如果你对HTML 5的使用没有限制，你可以使用带有formaction的<button>标签:

<form action="demo_form.asp" method="get">
   First name: <input type="text" name="fname" /><br />
   Last name: <input type="text" name="lname" /><br />
   <button type="submit">Submit</button><br />
   <button type="submit" formaction="demo_admin.asp">Submit as admin</button>
</form>

参考:http://www.w3schools.com/html5/att_button_formaction.asp

这个脚本允许指定一个data-form-action属性，它将在所有浏览器中作为HTML5 formaction属性(以一种不引人注目的方式):

$(document).on('click', '[type="submit"][data-form-action]', function(event) {
    var $this = $(this),
    var formAction = $this.attr('data-form-action'),
    $form = $($this.closest('form'));
    $form.attr('action', formAction);             
});

包含按钮的表单将被发送到data-form-action属性中指定的URL:

<button type="submit" data-form-action="different/url">Submit</button>   

这需要jQuery 1.7。对于以前的版本，您应该使用live()而不是on()。

如果您的浏览器支持输入按钮的属性格式操作(IE 10+，不确定其他浏览器)，那么以下应该工作:

@using (Html.BeginForm()){
    //put form inputs here

<input id="sendBtn" value="Send" type="submit" formaction="@Url.Action("Name Of Send Action")" />

<input id="cancelBtn" value="Cancel" type="submit" formaction="@Url.Action("Name of Cancel Action") />

}

使用自定义助手(创建一个“Helpers.”文件)。cshtml" App_Code文件夹内，在你的项目的根)用javascript重写(在一个'onclick'事件)表单的'动作'属性，你想要的东西，然后提交它。

助手可以是这样的:

@helper SubmitButton(string text, string controller,string action)
{   
    var uh = new System.Web.Mvc.UrlHelper(Context.Request.RequestContext);
    string url = @uh.Action(action, controller, null);   
    <input type=button  onclick="(
                                       function(e)
                                                 {
                                                   $(e).parent().attr('action', '@url'); //rewrite action url
                                                   //create a submit button to be clicked and removed, so that onsubmit is triggered
                                                   var form = document.getElementById($(e).parent().attr('id'));
                                                   var button = form.ownerDocument.createElement('input');
                                                   button.style.display = 'none';
                                                   button.type = 'submit';
                                                   form.appendChild(button).click(); 
                                                   form.removeChild(button);              
                                                  }
                                      )(this)" value="@text"/>
}

然后把它用作:

@Helpers.SubmitButton("Text for 1st button","ControllerForButton1","ActionForButton1")
@Helpers.SubmitButton("Text for 2nd button","ControllerForButton2","ActionForButton2")
...

在你的表单里面。

我尝试综合所有的解决方案，并创建了一个[ButtenHandler]属性，它可以很容易地处理表单上的多个按钮。

我已经在CodeProject中描述了它在ASP中的多个参数化(本地化)表单按钮。净MVC。

要处理此按钮的简单情况:

<button type="submit" name="AddDepartment">Add Department</button>

你会有如下的动作方法:

[ButtonHandler()]
public ActionResult AddDepartment(Company model)
{
    model.Departments.Add(new Department());
    return View(model);
}

注意按钮的名称与动作方法的名称是如何匹配的。本文还描述了如何让按钮具有值和按钮具有索引。

Modified version of HttpParamActionAttribute method but with a bug fix for not causing an error on expired/invalid session postbacks. To see if this is a problem with your current site, open the your form in a window and just before you go to click Save or Publish, open a duplicate window, and logout. Now go back to your first window and try to submit your form using either button. For me I got an error so this change solves that problem for me. I omit a bunch of stuff for the sake of brevity but you should get the idea. The key parts are the inclusion of ActionName on the attribute and making sure the name passed in is the name of the View that shows the form

属性类

[AttributeUsage(AttributeTargets.Method, AllowMultiple = false, Inherited = true)]
public class HttpParamActionAttribute : ActionNameSelectorAttribute
{
    private readonly string actionName;

    public HttpParamActionAttribute(string actionName)
    {
        this.actionName = actionName;
    }

    public override bool IsValidName(ControllerContext controllerContext, string actionName, MethodInfo methodInfo)
    {
        if (actionName.Equals(methodInfo.Name, StringComparison.InvariantCultureIgnoreCase))
            return true;

        if (!actionName.Equals(this.actionName, StringComparison.InvariantCultureIgnoreCase))
            return false;

        var request = controllerContext.RequestContext.HttpContext.Request;
        return request[methodInfo.Name] != null;
    }
}

控制器

[Authorize(Roles="CanAddContent")]
public ActionResult CreateContent(Guid contentOwnerId)
{
    var viewModel = new ContentViewModel
    {
        ContentOwnerId = contentOwnerId
        //populate rest of view model
    }
    return View("CreateContent", viewModel);
}

[Authorize(Roles="CanAddContent"), HttpPost, HttpParamAction("CreateContent"), ValidateAntiForgeryToken]
public ActionResult SaveDraft(ContentFormModel model)
{
    //Save as draft
    return RedirectToAction("CreateContent");
}

[Authorize(Roles="CanAddContent"), HttpPost, HttpParamAction("CreateContent"), ValidateAntiForgeryToken]
public ActionResult Publish(ContentFormModel model)
{
    //publish content
    return RedirectToAction("CreateContent");
}

View

@using (Ajax.BeginForm("CreateContent", "MyController", new { contentOwnerId = Model.ContentOwnerId }))
{
    @Html.AntiForgeryToken()
    @Html.HiddenFor(x => x.ContentOwnerId)

    <!-- Rest of your form controls -->
    <input name="SaveDraft" type="submit" value="SaveDraft" />
    <input name="Publish" type="submit" value="Publish" />
}