是否有一些简单的方法来处理来自同一个表单的多个提交按钮?例如:
<% Html.BeginForm("MyAction", "MyController", FormMethod.Post); %>
<input type="submit" value="Send" />
<input type="submit" value="Cancel" />
<% Html.EndForm(); %>
知道如何在ASP中做到这一点吗?NET框架测试版?我在谷歌上搜索的所有例子中都有单个按钮。
是否有一些简单的方法来处理来自同一个表单的多个提交按钮?例如:
<% Html.BeginForm("MyAction", "MyController", FormMethod.Post); %>
<input type="submit" value="Send" />
<input type="submit" value="Cancel" />
<% Html.EndForm(); %>
知道如何在ASP中做到这一点吗?NET框架测试版?我在谷歌上搜索的所有例子中都有单个按钮。
当前回答
对于每个提交按钮,只需添加:
$('#btnSelector').click(function () {
$('form').attr('action', "/Your/Action/);
$('form').submit();
});
其他回答
我也遇到过这个“问题”,但通过添加name属性找到了一个相当合理的解决方案。我不记得在其他语言中有这个问题。
http://www.w3.org/TR/html401/interact/forms.html#h-17.13.2
... 如果表单包含多个提交按钮,则只有激活的提交按钮是成功的。 ...
这意味着以下代码值属性可以被更改、本地化、国际化,而不需要额外的代码检查强类型资源文件或常量。
<% Html.BeginForm("MyAction", "MyController", FormMethod.Post); %>
<input type="submit" name="send" value="Send" />
<input type="submit" name="cancel" value="Cancel" />
<input type="submit" name="draft" value="Save as draft" />
<% Html.EndForm(); %>`
在接收端,您只需要检查是否有任何已知的提交类型不是空
public ActionResult YourAction(YourModel model) {
if(Request["send"] != null) {
// we got a send
}else if(Request["cancel"]) {
// we got a cancel, but would you really want to post data for this?
}else if(Request["draft"]) {
// we got a draft
}
}
刚刚写了一篇相关的文章: 多个提交按钮与ASP。NET MVC:
基本上,我用的不是ActionMethodSelectorAttribute,而是 ActionNameSelectorAttribute,它允许我假装动作名是我想要的任何东西。幸运的是,ActionNameSelectorAttribute不只是让我指定操作名称,而是我可以选择当前操作是否与请求匹配。
这就是我的班级(顺便说一句,我不太喜欢这个名字):
public class HttpParamActionAttribute : ActionNameSelectorAttribute {
public override bool IsValidName(ControllerContext controllerContext, string actionName, MethodInfo methodInfo) {
if (actionName.Equals(methodInfo.Name, StringComparison.InvariantCultureIgnoreCase))
return true;
if (!actionName.Equals("Action", StringComparison.InvariantCultureIgnoreCase))
return false;
var request = controllerContext.RequestContext.HttpContext.Request;
return request[methodInfo.Name] != null;
}
}
只需要像这样定义一个表单:
<% using (Html.BeginForm("Action", "Post")) { %>
<!— …form fields… -->
<input type="submit" name="saveDraft" value="Save Draft" />
<input type="submit" name="publish" value="Publish" />
<% } %>
控制器有两个方法
public class PostController : Controller {
[HttpParamAction]
[AcceptVerbs(HttpVerbs.Post)]
public ActionResult SaveDraft(…) {
//…
}
[HttpParamAction]
[AcceptVerbs(HttpVerbs.Post)]
public ActionResult Publish(…) {
//…
}
}
如您所见,该属性根本不需要指定任何内容。此外,按钮的名称直接转换为方法名称。此外(我还没有尝试过)这些应该作为正常的动作以及,所以你可以张贴到他们中的任何一个 直接。
这是我发现的最好的方法:
http://iwayneo.blogspot.co.uk/2013/10/aspnet-mvc-action-selector-with-list.html
代码如下:
/// <summary>
/// ActionMethodSelector to enable submit buttons to execute specific action methods.
/// </summary>
public class AcceptParameterAttribute : ActionMethodSelectorAttribute
{
/// <summary>
/// Gets or sets the value to use to inject the index into
/// </summary>
public string TargetArgument { get; set; }
/// <summary>
/// Gets or sets the value to use in submit button to identify which method to select. This must be unique in each controller.
/// </summary>
public string Action { get; set; }
/// <summary>
/// Gets or sets the regular expression to match the action.
/// </summary>
public string ActionRegex { get; set; }
/// <summary>
/// Determines whether the action method selection is valid for the specified controller context.
