There is generally nothing to be gained by divorcing object initialization from construction. RAII is correct, a successful call to the constructor should either result in a fully initialized live object or it should fail, and ALL failures at any point in any code path should always throw an exception. You gain nothing by use of a separate init() method except additional complexity at some level. The ctor contract should be either it returns a functional valid object or it cleans up after itself and throws.

考虑一下，如果实现了单独的init方法，仍然必须调用它。它仍然有可能抛出异常，它们仍然必须被处理，而且它们实际上总是必须在构造函数之后立即被调用，除了现在你有4种可能的对象状态而不是2种(IE，已构造，初始化，未初始化，失败vs只是有效和不存在)。

In any case I've run across in 25 years of OO development cases where it seems like a separate init method would 'solve some problem' are design flaws. If you don't need an object NOW then you shouldn't be constructing it now, and if you do need it now then you need it initialized. KISS should always be the principle followed, along with the simple concept that the behavior, state, and API of any interface should reflect WHAT the object does, not HOW it does it, client code should not even be aware that the object has any kind of internal state that requires initialization, thus the init after pattern violates this principle.

由于部分创建的类可能导致的所有麻烦，我认为永远不会。

如果需要在构造过程中验证某些内容，请将构造函数设为私有并定义一个公共静态工厂方法。如果某些东西无效，该方法可以抛出。但是如果一切都检查出来了，它就调用构造函数，保证不会抛出。

我不能说明Objective-C中的最佳实践，但在c++中，构造函数抛出异常是可以的。特别是没有其他方法可以确保在不调用isOK()方法的情况下报告构造过程中遇到的异常情况。

函数try块特性是专门为支持构造函数成员初始化失败而设计的(尽管它也可以用于常规函数)。这是修改或丰富将要抛出的异常信息的唯一方法。但由于其最初的设计目的(在构造函数中使用)，它不允许空catch()子句包含异常。

请注意，如果您在初始化器中抛出异常，如果任何代码使用[[[MyObj alloc] init] autorelease]模式，那么您将最终泄漏，因为异常将跳过自动释放。

看这个问题:

在init中引发异常时如何防止泄漏?

Throwing an exception during construction is a great way to make your code way more complex. Things that would seem simple suddenly become hard. For example, let's say you have a stack. How do you pop the stack and return the top value? Well, if the objects in the stack can throw in their constructors (constructing the temporary to return to the caller), you can't guarantee that you won't lose data (decrement stack pointer, construct return value using copy constructor of value in stack, which throws, and now have a stack that just lost an item)! This is why std::stack::pop does not return a value, and you have to call std::stack::top.

这个问题在这里有很好的描述，检查第10项，编写异常安全的代码。

严格地从Java的角度来说，任何时候初始化使用非法值的构造函数时，它都应该抛出异常。这样它就不会被构造成一个糟糕的状态。