Modified version of HttpParamActionAttribute method but with a bug fix for not causing an error on expired/invalid session postbacks. To see if this is a problem with your current site, open the your form in a window and just before you go to click Save or Publish, open a duplicate window, and logout. Now go back to your first window and try to submit your form using either button. For me I got an error so this change solves that problem for me. I omit a bunch of stuff for the sake of brevity but you should get the idea. The key parts are the inclusion of ActionName on the attribute and making sure the name passed in is the name of the View that shows the form

属性类

[AttributeUsage(AttributeTargets.Method, AllowMultiple = false, Inherited = true)]
public class HttpParamActionAttribute : ActionNameSelectorAttribute
{
    private readonly string actionName;

    public HttpParamActionAttribute(string actionName)
    {
        this.actionName = actionName;
    }

    public override bool IsValidName(ControllerContext controllerContext, string actionName, MethodInfo methodInfo)
    {
        if (actionName.Equals(methodInfo.Name, StringComparison.InvariantCultureIgnoreCase))
            return true;

        if (!actionName.Equals(this.actionName, StringComparison.InvariantCultureIgnoreCase))
            return false;

        var request = controllerContext.RequestContext.HttpContext.Request;
        return request[methodInfo.Name] != null;
    }
}

控制器

[Authorize(Roles="CanAddContent")]
public ActionResult CreateContent(Guid contentOwnerId)
{
    var viewModel = new ContentViewModel
    {
        ContentOwnerId = contentOwnerId
        //populate rest of view model
    }
    return View("CreateContent", viewModel);
}

[Authorize(Roles="CanAddContent"), HttpPost, HttpParamAction("CreateContent"), ValidateAntiForgeryToken]
public ActionResult SaveDraft(ContentFormModel model)
{
    //Save as draft
    return RedirectToAction("CreateContent");
}

[Authorize(Roles="CanAddContent"), HttpPost, HttpParamAction("CreateContent"), ValidateAntiForgeryToken]
public ActionResult Publish(ContentFormModel model)
{
    //publish content
    return RedirectToAction("CreateContent");
}

View

@using (Ajax.BeginForm("CreateContent", "MyController", new { contentOwnerId = Model.ContentOwnerId }))
{
    @Html.AntiForgeryToken()
    @Html.HiddenFor(x => x.ContentOwnerId)

    <!-- Rest of your form controls -->
    <input name="SaveDraft" type="submit" value="SaveDraft" />
    <input name="Publish" type="submit" value="Publish" />
}

当使用ajax表单时，我们可以使用ActionLinks与POST HttpMethod和 在AjaxOptions中序列化表单。OnBegin事件。

假设你有两个动作，InsertAction和UpdateAction:

<form>
    @Html.Hidden("SomeField", "SomeValue")

    @Ajax.ActionLink(
        "Insert",
        "InsertAction",
        null,
        new AjaxOptions { 
            OnBegin = "OnBegin", 
            UpdateTargetId = "yourDiv", 
            HttpMethod = "POST" })
    @Ajax.ActionLink(
        "Update",
        "UpdateAction",
        null,
        new AjaxOptions { 
            OnBegin = "OnBegin", 
            UpdateTargetId = "yourDiv", 
            HttpMethod = "POST" })
</form>

Javascript

function OnBegin(xhr, settings) {
    settings.data = $("form").serialize();
}

下面是基于Maarten Balliauw的帖子和评论，针对多个提交按钮问题的一个非常干净的基于属性的解决方案。

[AttributeUsage(AttributeTargets.Method, AllowMultiple = false, Inherited = true)]
public class MultipleButtonAttribute : ActionNameSelectorAttribute
{
    public string Name { get; set; }
    public string Argument { get; set; }

    public override bool IsValidName(ControllerContext controllerContext, string actionName, MethodInfo methodInfo)
    {
        var isValidName = false;
        var keyValue = string.Format("{0}:{1}", Name, Argument);
        var value = controllerContext.Controller.ValueProvider.GetValue(keyValue);

        if (value != null)
        {
            controllerContext.Controller.ControllerContext.RouteData.Values[Name] = Argument;
            isValidName = true;
        }

        return isValidName;
    }
}

剃须刀:

<form action="" method="post">
 <input type="submit" value="Save" name="action:Save" />
 <input type="submit" value="Cancel" name="action:Cancel" />
</form>

和控制器:

[HttpPost]
[MultipleButton(Name = "action", Argument = "Save")]
public ActionResult Save(MessageModel mm) { ... }

[HttpPost]
[MultipleButton(Name = "action", Argument = "Cancel")]
public ActionResult Cancel(MessageModel mm) { ... }

更新:Razor页面提供相同的功能开箱即用。对于新的开发来说，它可能更可取。

我尝试综合所有的解决方案，并创建了一个[ButtenHandler]属性，它可以很容易地处理表单上的多个按钮。

我已经在CodeProject中描述了它在ASP中的多个参数化(本地化)表单按钮。净MVC。

要处理此按钮的简单情况:

<button type="submit" name="AddDepartment">Add Department</button>

你会有如下的动作方法:

[ButtonHandler()]
public ActionResult AddDepartment(Company model)
{
    model.Departments.Add(new Department());
    return View(model);
}

注意按钮的名称与动作方法的名称是如何匹配的。本文还描述了如何让按钮具有值和按钮具有索引。

Index.cshtml @using （Html.BeginForm（“Index”， “Home”， FormMethod.Post， new { id = “submitForm” }）） { 按钮类型=“提交” id=“btn批准” 名称=“命令” 值=“批准”>批准 按钮类型=“提交” id=“btn拒绝” 名称=“命令” 值=“拒绝”>拒绝 }

public class HomeController : Controller
{
    public ActionResult Index()
    {
        return View();
    }

    [HttpPost]
    public ActionResult Index(FormCollection frm, string Command)
    {
        if (Command == "Approve")
        {

        }
        else if (Command == "Reject")
        {

        }

        return View();
    }

}

视图中的代码是:

<script language="javascript" type="text/javascript">
    function SubmeterForm(id)
    {
        if (id=='btnOk')
            document.forms[0].submit(id);
        else
            document.forms[1].submit(id);
    }
</script>


<% Html.BeginForm("ObterNomeBotaoClicado/1", "Teste01", FormMethod.Post); %>
<input id="btnOk" type="button" value="Ok" onclick="javascript:SubmeterForm('btnOk')" />
<% Html.EndForm(); %>
<% Html.BeginForm("ObterNomeBotaoClicado/2", "Teste01", FormMethod.Post); %>
<input id="btnCancelar" type="button" value="Cancelar" onclick="javascript:SubmeterForm('btnCancelar')" />
<% Html.EndForm(); %>

在Controller中，代码是:

public ActionResult ObterNomeBotaoClicado(string id)
{
    if (id=="1")
        btnOkFunction(...);
    else
        btnCancelarFunction(...);
    return View();
}