在ASP中如何处理多个提交按钮?NET MVC框架?

是否有一些简单的方法来处理来自同一个表单的多个提交按钮?例如:

<% Html.BeginForm("MyAction", "MyController", FormMethod.Post); %>
<input type="submit" value="Send" />
<input type="submit" value="Cancel" />
<% Html.EndForm(); %>

知道如何在ASP中做到这一点吗?NET框架测试版?我在谷歌上搜索的所有例子中都有单个按钮。

当前回答

我也遇到过这个“问题”，但通过添加name属性找到了一个相当合理的解决方案。我不记得在其他语言中有这个问题。

http://www.w3.org/TR/html401/interact/forms.html#h-17.13.2

.．. 如果表单包含多个提交按钮，则只有激活的提交按钮是成功的。 .．.

这意味着以下代码值属性可以被更改、本地化、国际化，而不需要额外的代码检查强类型资源文件或常量。

<% Html.BeginForm("MyAction", "MyController", FormMethod.Post); %>
<input type="submit" name="send" value="Send" />
<input type="submit" name="cancel" value="Cancel" />
<input type="submit" name="draft" value="Save as draft" />
<% Html.EndForm(); %>`

在接收端，您只需要检查是否有任何已知的提交类型不是空

public ActionResult YourAction(YourModel model) {

    if(Request["send"] != null) {

        // we got a send

    }else if(Request["cancel"]) {

        // we got a cancel, but would you really want to post data for this?

    }else if(Request["draft"]) {

        // we got a draft

    }

}

2014-04-30 11:48:12

其他回答

以下是最适合我的方法:

<input type="submit" value="Delete" name="onDelete" />
<input type="submit" value="Save" name="onSave" />


public ActionResult Practice(MyModel model, string onSave, string onDelete)
{
    if (onDelete != null)
    {
        // Delete the object
        ...
        return EmptyResult();
    }

    // Save the object
    ...
    return EmptyResult();
}

2011-12-22 00:46:25

基于mkozicki的答案，我提出了一个有点不同的解决方案。我仍然使用ActionNameSelectorAttribute，但我需要处理两个按钮“保存”和“同步”。它们做的几乎是一样的，所以我不想有两个动作。

属性:

public class MultipleButtonActionAttribute : ActionNameSelectorAttribute
{        
    private readonly List<string> AcceptedButtonNames;

    public MultipleButtonActionAttribute(params string[] acceptedButtonNames)
    {
        AcceptedButtonNames = acceptedButtonNames.ToList();
    }

    public override bool IsValidName(ControllerContext controllerContext, string actionName, MethodInfo methodInfo)
    {            
        foreach (var acceptedButtonName in AcceptedButtonNames)
        {
            var button = controllerContext.Controller.ValueProvider.GetValue(acceptedButtonName);
            if (button == null)
            {
                continue;
            }                
            controllerContext.Controller.ControllerContext.RouteData.Values.Add("ButtonName", acceptedButtonName);
            return true;
        }
        return false;
    }
}

view

<input type="submit" value="Save" name="Save" />
<input type="submit" value="Save and Sync" name="Sync" />

控制器

 [MultipleButtonAction("Save", "Sync")]
 public ActionResult Sync(OrgSynchronizationEditModel model)
 {
     var btn = this.RouteData.Values["ButtonName"];

我还想指出，如果动作做不同的事情，我可能会遵循mkozicki的帖子。

2013-09-26 05:35:04

我来派对已经很晚了，但现在开始… 我的实现借用了@mkozicki，但需要更少的硬编码字符串来出错。需要4.5+框架。实际上，控制器方法名应该是路由的关键。

标记。按钮名称必须以“action:[controllerMethodName]”为键

(注意使用c# 6的API名称，提供了对希望调用的控制器方法名称的特定类型引用。

<form>
    ... form fields ....
    <button name="action:@nameof(MyApp.Controllers.MyController.FundDeathStar)" type="submit" formmethod="post">Fund Death Star</button>
    <button name="action:@nameof(MyApp.Controllers.MyController.HireBoba)" type="submit" formmethod="post">Hire Boba Fett</button>
</form>

