而不是运行脚本使用。您可以使用sh Run2.sh或bash Run2.sh运行它

将启动一个新的子shell，然后运行脚本，它将在脚本结束时关闭，而打开另一个shell。

1)如果脚本成功，exit 0将从脚本中出来。

2)如果失败，exit 1将从脚本中出来。

你可以根据你的需要尝试以上两种。

是的,你可以用return代替exit。它的主要目的是从shell函数返回，但如果在source-d脚本中使用它，它将从该脚本返回。

如Bash参考手册§4.1“Bourne Shell Builtins”所述:

return [n] Cause a shell function to exit with the return value n. If n is not supplied, the return value is the exit status of the last command executed in the function. This may also be used to terminate execution of a script being executed with the . (or source) builtin, returning either n or the exit status of the last command executed within the script as the exit status of the script. Any command associated with the RETURN trap is executed before execution resumes after the function or script. The return status is non-zero if return is used outside a function and not during the execution of a script by . or source.

如果你的终端模拟器没有-hold，你可以净化一个源脚本，并保持终端:

#!/bin/sh
sed "s/exit/return/g" script >/tmp/script
. /tmp/script
read

否则你可以使用$TERM -hold -e脚本

您可以在return语句/命令之后添加一个额外的退出命令，这样它就可以同时从命令行执行脚本和从终端获取源。

脚本中的退出代码示例:

   if [ $# -lt 2 ]; then
     echo "Needs at least two arguments"
     return 1 2>/dev/null
     exit 1
   fi

当您在返回命令之后查找脚本时，将不会调用带有exit命令的行。

当您执行脚本时，返回命令会给出一个错误。因此，我们通过将错误消息转发到/dev/null.来抑制错误消息

我找不到解决方案，所以对于那些想要离开嵌套脚本而不离开终端窗口的人:

# this is just script which goes to directory if path satisfies regex
wpr(){
    leave=false
    pwd=$(pwd)
    if [[ "$pwd" =~ ddev.*web ]]; then
        # echo "your in wordpress instalation"
        wpDir=$(echo "$pwd" | grep -o  '.*\/web')
        cd $wpDir
        return
    fi
    echo 'please be in wordpress directory'
    # to leave from outside the scope
    leave=true
    return
}

wpt(){
    # nested function which returns $leave variable
    wpr
    
    # interupts the script if $leave is true
    if $leave; then
        return;
    fi
    echo 'here is the rest of the script, executes if leave is not defined'
}