假设我有一个字典列表:
[
{'id': 1, 'name': 'john', 'age': 34},
{'id': 1, 'name': 'john', 'age': 34},
{'id': 2, 'name': 'hanna', 'age': 30},
]
如何获得唯一字典的列表(删除重复项)?
[
{'id': 1, 'name': 'john', 'age': 34},
{'id': 2, 'name': 'hanna', 'age': 30},
]
我总结了我最喜欢的尝试:
https://repl.it/@SmaMa/Python-List-of-unique-dictionaries
# ----------------------------------------------
# Setup
# ----------------------------------------------
myList = [
{"id":"1", "lala": "value_1"},
{"id": "2", "lala": "value_2"},
{"id": "2", "lala": "value_2"},
{"id": "3", "lala": "value_3"}
]
print("myList:", myList)
# -----------------------------------------------
# Option 1 if objects has an unique identifier
# -----------------------------------------------
myUniqueList = list({myObject['id']:myObject for myObject in myList}.values())
print("myUniqueList:", myUniqueList)
# -----------------------------------------------
# Option 2 if uniquely identified by whole object
# -----------------------------------------------
myUniqueSet = [dict(s) for s in set(frozenset(myObject.items()) for myObject in myList)]
print("myUniqueSet:", myUniqueSet)
# -----------------------------------------------
# Option 3 for hashable objects (not dicts)
# -----------------------------------------------
myHashableObjects = list(set(["1", "2", "2", "3"]))
print("myHashAbleList:", myHashableObjects)
我总结了我最喜欢的尝试:
https://repl.it/@SmaMa/Python-List-of-unique-dictionaries
# ----------------------------------------------
# Setup
# ----------------------------------------------
myList = [
{"id":"1", "lala": "value_1"},
{"id": "2", "lala": "value_2"},
{"id": "2", "lala": "value_2"},
{"id": "3", "lala": "value_3"}
]
print("myList:", myList)
# -----------------------------------------------
# Option 1 if objects has an unique identifier
# -----------------------------------------------
myUniqueList = list({myObject['id']:myObject for myObject in myList}.values())
print("myUniqueList:", myUniqueList)
# -----------------------------------------------
# Option 2 if uniquely identified by whole object
# -----------------------------------------------
myUniqueSet = [dict(s) for s in set(frozenset(myObject.items()) for myObject in myList)]
print("myUniqueSet:", myUniqueSet)
# -----------------------------------------------
# Option 3 for hashable objects (not dicts)
# -----------------------------------------------
myHashableObjects = list(set(["1", "2", "2", "3"]))
print("myHashAbleList:", myHashableObjects)
我不知道你是否只希望列表中dicts的id是唯一的,但如果目标是有一组dict,其中所有键的值都是唯一的。你应该像这样使用元组键:
>>> L=[
... {'id':1,'name':'john', 'age':34},
... {'id':1,'name':'john', 'age':34},
... {'id':2,'name':'hanna', 'age':30},
... {'id':2,'name':'hanna', 'age':50}
... ]
>>> len(L)
4
>>> L=list({(v['id'], v['age'], v['name']):v for v in L}.values())
>>>L
[{'id': 1, 'name': 'john', 'age': 34}, {'id': 2, 'name': 'hanna', 'age': 30}, {'id': 2, 'name': 'hanna', 'age': 50}]
>>>len(L)
3
希望它能帮助你或其他有顾虑的人....
可能有更优雅的解决方案,但我认为最好添加一个更详细的解决方案,使其更容易遵循。这里假设没有唯一键,你有一个简单的k,v结构,并且你使用的python版本保证了列表顺序。这适用于原来的职位。
data_set = [
{'id': 1, 'name': 'john', 'age': 34},
{'id': 1, 'name': 'john', 'age': 34},
{'id': 2, 'name': 'hanna', 'age': 30},
]
# list of keys
keys = [k for k in data_set[0]]
# Create a List of Lists of the values from the data Set
data_set_list = [[v for v in v.values()] for v in data_set]
# Dedupe
new_data_set = []
for lst in data_set_list:
# Check if list exists in new data set
if lst in new_data_set:
print(lst)
continue
# Add list to new data set
new_data_set.append(lst)
# Create dicts
new_data_set = [dict(zip(keys,lst)) for lst in new_data_set]
print(new_data_set)
我们可以用熊猫
import pandas as pd
yourdict=pd.DataFrame(L).drop_duplicates().to_dict('r')
Out[293]: [{'age': 34, 'id': 1, 'name': 'john'}, {'age': 30, 'id': 2, 'name': 'hanna'}]
注意与接受答案略有不同。
drop_duplicate将检查pandas中的所有列,如果都相同则删除该行。
例如:
如果我们把第二个字典的名字从约翰改为彼得
L=[
{'id': 1, 'name': 'john', 'age': 34},
{'id': 1, 'name': 'peter', 'age': 34},
{'id': 2, 'name': 'hanna', 'age': 30},
]
pd.DataFrame(L).drop_duplicates().to_dict('r')
Out[295]:
[{'age': 34, 'id': 1, 'name': 'john'},
{'age': 34, 'id': 1, 'name': 'peter'},# here will still keeping the dict in the out put
{'age': 30, 'id': 2, 'name': 'hanna'}]
对象可以放入集合中。您可以使用对象而不是字典,如果需要,在所有set插入后转换回字典列表。例子
class Person:
def __init__(self, id, age, name):
self.id = id
self.age = age
self.name = name
my_set = {Person(id=2, age=3, name='Jhon')}
my_set.add(Person(id=3, age=34, name='Guy'))
my_set.add({Person(id=2, age=3, name='Jhon')})
# if needed convert to list of dicts
list_of_dict = [{'id': obj.id,
'name': obj.name,
'age': obj.age} for obj in my_set]