/// </summary>
/// <param name="controllerContext">The controller context.</param>
/// <param name="methodInfo">Information about the action method.</param>
/// <returns>true if the action method selection is valid for the specified controller context; otherwise, false.</returns>
public override bool IsValidForRequest(ControllerContext controllerContext, MethodInfo methodInfo)
{
if (controllerContext == null)
{
throw new ArgumentNullException("controllerContext");
}
Func<NameValueCollection> formGetter;
Func<NameValueCollection> queryStringGetter;
ValidationUtility.GetUnvalidatedCollections(HttpContext.Current, out formGetter, out queryStringGetter);
var form = formGetter();
var queryString = queryStringGetter();
var req = form.AllKeys.Any() ? form : queryString;
if (!string.IsNullOrEmpty(this.ActionRegex))
{
foreach (var key in req.AllKeys.Where(k => k.StartsWith(Action, true, System.Threading.Thread.CurrentThread.CurrentCulture)))
{
if (key.Contains(":"))
{
if (key.Split(':').Count() == this.ActionRegex.Split(':').Count())
{
bool match = false;
for (int i = 0; i < key.Split(':').Count(); i++)
{
if (Regex.IsMatch(key.Split(':')[0], this.ActionRegex.Split(':')[0]))
{
match = true;
}
else
{
match = false;
break;
}
}
if (match)
{
return !string.IsNullOrEmpty(req[key]);
}
}
}
else
{
if (Regex.IsMatch(key, this.Action + this.ActionRegex))
{
return !string.IsNullOrEmpty(req[key]);
}
}
}
return false;
}
else
{
return req.AllKeys.Contains(this.Action);
}
}
}
享受一个没有代码气味的多提交按钮的未来。
谢谢你!
Modified version of HttpParamActionAttribute method but with a bug fix for not causing an error on expired/invalid session postbacks. To see if this is a problem with your current site, open the your form in a window and just before you go to click Save or Publish, open a duplicate window, and logout. Now go back to your first window and try to submit your form using either button. For me I got an error so this change solves that problem for me. I omit a bunch of stuff for the sake of brevity but you should get the idea. The key parts are the inclusion of ActionName on the attribute and making sure the name passed in is the name of the View that shows the form
属性类
[AttributeUsage(AttributeTargets.Method, AllowMultiple = false, Inherited = true)]
public class HttpParamActionAttribute : ActionNameSelectorAttribute
{
private readonly string actionName;
public HttpParamActionAttribute(string actionName)
{
this.actionName = actionName;
}
public override bool IsValidName(ControllerContext controllerContext, string actionName, MethodInfo methodInfo)
{
if (actionName.Equals(methodInfo.Name, StringComparison.InvariantCultureIgnoreCase))
return true;
if (!actionName.Equals(this.actionName, StringComparison.InvariantCultureIgnoreCase))
return false;
var request = controllerContext.RequestContext.HttpContext.Request;
return request[methodInfo.Name] != null;
}
}
控制器
[Authorize(Roles="CanAddContent")]
public ActionResult CreateContent(Guid contentOwnerId)
{
var viewModel = new ContentViewModel
{
ContentOwnerId = contentOwnerId
//populate rest of view model
}
return View("CreateContent", viewModel);
}
[Authorize(Roles="CanAddContent"), HttpPost, HttpParamAction("CreateContent"), ValidateAntiForgeryToken]
public ActionResult SaveDraft(ContentFormModel model)
{
//Save as draft
return RedirectToAction("CreateContent");
}
[Authorize(Roles="CanAddContent"), HttpPost, HttpParamAction("CreateContent"), ValidateAntiForgeryToken]
public ActionResult Publish(ContentFormModel model)
{
//publish content
return RedirectToAction("CreateContent");
}
View
@using (Ajax.BeginForm("CreateContent", "MyController", new { contentOwnerId = Model.ContentOwnerId }))
{
@Html.AntiForgeryToken()
@Html.HiddenFor(x => x.ContentOwnerId)
<!-- Rest of your form controls -->
<input name="SaveDraft" type="submit" value="SaveDraft" />
<input name="Publish" type="submit" value="Publish" />
}
我尝试综合所有的解决方案,并创建了一个[ButtenHandler]属性,它可以很容易地处理表单上的多个按钮。
我已经在CodeProject中描述了它在ASP中的多个参数化(本地化)表单按钮。净MVC。
要处理此按钮的简单情况:
<button type="submit" name="AddDepartment">Add Department</button>
你会有如下的动作方法:
[ButtonHandler()]
public ActionResult AddDepartment(Company model)
{
model.Departments.Add(new Department());
return View(model);
}
注意按钮的名称与动作方法的名称是如何匹配的。本文还描述了如何让按钮具有值和按钮具有索引。