是否有一些简单的方法来处理来自同一个表单的多个提交按钮?例如:

<% Html.BeginForm("MyAction", "MyController", FormMethod.Post); %>
<input type="submit" value="Send" />
<input type="submit" value="Cancel" />
<% Html.EndForm(); %>

知道如何在ASP中做到这一点吗?NET框架测试版?我在谷歌上搜索的所有例子中都有单个按钮。


当前回答

[HttpPost]
public ActionResult ConfirmMobile(string nameValueResend, string nameValueSubmit, RegisterModel model)
    {
        var button = nameValueResend ?? nameValueSubmit;
        if (button == "Resend")
        {

        }
        else
        {

        }
    }


    Razor file Content:
    @using (Html.BeginForm()
    {
        <div class="page registration-result-page">

            <div class="page-title">
                <h1> Confirm Mobile Number</h1>
            </div>

            <div class="result">
                @Html.EditorFor(model => model.VefificationCode)
                @Html.LabelFor(model => model.VefificationCode, new { })
                @Html.ValidationMessageFor(model => model.VefificationCode)
            </div>
            <div class="buttons">
                <button type="submit" class="btn" name="nameValueResend" value="Resend">
                    Resend
                </button>
                <button type="submit" class="btn" name="nameValueSubmit" value="Verify">
                    Submit
                </button>

            </div>
            </div>

    }

其他回答

我的解决方案是使用2个asp面板:

< asp:面板ID = " . . "DefaultButton = " ID_OF_SHIPPING_SUBMIT_BUTTON "…> < / asp:面板>

Index.cshtml @using (Html.BeginForm(“Index”, “Home”, FormMethod.Post, new { id = “submitForm” })) { 按钮类型=“提交” id=“btn批准” 名称=“命令” 值=“批准”>批准 按钮类型=“提交” id=“btn拒绝” 名称=“命令” 值=“拒绝”>拒绝 }

public class HomeController : Controller
{
    public ActionResult Index()
    {
        return View();
    }

    [HttpPost]
    public ActionResult Index(FormCollection frm, string Command)
    {
        if (Command == "Approve")
        {

        }
        else if (Command == "Reject")
        {

        }

        return View();
    }

}

给你的提交按钮一个名字,然后在你的控制器方法中检查提交的值:

<% Html.BeginForm("MyAction", "MyController", FormMethod.Post); %>
<input type="submit" name="submitButton" value="Send" />
<input type="submit" name="submitButton" value="Cancel" />
<% Html.EndForm(); %>

发布到

public class MyController : Controller {
    public ActionResult MyAction(string submitButton) {
        switch(submitButton) {
            case "Send":
                // delegate sending to another controller action
                return(Send());
            case "Cancel":
                // call another action to perform the cancellation
                return(Cancel());
            default:
                // If they've submitted the form without a submitButton, 
                // just return the view again.
                return(View());
        }
    }

    private ActionResult Cancel() {
        // process the cancellation request here.
        return(View("Cancelled"));
    }

    private ActionResult Send() {
        // perform the actual send operation here.
        return(View("SendConfirmed"));
    }

}

编辑:

要将此方法扩展到本地化站点,请将您的消息隔离在其他地方(例如将资源文件编译为强类型资源类)

然后修改代码,使其像这样工作:

<% Html.BeginForm("MyAction", "MyController", FormMethod.Post); %>
<input type="submit" name="submitButton" value="<%= Html.Encode(Resources.Messages.Send)%>" />
<input type="submit" name="submitButton" value="<%=Html.Encode(Resources.Messages.Cancel)%>" />
<% Html.EndForm(); %>

你的控制器应该是这样的:

// Note that the localized resources aren't constants, so 
// we can't use a switch statement.

if (submitButton == Resources.Messages.Send) { 
    // delegate sending to another controller action
    return(Send());

} else if (submitButton == Resources.Messages.Cancel) {
     // call another action to perform the cancellation
     return(Cancel());
}

这个脚本允许指定一个data-form-action属性,它将在所有浏览器中作为HTML5 formaction属性(以一种不引人注目的方式):

$(document).on('click', '[type="submit"][data-form-action]', function(event) {
    var $this = $(this),
    var formAction = $this.attr('data-form-action'),
    $form = $($this.closest('form'));
    $form.attr('action', formAction);             
});

包含按钮的表单将被发送到data-form-action属性中指定的URL:

<button type="submit" data-form-action="different/url">Submit</button>   

这需要jQuery 1.7。对于以前的版本,您应该使用live()而不是on()。

以下是最适合我的方法:

<input type="submit" value="Delete" name="onDelete" />
<input type="submit" value="Save" name="onSave" />


public ActionResult Practice(MyModel model, string onSave, string onDelete)
{
    if (onDelete != null)
    {
        // Delete the object
        ...
        return EmptyResult();
    }

    // Save the object
    ...
    return EmptyResult();
}