我已经为HtmlHelper创建了一个ActionButton方法。它将在OnClick事件中生成带有javascript的普通输入按钮，将表单提交给指定的控制器/动作。

像这样使用辅助器

@Html.ActionButton("MyControllerName", "MyActionName", "button text")

这将生成以下HTML

<input type="button" value="button text" onclick="this.form.action = '/MyWebsiteFolder/MyControllerName/MyActionName'; this.form.submit();">

下面是扩展方法代码:

VB。网

<System.Runtime.CompilerServices.Extension()>
Function ActionButton(pHtml As HtmlHelper, pAction As String, pController As String, pRouteValues As Object, pBtnValue As String, pBtnName As String, pBtnID As String) As MvcHtmlString
    Dim urlHelperForActionLink As UrlHelper
    Dim btnTagBuilder As TagBuilder

    Dim actionLink As String
    Dim onClickEventJavascript As String

    urlHelperForActionLink = New UrlHelper(pHtml.ViewContext.RequestContext)
    If pController <> "" Then
        actionLink = urlHelperForActionLink.Action(pAction, pController, pRouteValues)
    Else
        actionLink = urlHelperForActionLink.Action(pAction, pRouteValues)
    End If
    onClickEventJavascript = "this.form.action = '" & actionLink & "'; this.form.submit();"

    btnTagBuilder = New TagBuilder("input")
    btnTagBuilder.MergeAttribute("type", "button")

    btnTagBuilder.MergeAttribute("onClick", onClickEventJavascript)

    If pBtnValue <> "" Then btnTagBuilder.MergeAttribute("value", pBtnValue)
    If pBtnName <> "" Then btnTagBuilder.MergeAttribute("name", pBtnName)
    If pBtnID <> "" Then btnTagBuilder.MergeAttribute("id", pBtnID)

    Return MvcHtmlString.Create(btnTagBuilder.ToString(TagRenderMode.Normal))
End Function

c# (c#代码只是从VB DLL中反编译的，所以它可以得到一些美化…但是时间太短了:-)

public static MvcHtmlString ActionButton(this HtmlHelper pHtml, string pAction, string pController, object pRouteValues, string pBtnValue, string pBtnName, string pBtnID)
{
    UrlHelper urlHelperForActionLink = new UrlHelper(pHtml.ViewContext.RequestContext);
    bool flag = Operators.CompareString(pController, "", true) != 0;
    string actionLink;
    if (flag)
    {
        actionLink = urlHelperForActionLink.Action(pAction, pController, System.Runtime.CompilerServices.RuntimeHelpers.GetObjectValue(pRouteValues));
    }
    else
    {
        actionLink = urlHelperForActionLink.Action(pAction, System.Runtime.CompilerServices.RuntimeHelpers.GetObjectValue(pRouteValues));
    }
    string onClickEventJavascript = "this.form.action = '" + actionLink + "'; this.form.submit();";
    TagBuilder btnTagBuilder = new TagBuilder("input");
    btnTagBuilder.MergeAttribute("type", "button");
    btnTagBuilder.MergeAttribute("onClick", onClickEventJavascript);
    flag = (Operators.CompareString(pBtnValue, "", true) != 0);
    if (flag)
    {
        btnTagBuilder.MergeAttribute("value", pBtnValue);
    }
    flag = (Operators.CompareString(pBtnName, "", true) != 0);
    if (flag)
    {
        btnTagBuilder.MergeAttribute("name", pBtnName);
    }
    flag = (Operators.CompareString(pBtnID, "", true) != 0);
    if (flag)
    {
        btnTagBuilder.MergeAttribute("id", pBtnID);
    }
    return MvcHtmlString.Create(btnTagBuilder.ToString(TagRenderMode.Normal));
}

这些方法具有各种参数，但是为了便于使用，您可以创建一些重载，只使用所需的参数。

我没有足够的代表在正确的地方发表评论，但我花了一整天的时间在这上面，所以想分享。

在尝试实现“MultipleButtonAttribute”解决方案时，ValueProvider.GetValue(keyValue)将错误地返回null。

原来我引用的是System.Web.MVC版本3.0，而它应该是4.0(其他程序集是4.0)。我不知道为什么我的项目没有正确升级，我没有其他明显的问题。

所以如果你的ActionNameSelectorAttribute不工作…检查。

我尝试综合所有的解决方案，并创建了一个[ButtenHandler]属性，它可以很容易地处理表单上的多个按钮。

我已经在CodeProject中描述了它在ASP中的多个参数化(本地化)表单按钮。净MVC。

要处理此按钮的简单情况:

