是否有一些简单的方法来处理来自同一个表单的多个提交按钮?例如:
<% Html.BeginForm("MyAction", "MyController", FormMethod.Post); %>
<input type="submit" value="Send" />
<input type="submit" value="Cancel" />
<% Html.EndForm(); %>
知道如何在ASP中做到这一点吗?NET框架测试版?我在谷歌上搜索的所有例子中都有单个按钮。
是否有一些简单的方法来处理来自同一个表单的多个提交按钮?例如:
<% Html.BeginForm("MyAction", "MyController", FormMethod.Post); %>
<input type="submit" value="Send" />
<input type="submit" value="Cancel" />
<% Html.EndForm(); %>
知道如何在ASP中做到这一点吗?NET框架测试版?我在谷歌上搜索的所有例子中都有单个按钮。
当前回答
当使用ajax表单时,我们可以使用ActionLinks与POST HttpMethod和 在AjaxOptions中序列化表单。OnBegin事件。
假设你有两个动作,InsertAction和UpdateAction:
<form>
@Html.Hidden("SomeField", "SomeValue")
@Ajax.ActionLink(
"Insert",
"InsertAction",
null,
new AjaxOptions {
OnBegin = "OnBegin",
UpdateTargetId = "yourDiv",
HttpMethod = "POST" })
@Ajax.ActionLink(
"Update",
"UpdateAction",
null,
new AjaxOptions {
OnBegin = "OnBegin",
UpdateTargetId = "yourDiv",
HttpMethod = "POST" })
</form>
Javascript
function OnBegin(xhr, settings) {
settings.data = $("form").serialize();
}
其他回答
我来派对已经很晚了,但现在开始… 我的实现借用了@mkozicki,但需要更少的硬编码字符串来出错。需要4.5+框架。实际上,控制器方法名应该是路由的关键。
标记。按钮名称必须以“action:[controllerMethodName]”为键
(注意使用c# 6的API名称,提供了对希望调用的控制器方法名称的特定类型引用。
<form>
... form fields ....
<button name="action:@nameof(MyApp.Controllers.MyController.FundDeathStar)" type="submit" formmethod="post">Fund Death Star</button>
<button name="action:@nameof(MyApp.Controllers.MyController.HireBoba)" type="submit" formmethod="post">Hire Boba Fett</button>
</form>
控制器:
namespace MyApp.Controllers
{
class MyController
{
[SubmitActionToThisMethod]
public async Task<ActionResult> FundDeathStar(ImperialModel model)
{
await TrainStormTroopers();
return View();
}
[SubmitActionToThisMethod]
public async Task<ActionResult> HireBoba(ImperialModel model)
{
await RepairSlave1();
return View();
}
}
}
属性的魔法。注意使用CallerMemberName功能。
[AttributeUsage(AttributeTargets.Method, AllowMultiple = false, Inherited = true)]
public class SubmitActionToThisMethodAttribute : ActionNameSelectorAttribute
{
public SubmitActionToThisMethodAttribute([CallerMemberName]string ControllerMethodName = "")
{
controllerMethod = ControllerMethodName;
actionFormat = string.Concat(actionConstant, ":", controllerMethod);
}
const string actionConstant = "action";
readonly string actionFormat;
readonly string controllerMethod;
public override bool IsValidName(ControllerContext controllerContext, string actionName, MethodInfo methodInfo)
{
var isValidName = false;
var value = controllerContext.Controller.ValueProvider.GetValue(actionFormat);
if (value != null)
{
controllerContext.Controller.ControllerContext.RouteData.Values[actionConstant] = controllerMethod;
isValidName = true;
}
return isValidName;
}
}
您可以像前面提到的那样检查动作中的名称,但是您可能会考虑这是否是好的设计。考虑动作的职责,不要将这种设计过多地与按钮名称等UI方面结合起来,这是一个好主意。所以考虑使用两种形式和两种动作:
<% Html.BeginForm("Send", "MyController", FormMethod.Post); %>
<input type="submit" name="button" value="Send" />
<% Html.EndForm(); %>
<% Html.BeginForm("Cancel", "MyController", FormMethod.Post); %>
<input type="submit" name="button" value="Cancel" />
<% Html.EndForm(); %>
此外,在“取消”的情况下,您通常只是不处理表单,而是转到一个新的URL。在这种情况下,你根本不需要提交表单,只需要一个链接:
<%=Html.ActionLink("Cancel", "List", "MyController") %>
//model
public class input_element
{
public string Btn { get; set; }
}
//views--submit btn can be input type also...
@using (Html.BeginForm())
{
<button type="submit" name="btn" value="verify">
Verify data</button>
<button type="submit" name="btn" value="save">
Save data</button>
<button type="submit" name="btn" value="redirect">
Redirect</button>
}
//controller
public ActionResult About()
{
ViewBag.Message = "Your app description page.";
return View();
}
[HttpPost]
public ActionResult About(input_element model)
{
if (model.Btn == "verify")
{
// the Verify button was clicked
}
else if (model.Btn == "save")
{
// the Save button was clicked
}
else if (model.Btn == "redirect")
{
// the Redirect button was clicked
}
return View();
}
[HttpPost]
public ActionResult ConfirmMobile(string nameValueResend, string nameValueSubmit, RegisterModel model)
{
var button = nameValueResend ?? nameValueSubmit;
if (button == "Resend")
{
}
else
{
}
}
Razor file Content:
@using (Html.BeginForm()
{
<div class="page registration-result-page">
<div class="page-title">
<h1> Confirm Mobile Number</h1>
</div>
<div class="result">
@Html.EditorFor(model => model.VefificationCode)
@Html.LabelFor(model => model.VefificationCode, new { })
@Html.ValidationMessageFor(model => model.VefificationCode)
</div>
<div class="buttons">
<button type="submit" class="btn" name="nameValueResend" value="Resend">
Resend
</button>
<button type="submit" class="btn" name="nameValueSubmit" value="Verify">
Submit
</button>
</div>
</div>
}
这个脚本允许指定一个data-form-action属性,它将在所有浏览器中作为HTML5 formaction属性(以一种不引人注目的方式):
$(document).on('click', '[type="submit"][data-form-action]', function(event) {
var $this = $(this),
var formAction = $this.attr('data-form-action'),
$form = $($this.closest('form'));
$form.attr('action', formAction);
});
包含按钮的表单将被发送到data-form-action属性中指定的URL:
<button type="submit" data-form-action="different/url">Submit</button>
这需要jQuery 1.7。对于以前的版本,您应该使用live()而不是on()。