是否有一些简单的方法来处理来自同一个表单的多个提交按钮?例如:

<% Html.BeginForm("MyAction", "MyController", FormMethod.Post); %>
<input type="submit" value="Send" />
<input type="submit" value="Cancel" />
<% Html.EndForm(); %>

知道如何在ASP中做到这一点吗?NET框架测试版?我在谷歌上搜索的所有例子中都有单个按钮。


当前回答

刚刚写了一篇相关的文章: 多个提交按钮与ASP。NET MVC:

基本上,我用的不是ActionMethodSelectorAttribute,而是 ActionNameSelectorAttribute,它允许我假装动作名是我想要的任何东西。幸运的是,ActionNameSelectorAttribute不只是让我指定操作名称,而是我可以选择当前操作是否与请求匹配。

这就是我的班级(顺便说一句,我不太喜欢这个名字):

public class HttpParamActionAttribute : ActionNameSelectorAttribute {
    public override bool IsValidName(ControllerContext controllerContext, string actionName, MethodInfo methodInfo) {
        if (actionName.Equals(methodInfo.Name, StringComparison.InvariantCultureIgnoreCase))
            return true;

        if (!actionName.Equals("Action", StringComparison.InvariantCultureIgnoreCase))
            return false;

        var request = controllerContext.RequestContext.HttpContext.Request;
        return request[methodInfo.Name] != null;
    }
} 

只需要像这样定义一个表单:

<% using (Html.BeginForm("Action", "Post")) { %>
  <!— …form fields… -->
  <input type="submit" name="saveDraft" value="Save Draft" />
  <input type="submit" name="publish" value="Publish" />
<% } %> 

控制器有两个方法

public class PostController : Controller {
    [HttpParamAction]
    [AcceptVerbs(HttpVerbs.Post)]
    public ActionResult SaveDraft(…) {
        //…
    }

    [HttpParamAction]
    [AcceptVerbs(HttpVerbs.Post)]
    public ActionResult Publish(…) {
        //…
    } 
}

如您所见,该属性根本不需要指定任何内容。此外,按钮的名称直接转换为方法名称。此外(我还没有尝试过)这些应该作为正常的动作以及,所以你可以张贴到他们中的任何一个 直接。

其他回答

Modified version of HttpParamActionAttribute method but with a bug fix for not causing an error on expired/invalid session postbacks. To see if this is a problem with your current site, open the your form in a window and just before you go to click Save or Publish, open a duplicate window, and logout. Now go back to your first window and try to submit your form using either button. For me I got an error so this change solves that problem for me. I omit a bunch of stuff for the sake of brevity but you should get the idea. The key parts are the inclusion of ActionName on the attribute and making sure the name passed in is the name of the View that shows the form

属性类

[AttributeUsage(AttributeTargets.Method, AllowMultiple = false, Inherited = true)]
public class HttpParamActionAttribute : ActionNameSelectorAttribute
{
    private readonly string actionName;

    public HttpParamActionAttribute(string actionName)
    {
        this.actionName = actionName;
    }

    public override bool IsValidName(ControllerContext controllerContext, string actionName, MethodInfo methodInfo)
    {
        if (actionName.Equals(methodInfo.Name, StringComparison.InvariantCultureIgnoreCase))
            return true;

        if (!actionName.Equals(this.actionName, StringComparison.InvariantCultureIgnoreCase))
            return false;

        var request = controllerContext.RequestContext.HttpContext.Request;
        return request[methodInfo.Name] != null;
    }
}

控制器

[Authorize(Roles="CanAddContent")]
public ActionResult CreateContent(Guid contentOwnerId)
{
    var viewModel = new ContentViewModel
    {
        ContentOwnerId = contentOwnerId
        //populate rest of view model
    }
    return View("CreateContent", viewModel);
}

[Authorize(Roles="CanAddContent"), HttpPost, HttpParamAction("CreateContent"), ValidateAntiForgeryToken]
public ActionResult SaveDraft(ContentFormModel model)
{
    //Save as draft
    return RedirectToAction("CreateContent");
}

[Authorize(Roles="CanAddContent"), HttpPost, HttpParamAction("CreateContent"), ValidateAntiForgeryToken]
public ActionResult Publish(ContentFormModel model)
{
    //publish content
    return RedirectToAction("CreateContent");
}

View

@using (Ajax.BeginForm("CreateContent", "MyController", new { contentOwnerId = Model.ContentOwnerId }))
{
    @Html.AntiForgeryToken()
    @Html.HiddenFor(x => x.ContentOwnerId)

    <!-- Rest of your form controls -->
    <input name="SaveDraft" type="submit" value="SaveDraft" />
    <input name="Publish" type="submit" value="Publish" />
}

你应该能够为按钮命名并赋予它们一个值;然后将此名称映射为操作的参数。或者,使用2个单独的动作链接或2个表单。

视图中的代码是:

<script language="javascript" type="text/javascript">
    function SubmeterForm(id)
    {
        if (id=='btnOk')
            document.forms[0].submit(id);
        else
            document.forms[1].submit(id);
    }
</script>


<% Html.BeginForm("ObterNomeBotaoClicado/1", "Teste01", FormMethod.Post); %>
<input id="btnOk" type="button" value="Ok" onclick="javascript:SubmeterForm('btnOk')" />
<% Html.EndForm(); %>
<% Html.BeginForm("ObterNomeBotaoClicado/2", "Teste01", FormMethod.Post); %>
<input id="btnCancelar" type="button" value="Cancelar" onclick="javascript:SubmeterForm('btnCancelar')" />
<% Html.EndForm(); %>

在Controller中,代码是:

public ActionResult ObterNomeBotaoClicado(string id)
{
    if (id=="1")
        btnOkFunction(...);
    else
        btnCancelarFunction(...);
    return View();
}

我建议感兴趣的人看看Maarten Balliauw的解决方案。我认为它非常优雅。

如果链接消失,它将使用应用于控制器操作的MultiButton属性来指示该操作应该与哪个按钮单击相关。

Eilon建议你可以这样做:

If you have more than one button you can distinguish between them by giving each button a name: <input type="submit" name="SaveButton" value="Save data" /> <input type="submit" name="CancelButton" value="Cancel and go back to main page" /> In your controller action method you can add parameters named after the HTML input tag names: public ActionResult DoSomeStuff(string saveButton, string cancelButton, ... other parameters ...) { ... } If any value gets posted to one of those parameters, that means that button was the one that got clicked. The web browser will only post a value for the one button that got clicked. All other values will be null. if (saveButton != null) { /* do save logic */ } if (cancelButton != null) { /* do cancel logic */ }

我喜欢这个方法,因为它不依赖于提交按钮的值属性,这个属性比分配的名称更有可能改变,并且不需要启用javascript

看到的: http://forums.asp.net/p/1369617/2865166.aspx#2865166