<button type="submit" name="AddDepartment">Add Department</button>

你会有如下的动作方法:

[ButtonHandler()]
public ActionResult AddDepartment(Company model)
{
    model.Departments.Add(new Department());
    return View(model);
}

注意按钮的名称与动作方法的名称是如何匹配的。本文还描述了如何让按钮具有值和按钮具有索引。

Modified version of HttpParamActionAttribute method but with a bug fix for not causing an error on expired/invalid session postbacks. To see if this is a problem with your current site, open the your form in a window and just before you go to click Save or Publish, open a duplicate window, and logout. Now go back to your first window and try to submit your form using either button. For me I got an error so this change solves that problem for me. I omit a bunch of stuff for the sake of brevity but you should get the idea. The key parts are the inclusion of ActionName on the attribute and making sure the name passed in is the name of the View that shows the form

属性类

[AttributeUsage(AttributeTargets.Method, AllowMultiple = false, Inherited = true)]
public class HttpParamActionAttribute : ActionNameSelectorAttribute
{
    private readonly string actionName;

    public HttpParamActionAttribute(string actionName)
    {
        this.actionName = actionName;
    }

    public override bool IsValidName(ControllerContext controllerContext, string actionName, MethodInfo methodInfo)
    {
        if (actionName.Equals(methodInfo.Name, StringComparison.InvariantCultureIgnoreCase))
            return true;

        if (!actionName.Equals(this.actionName, StringComparison.InvariantCultureIgnoreCase))
            return false;

        var request = controllerContext.RequestContext.HttpContext.Request;
        return request[methodInfo.Name] != null;
    }
}

控制器

[Authorize(Roles="CanAddContent")]
public ActionResult CreateContent(Guid contentOwnerId)
{
    var viewModel = new ContentViewModel
    {
        ContentOwnerId = contentOwnerId
        //populate rest of view model
    }
    return View("CreateContent", viewModel);
}

[Authorize(Roles="CanAddContent"), HttpPost, HttpParamAction("CreateContent"), ValidateAntiForgeryToken]
public ActionResult SaveDraft(ContentFormModel model)
{
    //Save as draft
    return RedirectToAction("CreateContent");
}

[Authorize(Roles="CanAddContent"), HttpPost, HttpParamAction("CreateContent"), ValidateAntiForgeryToken]
public ActionResult Publish(ContentFormModel model)
{
    //publish content
    return RedirectToAction("CreateContent");
}

View

@using (Ajax.BeginForm("CreateContent", "MyController", new { contentOwnerId = Model.ContentOwnerId }))
{
    @Html.AntiForgeryToken()
    @Html.HiddenFor(x => x.ContentOwnerId)

    <!-- Rest of your form controls -->
    <input name="SaveDraft" type="submit" value="SaveDraft" />
    <input name="Publish" type="submit" value="Publish" />
}

如果你对HTML 5的使用没有限制，你可以使用带有formaction的<button>标签:

<form action="demo_form.asp" method="get">
   First name: <input type="text" name="fname" /><br />
   Last name: <input type="text" name="lname" /><br />
   <button type="submit">Submit</button><br />
   <button type="submit" formaction="demo_admin.asp">Submit as admin</button>
</form>

参考:http://www.w3schools.com/html5/att_button_formaction.asp

我的JQuery方法使用扩展方法:

public static MvcHtmlString SubmitButtonFor<TController>(this HtmlHelper helper, Expression<Action<TController>> action, string value) where TController : Controller
{
    RouteValueDictionary routingValues = Microsoft.Web.Mvc.Internal.ExpressionHelper.GetRouteValuesFromExpression(action);

    var onclick = string.Format("$('form').first().attr('action', '/{0}')", string.Join("/", routingValues.Values.ToArray().Where(x => x != null).Select(x => x.ToString()).ToArray()));
    var html = "<input type=\"submit\" value=\"" + value + "\" onclick=\"" + onclick + "\" />";

    return MvcHtmlString.Create(html);
}

你可以这样使用它:

@(Html.SubmitButtonFor<FooController>(c => c.Save(null), "Save"))

它是这样渲染的:

<input type="submit" value="Save" onclick="$('form').first().attr('action', '/Foo/Save')" >