我已经为HtmlHelper创建了一个ActionButton方法。它将在OnClick事件中生成带有javascript的普通输入按钮，将表单提交给指定的控制器/动作。

像这样使用辅助器

@Html.ActionButton("MyControllerName", "MyActionName", "button text")

这将生成以下HTML

<input type="button" value="button text" onclick="this.form.action = '/MyWebsiteFolder/MyControllerName/MyActionName'; this.form.submit();">

下面是扩展方法代码:

VB。网

<System.Runtime.CompilerServices.Extension()>
Function ActionButton(pHtml As HtmlHelper, pAction As String, pController As String, pRouteValues As Object, pBtnValue As String, pBtnName As String, pBtnID As String) As MvcHtmlString
    Dim urlHelperForActionLink As UrlHelper
    Dim btnTagBuilder As TagBuilder

    Dim actionLink As String
    Dim onClickEventJavascript As String

    urlHelperForActionLink = New UrlHelper(pHtml.ViewContext.RequestContext)
    If pController <> "" Then
        actionLink = urlHelperForActionLink.Action(pAction, pController, pRouteValues)
    Else
        actionLink = urlHelperForActionLink.Action(pAction, pRouteValues)
    End If
    onClickEventJavascript = "this.form.action = '" & actionLink & "'; this.form.submit();"

    btnTagBuilder = New TagBuilder("input")
    btnTagBuilder.MergeAttribute("type", "button")

    btnTagBuilder.MergeAttribute("onClick", onClickEventJavascript)

    If pBtnValue <> "" Then btnTagBuilder.MergeAttribute("value", pBtnValue)
    If pBtnName <> "" Then btnTagBuilder.MergeAttribute("name", pBtnName)
    If pBtnID <> "" Then btnTagBuilder.MergeAttribute("id", pBtnID)

    Return MvcHtmlString.Create(btnTagBuilder.ToString(TagRenderMode.Normal))
End Function

c# (c#代码只是从VB DLL中反编译的，所以它可以得到一些美化…但是时间太短了:-)

public static MvcHtmlString ActionButton(this HtmlHelper pHtml, string pAction, string pController, object pRouteValues, string pBtnValue, string pBtnName, string pBtnID)
{
    UrlHelper urlHelperForActionLink = new UrlHelper(pHtml.ViewContext.RequestContext);
    bool flag = Operators.CompareString(pController, "", true) != 0;
    string actionLink;
    if (flag)
    {
        actionLink = urlHelperForActionLink.Action(pAction, pController, System.Runtime.CompilerServices.RuntimeHelpers.GetObjectValue(pRouteValues));
    }
    else
    {
        actionLink = urlHelperForActionLink.Action(pAction, System.Runtime.CompilerServices.RuntimeHelpers.GetObjectValue(pRouteValues));
    }
    string onClickEventJavascript = "this.form.action = '" + actionLink + "'; this.form.submit();";
    TagBuilder btnTagBuilder = new TagBuilder("input");
    btnTagBuilder.MergeAttribute("type", "button");
    btnTagBuilder.MergeAttribute("onClick", onClickEventJavascript);
    flag = (Operators.CompareString(pBtnValue, "", true) != 0);
    if (flag)
    {
        btnTagBuilder.MergeAttribute("value", pBtnValue);
    }
    flag = (Operators.CompareString(pBtnName, "", true) != 0);
    if (flag)
    {
        btnTagBuilder.MergeAttribute("name", pBtnName);
    }
    flag = (Operators.CompareString(pBtnID, "", true) != 0);
    if (flag)
    {
        btnTagBuilder.MergeAttribute("id", pBtnID);
    }
    return MvcHtmlString.Create(btnTagBuilder.ToString(TagRenderMode.Normal));
}

这些方法具有各种参数，但是为了便于使用，您可以创建一些重载，只使用所需的参数。

我来派对已经很晚了，但现在开始… 我的实现借用了@mkozicki，但需要更少的硬编码字符串来出错。需要4.5+框架。实际上，控制器方法名应该是路由的关键。

标记。按钮名称必须以“action:[controllerMethodName]”为键

(注意使用c# 6的API名称，提供了对希望调用的控制器方法名称的特定类型引用。

<form>
    ... form fields ....
    <button name="action:@nameof(MyApp.Controllers.MyController.FundDeathStar)" type="submit" formmethod="post">Fund Death Star</button>
    <button name="action:@nameof(MyApp.Controllers.MyController.HireBoba)" type="submit" formmethod="post">Hire Boba Fett</button>
</form>

控制器:

namespace MyApp.Controllers
{
    class MyController
    {    
        [SubmitActionToThisMethod]
        public async Task<ActionResult> FundDeathStar(ImperialModel model)
        {
            await TrainStormTroopers();
            return View();
        }

        [SubmitActionToThisMethod]
        public async Task<ActionResult> HireBoba(ImperialModel model)
        {
            await RepairSlave1();
            return View();
        }
    }
}

