是否有一些简单的方法来处理来自同一个表单的多个提交按钮?例如:
<% Html.BeginForm("MyAction", "MyController", FormMethod.Post); %>
<input type="submit" value="Send" />
<input type="submit" value="Cancel" />
<% Html.EndForm(); %>
知道如何在ASP中做到这一点吗?NET框架测试版?我在谷歌上搜索的所有例子中都有单个按钮。
是否有一些简单的方法来处理来自同一个表单的多个提交按钮?例如:
<% Html.BeginForm("MyAction", "MyController", FormMethod.Post); %>
<input type="submit" value="Send" />
<input type="submit" value="Cancel" />
<% Html.EndForm(); %>
知道如何在ASP中做到这一点吗?NET框架测试版?我在谷歌上搜索的所有例子中都有单个按钮。
当前回答
当使用ajax表单时,我们可以使用ActionLinks与POST HttpMethod和 在AjaxOptions中序列化表单。OnBegin事件。
假设你有两个动作,InsertAction和UpdateAction:
<form>
@Html.Hidden("SomeField", "SomeValue")
@Ajax.ActionLink(
"Insert",
"InsertAction",
null,
new AjaxOptions {
OnBegin = "OnBegin",
UpdateTargetId = "yourDiv",
HttpMethod = "POST" })
@Ajax.ActionLink(
"Update",
"UpdateAction",
null,
new AjaxOptions {
OnBegin = "OnBegin",
UpdateTargetId = "yourDiv",
HttpMethod = "POST" })
</form>
Javascript
function OnBegin(xhr, settings) {
settings.data = $("form").serialize();
}
其他回答
给你的提交按钮一个名字,然后在你的控制器方法中检查提交的值:
<% Html.BeginForm("MyAction", "MyController", FormMethod.Post); %>
<input type="submit" name="submitButton" value="Send" />
<input type="submit" name="submitButton" value="Cancel" />
<% Html.EndForm(); %>
发布到
public class MyController : Controller {
public ActionResult MyAction(string submitButton) {
switch(submitButton) {
case "Send":
// delegate sending to another controller action
return(Send());
case "Cancel":
// call another action to perform the cancellation
return(Cancel());
default:
// If they've submitted the form without a submitButton,
// just return the view again.
return(View());
}
}
private ActionResult Cancel() {
// process the cancellation request here.
return(View("Cancelled"));
}
private ActionResult Send() {
// perform the actual send operation here.
return(View("SendConfirmed"));
}
}
编辑:
要将此方法扩展到本地化站点,请将您的消息隔离在其他地方(例如将资源文件编译为强类型资源类)
然后修改代码,使其像这样工作:
<% Html.BeginForm("MyAction", "MyController", FormMethod.Post); %>
<input type="submit" name="submitButton" value="<%= Html.Encode(Resources.Messages.Send)%>" />
<input type="submit" name="submitButton" value="<%=Html.Encode(Resources.Messages.Cancel)%>" />
<% Html.EndForm(); %>
你的控制器应该是这样的:
// Note that the localized resources aren't constants, so
// we can't use a switch statement.
if (submitButton == Resources.Messages.Send) {
// delegate sending to another controller action
return(Send());
} else if (submitButton == Resources.Messages.Cancel) {
// call another action to perform the cancellation
return(Cancel());
}
我来派对已经很晚了,但现在开始… 我的实现借用了@mkozicki,但需要更少的硬编码字符串来出错。需要4.5+框架。实际上,控制器方法名应该是路由的关键。
标记。按钮名称必须以“action:[controllerMethodName]”为键
(注意使用c# 6的API名称,提供了对希望调用的控制器方法名称的特定类型引用。
<form>
... form fields ....
<button name="action:@nameof(MyApp.Controllers.MyController.FundDeathStar)" type="submit" formmethod="post">Fund Death Star</button>
<button name="action:@nameof(MyApp.Controllers.MyController.HireBoba)" type="submit" formmethod="post">Hire Boba Fett</button>
</form>
控制器:
namespace MyApp.Controllers
{
class MyController
{
[SubmitActionToThisMethod]
public async Task<ActionResult> FundDeathStar(ImperialModel model)
{
await TrainStormTroopers();
return View();
}
[SubmitActionToThisMethod]
public async Task<ActionResult> HireBoba(ImperialModel model)
{
await RepairSlave1();
return View();
}
}
}
属性的魔法。注意使用CallerMemberName功能。
[AttributeUsage(AttributeTargets.Method, AllowMultiple = false, Inherited = true)]
public class SubmitActionToThisMethodAttribute : ActionNameSelectorAttribute
{
public SubmitActionToThisMethodAttribute([CallerMemberName]string ControllerMethodName = "")
{
controllerMethod = ControllerMethodName;
actionFormat = string.Concat(actionConstant, ":", controllerMethod);
}
const string actionConstant = "action";
readonly string actionFormat;
readonly string controllerMethod;
public override bool IsValidName(ControllerContext controllerContext, string actionName, MethodInfo methodInfo)
{
var isValidName = false;
var value = controllerContext.Controller.ValueProvider.GetValue(actionFormat);
if (value != null)
{
controllerContext.Controller.ControllerContext.RouteData.Values[actionConstant] = controllerMethod;
isValidName = true;
}
return isValidName;
}
}
以下是最适合我的方法:
<input type="submit" value="Delete" name="onDelete" />
<input type="submit" value="Save" name="onSave" />
public ActionResult Practice(MyModel model, string onSave, string onDelete)
{
if (onDelete != null)
{
// Delete the object
...
return EmptyResult();
}
// Save the object
...
return EmptyResult();
}
您可以像前面提到的那样检查动作中的名称,但是您可能会考虑这是否是好的设计。考虑动作的职责,不要将这种设计过多地与按钮名称等UI方面结合起来,这是一个好主意。所以考虑使用两种形式和两种动作:
<% Html.BeginForm("Send", "MyController", FormMethod.Post); %>
<input type="submit" name="button" value="Send" />
<% Html.EndForm(); %>
<% Html.BeginForm("Cancel", "MyController", FormMethod.Post); %>
<input type="submit" name="button" value="Cancel" />
<% Html.EndForm(); %>
此外,在“取消”的情况下,您通常只是不处理表单,而是转到一个新的URL。在这种情况下,你根本不需要提交表单,只需要一个链接:
<%=Html.ActionLink("Cancel", "List", "MyController") %>
我也遇到过这个“问题”,但通过添加name属性找到了一个相当合理的解决方案。我不记得在其他语言中有这个问题。
http://www.w3.org/TR/html401/interact/forms.html#h-17.13.2
... 如果表单包含多个提交按钮,则只有激活的提交按钮是成功的。 ...
这意味着以下代码值属性可以被更改、本地化、国际化,而不需要额外的代码检查强类型资源文件或常量。
<% Html.BeginForm("MyAction", "MyController", FormMethod.Post); %>
<input type="submit" name="send" value="Send" />
<input type="submit" name="cancel" value="Cancel" />
<input type="submit" name="draft" value="Save as draft" />
<% Html.EndForm(); %>`
在接收端,您只需要检查是否有任何已知的提交类型不是空
public ActionResult YourAction(YourModel model) {
if(Request["send"] != null) {
// we got a send
}else if(Request["cancel"]) {
// we got a cancel, but would you really want to post data for this?
}else if(Request["draft"]) {
// we got a draft
}
}