控制器:

namespace MyApp.Controllers
{
    class MyController
    {    
        [SubmitActionToThisMethod]
        public async Task<ActionResult> FundDeathStar(ImperialModel model)
        {
            await TrainStormTroopers();
            return View();
        }

        [SubmitActionToThisMethod]
        public async Task<ActionResult> HireBoba(ImperialModel model)
        {
            await RepairSlave1();
            return View();
        }
    }
}

属性的魔法。注意使用CallerMemberName功能。

[AttributeUsage(AttributeTargets.Method, AllowMultiple = false, Inherited = true)]
public class SubmitActionToThisMethodAttribute : ActionNameSelectorAttribute
{        
    public SubmitActionToThisMethodAttribute([CallerMemberName]string ControllerMethodName = "")
    {
        controllerMethod = ControllerMethodName;
        actionFormat = string.Concat(actionConstant, ":", controllerMethod);
    }
    const string actionConstant = "action";
    readonly string actionFormat;
    readonly string controllerMethod;

    public override bool IsValidName(ControllerContext controllerContext, string actionName, MethodInfo methodInfo)
    {
        var isValidName = false;
        var value = controllerContext.Controller.ValueProvider.GetValue(actionFormat);

        if (value != null)
        {
            controllerContext.Controller.ControllerContext.RouteData.Values[actionConstant] = controllerMethod;
            isValidName = true;
        }
        return isValidName;
    }
}

2015-11-12 02:22:12

Modified version of HttpParamActionAttribute method but with a bug fix for not causing an error on expired/invalid session postbacks. To see if this is a problem with your current site, open the your form in a window and just before you go to click Save or Publish, open a duplicate window, and logout. Now go back to your first window and try to submit your form using either button. For me I got an error so this change solves that problem for me. I omit a bunch of stuff for the sake of brevity but you should get the idea. The key parts are the inclusion of ActionName on the attribute and making sure the name passed in is the name of the View that shows the form

属性类

[AttributeUsage(AttributeTargets.Method, AllowMultiple = false, Inherited = true)]
public class HttpParamActionAttribute : ActionNameSelectorAttribute
{
    private readonly string actionName;

    public HttpParamActionAttribute(string actionName)
    {
        this.actionName = actionName;
    }

    public override bool IsValidName(ControllerContext controllerContext, string actionName, MethodInfo methodInfo)
    {
        if (actionName.Equals(methodInfo.Name, StringComparison.InvariantCultureIgnoreCase))
            return true;

        if (!actionName.Equals(this.actionName, StringComparison.InvariantCultureIgnoreCase))
            return false;

        var request = controllerContext.RequestContext.HttpContext.Request;
        return request[methodInfo.Name] != null;
    }
}

控制器

[Authorize(Roles="CanAddContent")]
public ActionResult CreateContent(Guid contentOwnerId)
{
    var viewModel = new ContentViewModel
    {
        ContentOwnerId = contentOwnerId
        //populate rest of view model
    }
    return View("CreateContent", viewModel);
}

[Authorize(Roles="CanAddContent"), HttpPost, HttpParamAction("CreateContent"), ValidateAntiForgeryToken]
public ActionResult SaveDraft(ContentFormModel model)
{
    //Save as draft
    return RedirectToAction("CreateContent");
}

[Authorize(Roles="CanAddContent"), HttpPost, HttpParamAction("CreateContent"), ValidateAntiForgeryToken]
public ActionResult Publish(ContentFormModel model)
{
    //publish content
    return RedirectToAction("CreateContent");
}

View

@using (Ajax.BeginForm("CreateContent", "MyController", new { contentOwnerId = Model.ContentOwnerId }))
{
    @Html.AntiForgeryToken()
    @Html.HiddenFor(x => x.ContentOwnerId)

    <!-- Rest of your form controls -->
    <input name="SaveDraft" type="submit" value="SaveDraft" />
    <input name="Publish" type="submit" value="Publish" />
}

2013-10-17 18:19:00