属性的魔法。注意使用CallerMemberName功能。

[AttributeUsage(AttributeTargets.Method, AllowMultiple = false, Inherited = true)]
public class SubmitActionToThisMethodAttribute : ActionNameSelectorAttribute
{        
    public SubmitActionToThisMethodAttribute([CallerMemberName]string ControllerMethodName = "")
    {
        controllerMethod = ControllerMethodName;
        actionFormat = string.Concat(actionConstant, ":", controllerMethod);
    }
    const string actionConstant = "action";
    readonly string actionFormat;
    readonly string controllerMethod;

    public override bool IsValidName(ControllerContext controllerContext, string actionName, MethodInfo methodInfo)
    {
        var isValidName = false;
        var value = controllerContext.Controller.ValueProvider.GetValue(actionFormat);

        if (value != null)
        {
            controllerContext.Controller.ControllerContext.RouteData.Values[actionConstant] = controllerMethod;
            isValidName = true;
        }
        return isValidName;
    }
}

David Findley在他的ASP上写了3种不同的选择。网络博客。

阅读文章的多个按钮以相同的形式查看他的解决方案，以及每个方案的优缺点。恕我直言，他提供了一个非常优雅的解决方案，利用属性，你装饰你的行动。

我建议感兴趣的人看看Maarten Balliauw的解决方案。我认为它非常优雅。

如果链接消失，它将使用应用于控制器操作的MultiButton属性来指示该操作应该与哪个按钮单击相关。

Eilon建议你可以这样做:

If you have more than one button you can distinguish between them by giving each button a name: <input type="submit" name="SaveButton" value="Save data" /> <input type="submit" name="CancelButton" value="Cancel and go back to main page" /> In your controller action method you can add parameters named after the HTML input tag names: public ActionResult DoSomeStuff(string saveButton, string cancelButton, ... other parameters ...) { ... } If any value gets posted to one of those parameters, that means that button was the one that got clicked. The web browser will only post a value for the one button that got clicked. All other values will be null. if (saveButton != null) { /* do save logic */ } if (cancelButton != null) { /* do cancel logic */ }

我喜欢这个方法，因为它不依赖于提交按钮的值属性，这个属性比分配的名称更有可能改变，并且不需要启用javascript

看到的: http://forums.asp.net/p/1369617/2865166.aspx#2865166

Modified version of HttpParamActionAttribute method but with a bug fix for not causing an error on expired/invalid session postbacks. To see if this is a problem with your current site, open the your form in a window and just before you go to click Save or Publish, open a duplicate window, and logout. Now go back to your first window and try to submit your form using either button. For me I got an error so this change solves that problem for me. I omit a bunch of stuff for the sake of brevity but you should get the idea. The key parts are the inclusion of ActionName on the attribute and making sure the name passed in is the name of the View that shows the form

属性类

[AttributeUsage(AttributeTargets.Method, AllowMultiple = false, Inherited = true)]
public class HttpParamActionAttribute : ActionNameSelectorAttribute
{
    private readonly string actionName;

    public HttpParamActionAttribute(string actionName)
    {
        this.actionName = actionName;
    }

    public override bool IsValidName(ControllerContext controllerContext, string actionName, MethodInfo methodInfo)
    {
        if (actionName.Equals(methodInfo.Name, StringComparison.InvariantCultureIgnoreCase))
            return true;

        if (!actionName.Equals(this.actionName, StringComparison.InvariantCultureIgnoreCase))
            return false;

        var request = controllerContext.RequestContext.HttpContext.Request;
        return request[methodInfo.Name] != null;
    }
}

控制器

[Authorize(Roles="CanAddContent")]
public ActionResult CreateContent(Guid contentOwnerId)
{
    var viewModel = new ContentViewModel
    {
        ContentOwnerId = contentOwnerId
        //populate rest of view model
    }
    return View("CreateContent", viewModel);
}

[Authorize(Roles="CanAddContent"), HttpPost, HttpParamAction("CreateContent"), ValidateAntiForgeryToken]
public ActionResult SaveDraft(ContentFormModel model)
{
    //Save as draft
    return RedirectToAction("CreateContent");
}

[Authorize(Roles="CanAddContent"), HttpPost, HttpParamAction("CreateContent"), ValidateAntiForgeryToken]
public ActionResult Publish(ContentFormModel model)
{
    //publish content
    return RedirectToAction("CreateContent");
}

View

@using (Ajax.BeginForm("CreateContent", "MyController", new { contentOwnerId = Model.ContentOwnerId }))
{
    @Html.AntiForgeryToken()
    @Html.HiddenFor(x => x.ContentOwnerId)

    <!-- Rest of your form controls -->
    <input name="SaveDraft" type="submit" value="SaveDraft" />
    <input name="Publish" type="submit" value="Publish" />
}