly string actionFormat;
    readonly string controllerMethod;

    public override bool IsValidName(ControllerContext controllerContext, string actionName, MethodInfo methodInfo)
    {
        var isValidName = false;
        var value = controllerContext.Controller.ValueProvider.GetValue(actionFormat);

        if (value != null)
        {
            controllerContext.Controller.ControllerContext.RouteData.Values[actionConstant] = controllerMethod;
            isValidName = true;
        }
        return isValidName;
    }
}

这是我发现的最好的方法:

http://iwayneo.blogspot.co.uk/2013/10/aspnet-mvc-action-selector-with-list.html

代码如下:

    /// <summary>
    /// ActionMethodSelector to enable submit buttons to execute specific action methods.
    /// </summary>
    public class AcceptParameterAttribute : ActionMethodSelectorAttribute
   {
        /// <summary>
        /// Gets or sets the value to use to inject the index into
        /// </summary>
       public string TargetArgument { get; set; }

       /// <summary>
       /// Gets or sets the value to use in submit button to identify which method to select. This must be unique in each controller.
       /// </summary>
       public string Action { get; set; }

       /// <summary>
       /// Gets or sets the regular expression to match the action.
       /// </summary>
       public string ActionRegex { get; set; }

       /// <summary>
       /// Determines whether the action method selection is valid for the specified controller context.
       /// </summary>
       /// <param name="controllerContext">The controller context.</param>
       /// <param name="methodInfo">Information about the action method.</param>
       /// <returns>true if the action method selection is valid for the specified controller context; otherwise, false.</returns>
       public override bool IsValidForRequest(ControllerContext controllerContext, MethodInfo methodInfo)
       {

           if (controllerContext == null)
           {
               throw new ArgumentNullException("controllerContext");
           }

           Func<NameValueCollection> formGetter;
           Func<NameValueCollection> queryStringGetter;

           ValidationUtility.GetUnvalidatedCollections(HttpContext.Current, out formGetter, out queryStringGetter);

           var form = formGetter();
           var queryString = queryStringGetter();

           var req = form.AllKeys.Any() ? form : queryString;

           if (!string.IsNullOrEmpty(this.ActionRegex))
           {
               foreach (var key in req.AllKeys.Where(k => k.StartsWith(Action, true, System.Threading.Thread.CurrentThread.CurrentCulture)))
               {
                   if (key.Contains(":"))
                   {
                       if (key.Split(':').Count() == this.ActionRegex.Split(':').Count())
                       {
                           bool match = false;
                           for (int i = 0; i < key.Split(':').Count(); i++)
                           {
                               if (Regex.IsMatch(key.Split(':')[0], this.ActionRegex.Split(':')[0]))
                               {
                                   match = true;
                               }
                               else
                               {
                                   match = false;
                                   break;
                               }
                           }

                           if (match)
                           {
                               return !string.IsNullOrEmpty(req[key]);
                           }
                       }
                   }
                   else
                   {
                       if (Regex.IsMatch(key, this.Action + this.ActionRegex))
                       {
                           return !string.IsNullOrEmpty(req[key]);
                       }
                   }

               }
               return false;
           }
           else
           {
               return req.AllKeys.Contains(this.Action);
           }
       }
   }

享受一个没有代码气味的多提交按钮的未来。

谢谢你!

刚刚写了一篇相关的文章: 多个提交按钮与ASP。NET MVC:

基本上,我用的不是ActionMethodSelectorAttribute,而是 ActionNameSelectorAttribute,它允许我假装动作名是我想要的任何东西。幸运的是,ActionNameSelectorAttribute不只是让我指定操作名称,而是我可以选择当前操作是否与请求匹配。

这就是我的班级(顺便说一句,我不太喜欢这个名字):

public class HttpParamActionAttribute : ActionNameSelectorAttribute {
    public override bool IsValidName(ControllerContext controllerContext, string actionName, MethodInfo methodInfo) {
        if (actionName.Equals(methodInfo.Name, StringComparison.InvariantCultureIgnoreCase))
            return true;

        if (!actionName.Equals("Action", StringComparison.InvariantCultureIgnoreCase))
            return false;

        var request = controllerContext.RequestContext.HttpContext.Request;
        return request[methodInfo.Name] != null;
    }
} 

