是否有一些简单的方法来处理来自同一个表单的多个提交按钮?例如:

<% Html.BeginForm("MyAction", "MyController", FormMethod.Post); %>
<input type="submit" value="Send" />
<input type="submit" value="Cancel" />
<% Html.EndForm(); %>

知道如何在ASP中做到这一点吗?NET框架测试版?我在谷歌上搜索的所有例子中都有单个按钮。


当前回答

当使用ajax表单时,我们可以使用ActionLinks与POST HttpMethod和 在AjaxOptions中序列化表单。OnBegin事件。

假设你有两个动作,InsertAction和UpdateAction:

<form>
    @Html.Hidden("SomeField", "SomeValue")

    @Ajax.ActionLink(
        "Insert",
        "InsertAction",
        null,
        new AjaxOptions { 
            OnBegin = "OnBegin", 
            UpdateTargetId = "yourDiv", 
            HttpMethod = "POST" })
    @Ajax.ActionLink(
        "Update",
        "UpdateAction",
        null,
        new AjaxOptions { 
            OnBegin = "OnBegin", 
            UpdateTargetId = "yourDiv", 
            HttpMethod = "POST" })
</form>

Javascript

function OnBegin(xhr, settings) {
    settings.data = $("form").serialize();
}

其他回答

我来派对已经很晚了,但现在开始… 我的实现借用了@mkozicki,但需要更少的硬编码字符串来出错。需要4.5+框架。实际上,控制器方法名应该是路由的关键。

标记。按钮名称必须以“action:[controllerMethodName]”为键

(注意使用c# 6的API名称,提供了对希望调用的控制器方法名称的特定类型引用。

<form>
    ... form fields ....
    <button name="action:@nameof(MyApp.Controllers.MyController.FundDeathStar)" type="submit" formmethod="post">Fund Death Star</button>
    <button name="action:@nameof(MyApp.Controllers.MyController.HireBoba)" type="submit" formmethod="post">Hire Boba Fett</button>
</form>

控制器:

namespace MyApp.Controllers
{
    class MyController
    {    
        [SubmitActionToThisMethod]
        public async Task<ActionResult> FundDeathStar(ImperialModel model)
        {
            await TrainStormTroopers();
            return View();
        }

        [SubmitActionToThisMethod]
        public async Task<ActionResult> HireBoba(ImperialModel model)
        {
            await RepairSlave1();
            return View();
        }
    }
}

属性的魔法。注意使用CallerMemberName功能。

[AttributeUsage(AttributeTargets.Method, AllowMultiple = false, Inherited = true)]
public class SubmitActionToThisMethodAttribute : ActionNameSelectorAttribute
{        
    public SubmitActionToThisMethodAttribute([CallerMemberName]string ControllerMethodName = "")
    {
        controllerMethod = ControllerMethodName;
        actionFormat = string.Concat(actionConstant, ":", controllerMethod);
    }
    const string actionConstant = "action";
    readonly string actionFormat;
    readonly string controllerMethod;

    public override bool IsValidName(ControllerContext controllerContext, string actionName, MethodInfo methodInfo)
    {
        var isValidName = false;
        var value = controllerContext.Controller.ValueProvider.GetValue(actionFormat);

        if (value != null)
        {
            controllerContext.Controller.ControllerContext.RouteData.Values[actionConstant] = controllerMethod;
            isValidName = true;
        }
        return isValidName;
    }
}

您可以像前面提到的那样检查动作中的名称,但是您可能会考虑这是否是好的设计。考虑动作的职责,不要将这种设计过多地与按钮名称等UI方面结合起来,这是一个好主意。所以考虑使用两种形式和两种动作:

<% Html.BeginForm("Send", "MyController", FormMethod.Post); %>
<input type="submit" name="button" value="Send" />
<% Html.EndForm(); %>

<% Html.BeginForm("Cancel", "MyController", FormMethod.Post); %>
<input type="submit" name="button" value="Cancel" />
<% Html.EndForm(); %>

此外,在“取消”的情况下,您通常只是不处理表单,而是转到一个新的URL。在这种情况下,你根本不需要提交表单,只需要一个链接:

<%=Html.ActionLink("Cancel", "List", "MyController") %>
//model
    public class input_element
        {
         public string Btn { get; set; }
        }   

//views--submit btn can be input type also...
    @using (Html.BeginForm())
    {
            <button type="submit" name="btn" value="verify">
             Verify data</button>
            <button type="submit" name="btn" value="save">
             Save data</button>    
            <button type="submit" name="btn" value="redirect">
                 Redirect</button>
    }

//controller

    public ActionResult About()
        {
            ViewBag.Message = "Your app description page.";
            return View();
        }

        [HttpPost]
        public ActionResult About(input_element model)
        {
                if (model.Btn == "verify")
                {
                // the Verify button was clicked
                }
                else if (model.Btn == "save")
                {
                // the Save button was clicked
                } 
                else if (model.Btn == "redirect")
                {
                // the Redirect button was clicked
                } 
                return View();
        }
[HttpPost]
public ActionResult ConfirmMobile(string nameValueResend, string nameValueSubmit, RegisterModel model)
    {
        var button = nameValueResend ?? nameValueSubmit;
        if (button == "Resend")
        {

        }
        else
        {

        }
    }


    Razor file Content:
    @using (Html.BeginForm()
    {
        <div class="page registration-result-page">

            <div class="page-title">
                <h1> Confirm Mobile Number</h1>
            </div>

            <div class="result">
                @Html.EditorFor(model => model.VefificationCode)
                @Html.LabelFor(model => model.VefificationCode, new { })
                @Html.ValidationMessageFor(model => model.VefificationCode)
            </div>
            <div class="buttons">
                <button type="submit" class="btn" name="nameValueResend" value="Resend">
                    Resend
                </button>
                <button type="submit" class="btn" name="nameValueSubmit" value="Verify">
                    Submit
                </button>

            </div>
            </div>

    }

这个脚本允许指定一个data-form-action属性,它将在所有浏览器中作为HTML5 formaction属性(以一种不引人注目的方式):

$(document).on('click', '[type="submit"][data-form-action]', function(event) {
    var $this = $(this),
    var formAction = $this.attr('data-form-action'),
    $form = $($this.closest('form'));
    $form.attr('action', formAction);             
});

包含按钮的表单将被发送到data-form-action属性中指定的URL:

<button type="submit" data-form-action="different/url">Submit</button>   

这需要jQuery 1.7。对于以前的版本,您应该使用live()而不是on()。