下面是基于Maarten Balliauw的帖子和评论，针对多个提交按钮问题的一个非常干净的基于属性的解决方案。

[AttributeUsage(AttributeTargets.Method, AllowMultiple = false, Inherited = true)]
public class MultipleButtonAttribute : ActionNameSelectorAttribute
{
    public string Name { get; set; }
    public string Argument { get; set; }

    public override bool IsValidName(ControllerContext controllerContext, string actionName, MethodInfo methodInfo)
    {
        var isValidName = false;
        var keyValue = string.Format("{0}:{1}", Name, Argument);
        var value = controllerContext.Controller.ValueProvider.GetValue(keyValue);

        if (value != null)
        {
            controllerContext.Controller.ControllerContext.RouteData.Values[Name] = Argument;
            isValidName = true;
        }

        return isValidName;
    }
}

剃须刀:

<form action="" method="post">
 <input type="submit" value="Save" name="action:Save" />
 <input type="submit" value="Cancel" name="action:Cancel" />
</form>

和控制器:

[HttpPost]
[MultipleButton(Name = "action", Argument = "Save")]
public ActionResult Save(MessageModel mm) { ... }

[HttpPost]
[MultipleButton(Name = "action", Argument = "Cancel")]
public ActionResult Cancel(MessageModel mm) { ... }

更新:Razor页面提供相同的功能开箱即用。对于新的开发来说，它可能更可取。

当使用ajax表单时，我们可以使用ActionLinks与POST HttpMethod和 在AjaxOptions中序列化表单。OnBegin事件。

假设你有两个动作，InsertAction和UpdateAction:

<form>
    @Html.Hidden("SomeField", "SomeValue")

    @Ajax.ActionLink(
        "Insert",
        "InsertAction",
        null,
        new AjaxOptions { 
            OnBegin = "OnBegin", 
            UpdateTargetId = "yourDiv", 
            HttpMethod = "POST" })
    @Ajax.ActionLink(
        "Update",
        "UpdateAction",
        null,
        new AjaxOptions { 
            OnBegin = "OnBegin", 
            UpdateTargetId = "yourDiv", 
            HttpMethod = "POST" })
</form>

Javascript

function OnBegin(xhr, settings) {
    settings.data = $("form").serialize();
}

给你的提交按钮一个名字，然后在你的控制器方法中检查提交的值:

<% Html.BeginForm("MyAction", "MyController", FormMethod.Post); %>
<input type="submit" name="submitButton" value="Send" />
<input type="submit" name="submitButton" value="Cancel" />
<% Html.EndForm(); %>

发布到

public class MyController : Controller {
    public ActionResult MyAction(string submitButton) {
        switch(submitButton) {
            case "Send":
                // delegate sending to another controller action
                return(Send());
            case "Cancel":
                // call another action to perform the cancellation
                return(Cancel());
            default:
                // If they've submitted the form without a submitButton, 
                // just return the view again.
                return(View());
        }
    }

    private ActionResult Cancel() {
        // process the cancellation request here.
        return(View("Cancelled"));
    }

    private ActionResult Send() {
        // perform the actual send operation here.
        return(View("SendConfirmed"));
    }

}

编辑:

要将此方法扩展到本地化站点，请将您的消息隔离在其他地方(例如将资源文件编译为强类型资源类)

然后修改代码，使其像这样工作:

<% Html.BeginForm("MyAction", "MyController", FormMethod.Post); %>
<input type="submit" name="submitButton" value="<%= Html.Encode(Resources.Messages.Send)%>" />
<input type="submit" name="submitButton" value="<%=Html.Encode(Resources.Messages.Cancel)%>" />
<% Html.EndForm(); %>

你的控制器应该是这样的:

// Note that the localized resources aren't constants, so 
// we can't use a switch statement.

if (submitButton == Resources.Messages.Send) { 
    // delegate sending to another controller action
    return(Send());

} else if (submitButton == Resources.Messages.Cancel) {
     // call another action to perform the cancellation
     return(Cancel());
}

你可以这样写:

<% Html.BeginForm("MyAction", "MyController", FormMethod.Post); %>
<input type="submit" name="button" value="Send" />
<input type="submit" name="button" value="Cancel" />
<% Html.EndForm(); %>

然后在页面中检查name == "Send"或者name == "Cancel"…

Modified version of HttpParamActionAttribute method but with a bug fix for not causing an error on expired/invalid session postbacks. To see if this is a problem with your current site, open the your form in a window and just before you go to click Save or Publish, open a duplicate window, and logout. Now go back to your first window and try to submit your form using either button. For me I got an error so this change solves that problem for me. I omit a bunch of stuff for the sake of brevity but you should get the idea. The key parts are the inclusion of ActionName on the attribute and making sure the name passed in is the name of the View that shows the form

属性类

[AttributeUsage(AttributeTargets.Method, AllowMultiple = false, Inherited = true)]
public class HttpParamActionAttribute : ActionNameSelectorAttribute
{
    private readonly string actionName;

    public HttpParamActionAttribute(string actionName)
    {
        this.actionName = actionName;
    }

    public override bool IsValidName(ControllerContext controllerContext, string actionName, MethodInfo methodInfo)
    {
        if (actionName.Equals(methodInfo.Name, StringComparison.InvariantCultureIgnoreCase))
            return true;

        if (!actionName.Equals(this.actionName, StringComparison.InvariantCultureIgnoreCase))
            return false;

        var request = controllerContext.RequestContext.HttpContext.Request;
        return request[methodInfo.Name] != null;
    }
}

控制器

[Authorize(Roles="CanAddContent")]
public ActionResult CreateContent(Guid contentOwnerId)
{
    var viewModel = new ContentViewModel
    {
        ContentOwnerId = contentOwnerId
        //populate rest of view model
    }
    return View("CreateContent", viewModel);
}

[Authorize(Roles="CanAddContent"), HttpPost, HttpParamAction("CreateContent"), ValidateAntiForgeryToken]
public ActionResult SaveDraft(ContentFormModel model)
{
    //Save as draft
    return RedirectToAction("CreateContent");
}

[Authorize(Roles="CanAddContent"), HttpPost, HttpParamAction("CreateContent"), ValidateAntiForgeryToken]
public ActionResult Publish(ContentFormModel model)
{
    //publish content
    return RedirectToAction("CreateContent");
}

View

@using (Ajax.BeginForm("CreateContent", "MyController", new { contentOwnerId = Model.ContentOwnerId }))
{
    @Html.AntiForgeryToken()
    @Html.HiddenFor(x => x.ContentOwnerId)

    <!-- Rest of your form controls -->
    <input name="SaveDraft" type="submit" value="SaveDraft" />
    <input name="Publish" type="submit" value="Publish" />
}

这个脚本允许指定一个data-form-action属性，它将在所有浏览器中作为HTML5 formaction属性(以一种不引人注目的方式):

$(document).on('click', '[type="submit"][data-form-action]', function(event) {
    var $this = $(this),
    var formAction = $this.attr('data-form-action'),
    $form = $($this.closest('form'));
    $form.attr('action', formAction);             
});

包含按钮的表单将被发送到data-form-action属性中指定的URL:

<button type="submit" data-form-action="different/url">Submit</button>   

这需要jQuery 1.7。对于以前的版本，您应该使用live()而不是on()。