只需要像这样定义一个表单:

<% using (Html.BeginForm("Action", "Post")) { %>
  <!— …form fields… -->
  <input type="submit" name="saveDraft" value="Save Draft" />
  <input type="submit" name="publish" value="Publish" />
<% } %> 

控制器有两个方法

public class PostController : Controller {
    [HttpParamAction]
    [AcceptVerbs(HttpVerbs.Post)]
    public ActionResult SaveDraft(…) {
        //…
    }

    [HttpParamAction]
    [AcceptVerbs(HttpVerbs.Post)]
    public ActionResult Publish(…) {
        //…
    } 
}

如您所见,该属性根本不需要指定任何内容。此外,按钮的名称直接转换为方法名称。此外(我还没有尝试过)这些应该作为正常的动作以及,所以你可以张贴到他们中的任何一个 直接。

Modified version of HttpParamActionAttribute method but with a bug fix for not causing an error on expired/invalid session postbacks. To see if this is a problem with your current site, open the your form in a window and just before you go to click Save or Publish, open a duplicate window, and logout. Now go back to your first window and try to submit your form using either button. For me I got an error so this change solves that problem for me. I omit a bunch of stuff for the sake of brevity but you should get the idea. The key parts are the inclusion of ActionName on the attribute and making sure the name passed in is the name of the View that shows the form

属性类

[AttributeUsage(AttributeTargets.Method, AllowMultiple = false, Inherited = true)]
public class HttpParamActionAttribute : ActionNameSelectorAttribute
{
    private readonly string actionName;

    public HttpParamActionAttribute(string actionName)
    {
        this.actionName = actionName;
    }

    public override bool IsValidName(ControllerContext controllerContext, string actionName, MethodInfo methodInfo)
    {
        if (actionName.Equals(methodInfo.Name, StringComparison.InvariantCultureIgnoreCase))
            return true;

        if (!actionName.Equals(this.actionName, StringComparison.InvariantCultureIgnoreCase))
            return false;

        var request = controllerContext.RequestContext.HttpContext.Request;
        return request[methodInfo.Name] != null;
    }
}

控制器

[Authorize(Roles="CanAddContent")]
public ActionResult CreateContent(Guid contentOwnerId)
{
    var viewModel = new ContentViewModel
    {
        ContentOwnerId = contentOwnerId
        //populate rest of view model
    }
    return View("CreateContent", viewModel);
}

[Authorize(Roles="CanAddContent"), HttpPost, HttpParamAction("CreateContent"), ValidateAntiForgeryToken]
public ActionResult SaveDraft(ContentFormModel model)
{
    //Save as draft
    return RedirectToAction("CreateContent");
}

[Authorize(Roles="CanAddContent"), HttpPost, HttpParamAction("CreateContent"), ValidateAntiForgeryToken]
public ActionResult Publish(ContentFormModel model)
{
    //publish content
    return RedirectToAction("CreateContent");
}

View

@using (Ajax.BeginForm("CreateContent", "MyController", new { contentOwnerId = Model.ContentOwnerId }))
{
    @Html.AntiForgeryToken()
    @Html.HiddenFor(x => x.ContentOwnerId)

    <!-- Rest of your form controls -->
    <input name="SaveDraft" type="submit" value="SaveDraft" />
    <input name="Publish" type="submit" value="Publish" />
}

这个脚本允许指定一个data-form-action属性,它将在所有浏览器中作为HTML5 formaction属性(以一种不引人注目的方式):

$(document).on('click', '[type="submit"][data-form-action]', function(event) {
    var $this = $(this),
    var formAction = $this.attr('data-form-action'),
    $form = $($this.closest('form'));
    $form.attr('action', formAction);             
});

包含按钮的表单将被发送到data-form-action属性中指定的URL:

<button type="submit" data-form-action="different/url">Submit</button>   

这需要jQuery 1.7。对于以前的版本,您应该使用live()而不是on()。