我不喜欢ActionSelectName的地方是IsValidName被控制器中的每个动作方法调用;我不知道为什么会这样。我喜欢一种解决方案，每个按钮都有一个不同的名称，基于它的功能，但我不喜欢这样的事实，你必须有许多参数在动作方法中的按钮在表单。我已经为所有按钮类型创建了一个枚举:

public enum ButtonType
{
    Submit,
    Cancel,
    Delete
}

而不是ActionSelectName，我使用ActionFilter:

public class MultipleButtonsEnumAttribute : ActionFilterAttribute
{
    public Type EnumType { get; set; }

    public MultipleButtonsEnumAttribute(Type enumType)
    {
        EnumType = enumType;
    }

    public override void OnActionExecuting(ActionExecutingContext filterContext)
    {
        foreach (var key in filterContext.HttpContext.Request.Form.AllKeys)
        {
            if (Enum.IsDefined(EnumType, key))
            {
                var pDesc = filterContext.ActionDescriptor.GetParameters()
                    .FirstOrDefault(x => x.ParameterType == EnumType);
                filterContext.ActionParameters[pDesc.ParameterName] = Enum.Parse(EnumType, key);
                break;
            }
        }
    }
}

过滤器将在表单数据中找到按钮名称，如果按钮名称与枚举中定义的任何按钮类型匹配，它将在动作参数中找到ButtonType参数:

[MultipleButtonsEnumAttribute(typeof(ButtonType))]
public ActionResult Manage(ButtonType buttonPressed, ManageViewModel model)
{
    if (button == ButtonType.Cancel)
    {
        return RedirectToAction("Index", "Home");
    }
    //and so on
    return View(model)
}

然后在视图中，我可以使用:

<input type="submit" value="Button Cancel" name="@ButtonType.Cancel" />
<input type="submit" value="Button Submit" name="@ButtonType.Submit" />

我来派对已经很晚了，但现在开始… 我的实现借用了@mkozicki，但需要更少的硬编码字符串来出错。需要4.5+框架。实际上，控制器方法名应该是路由的关键。

标记。按钮名称必须以“action:[controllerMethodName]”为键

(注意使用c# 6的API名称，提供了对希望调用的控制器方法名称的特定类型引用。

<form>
    ... form fields ....
    <button name="action:@nameof(MyApp.Controllers.MyController.FundDeathStar)" type="submit" formmethod="post">Fund Death Star</button>
    <button name="action:@nameof(MyApp.Controllers.MyController.HireBoba)" type="submit" formmethod="post">Hire Boba Fett</button>
</form>

控制器:

namespace MyApp.Controllers
{
    class MyController
    {    
        [SubmitActionToThisMethod]
        public async Task<ActionResult> FundDeathStar(ImperialModel model)
        {
            await TrainStormTroopers();
            return View();
        }

        [SubmitActionToThisMethod]
        public async Task<ActionResult> HireBoba(ImperialModel model)
        {
            await RepairSlave1();
            return View();
        }
    }
}

属性的魔法。注意使用CallerMemberName功能。

[AttributeUsage(AttributeTargets.Method, AllowMultiple = false, Inherited = true)]
public class SubmitActionToThisMethodAttribute : ActionNameSelectorAttribute
{        
    public SubmitActionToThisMethodAttribute([CallerMemberName]string ControllerMethodName = "")
    {
        controllerMethod = ControllerMethodName;
        actionFormat = string.Concat(actionConstant, ":", controllerMethod);
    }
    const string actionConstant = "action";
    readonly string actionFormat;
    readonly string controllerMethod;

    public override bool IsValidName(ControllerContext controllerContext, string actionName, MethodInfo methodInfo)
    {
        var isValidName = false;
        var value = controllerContext.Controller.ValueProvider.GetValue(actionFormat);

        if (value != null)
        {
            controllerContext.Controller.ControllerContext.RouteData.Values[actionConstant] = controllerMethod;
            isValidName = true;
        }
        return isValidName;
    }
}

使用自定义助手(创建一个“Helpers.”文件)。cshtml" App_Code文件夹内，在你的项目的根)用javascript重写(在一个'onclick'事件)表单的'动作'属性，你想要的东西，然后提交它。

助手可以是这样的:

@helper SubmitButton(string text, string controller,string action)
{   
    var uh = new System.Web.Mvc.UrlHelper(Context.Request.RequestContext);
    string url = @uh.Action(action, controller, null);   
    <input type=button  onclick="(
                                       function(e)
                                                 {
                                                   $(e).parent().attr('action', '@url'); //rewrite action url
                                                   //create a submit button to be clicked and removed, so that onsubmit is triggered
                                                   var form = document.getElementById($(e).parent().attr('id'));
                                                   var button = form.ownerDocument.createElement('input');
                                                   button.style.display = 'none';
                                                   button.type = 'submit';
                                                   form.appendChild(button).click(); 
                                                   form.removeChild(button);              
                                                  }
                                      )(this)" value="@text"/>
}

然后把它用作:

@Helpers.SubmitButton("Text for 1st button","ControllerForButton1","ActionForButton1")
@Helpers.SubmitButton("Text for 2nd button","ControllerForButton2","ActionForButton2")
...

在你的表单里面。

[HttpPost]
public ActionResult ConfirmMobile(string nameValueResend, string nameValueSubmit, RegisterModel model)
    {
        var button = nameValueResend ?? nameValueSubmit;
        if (button == "Resend")
        {

        }
        else
        {

        }
    }


    Razor file Content:
    @using (Html.BeginForm()
    {
        <div class="page registration-result-page">

            <div class="page-title">
                <h1> Confirm Mobile Number</h1>
            </div>

            <div class="result">
                @Html.EditorFor(model => model.VefificationCode)
                @Html.LabelFor(model => model.VefificationCode, new { })
                @Html.ValidationMessageFor(model => model.VefificationCode)
            </div>
            <div class="buttons">
                <button type="submit" class="btn" name="nameValueResend" value="Resend">
                    Resend
                </button>
                <button type="submit" class="btn" name="nameValueSubmit" value="Verify">
                    Submit
                </button>

            </div>
            </div>

    }

当使用ajax表单时，我们可以使用ActionLinks与POST HttpMethod和 在AjaxOptions中序列化表单。OnBegin事件。

假设你有两个动作，InsertAction和UpdateAction:

<form>
    @Html.Hidden("SomeField", "SomeValue")

    @Ajax.ActionLink(
        "Insert",
        "InsertAction",
        null,
        new AjaxOptions { 
            OnBegin = "OnBegin", 
            UpdateTargetId = "yourDiv", 
            HttpMethod = "POST" })
    @Ajax.ActionLink(
        "Update",
        "UpdateAction",
        null,
        new AjaxOptions { 
            OnBegin = "OnBegin", 
            UpdateTargetId = "yourDiv", 
            HttpMethod = "POST" })
</form>

Javascript

function OnBegin(xhr, settings) {
    settings.data = $("form").serialize();
}

如果你对HTML 5的使用没有限制，你可以使用带有formaction的<button>标签:

<form action="demo_form.asp" method="get">
   First name: <input type="text" name="fname" /><br />
   Last name: <input type="text" name="lname" /><br />
   <button type="submit">Submit</button><br />
   <button type="submit" formaction="demo_admin.asp">Submit as admin</button>
</form>

参考:http://www.w3schools.com/html5/att_button_formaction.asp