是否有一种方法可以方便地在Python中定义类c结构?我厌倦了写这样的东西:
class MyStruct():
def __init__(self, field1, field2, field3):
self.field1 = field1
self.field2 = field2
self.field3 = field3
是否有一种方法可以方便地在Python中定义类c结构?我厌倦了写这样的东西:
class MyStruct():
def __init__(self, field1, field2, field3):
self.field1 = field1
self.field2 = field2
self.field3 = field3
当前回答
https://stackoverflow.com/a/32448434/159695在Python3中不起作用。
https://stackoverflow.com/a/35993/159695在Python3中工作。
然后我扩展它来添加默认值。
class myStruct:
def __init__(self, **kwds):
self.x=0
self.__dict__.update(kwds) # Must be last to accept assigned member variable.
def __repr__(self):
args = ['%s=%s' % (k, repr(v)) for (k,v) in vars(self).items()]
return '%s(%s)' % ( self.__class__.__qualname__, ', '.join(args) )
a=myStruct()
b=myStruct(x=3,y='test')
c=myStruct(x='str')
>>> a
myStruct(x=0)
>>> b
myStruct(x=3, y='test')
>>> c
myStruct(x='str')
其他回答
我认为Python结构字典适合这个需求。
d = dict{}
d[field1] = field1
d[field2] = field2
d[field2] = field3
使用命名元组,该元组被添加到Python 2.6标准库中的collections模块中。如果你需要支持Python 2.4,也可以使用Raymond Hettinger的命名元组配方。
它适用于基本示例,但也适用于稍后可能遇到的一些边缘情况。你上面的片段可以写成:
from collections import namedtuple
MyStruct = namedtuple("MyStruct", "field1 field2 field3")
新创建的类型可以这样使用:
m = MyStruct("foo", "bar", "baz")
你也可以使用命名参数:
m = MyStruct(field1="foo", field2="bar", field3="baz")
也许你正在寻找没有构造函数的struct:
class Sample:
name = ''
average = 0.0
values = None # list cannot be initialized here!
s1 = Sample()
s1.name = "sample 1"
s1.values = []
s1.values.append(1)
s1.values.append(2)
s1.values.append(3)
s2 = Sample()
s2.name = "sample 2"
s2.values = []
s2.values.append(4)
for v in s1.values: # prints 1,2,3 --> OK.
print v
print "***"
for v in s2.values: # prints 4 --> OK.
print v
NamedTuple很舒服。但是没有人共享性能和存储。
from typing import NamedTuple
import guppy # pip install guppy
import timeit
class User:
def __init__(self, name: str, uid: int):
self.name = name
self.uid = uid
class UserSlot:
__slots__ = ('name', 'uid')
def __init__(self, name: str, uid: int):
self.name = name
self.uid = uid
class UserTuple(NamedTuple):
# __slots__ = () # AttributeError: Cannot overwrite NamedTuple attribute __slots__
name: str
uid: int
def get_fn(obj, attr_name: str):
def get():
getattr(obj, attr_name)
return get
if 'memory test':
obj = [User('Carson', 1) for _ in range(1000000)] # Cumulative: 189138883
obj_slot = [UserSlot('Carson', 1) for _ in range(1000000)] # 77718299 <-- winner
obj_namedtuple = [UserTuple('Carson', 1) for _ in range(1000000)] # 85718297
print(guppy.hpy().heap()) # Run this function individually.
"""
Index Count % Size % Cumulative % Kind (class / dict of class)
0 1000000 24 112000000 34 112000000 34 dict of __main__.User
1 1000000 24 64000000 19 176000000 53 __main__.UserTuple
2 1000000 24 56000000 17 232000000 70 __main__.User
3 1000000 24 56000000 17 288000000 87 __main__.UserSlot
...
"""
if 'performance test':
obj = User('Carson', 1)
obj_slot = UserSlot('Carson', 1)
obj_tuple = UserTuple('Carson', 1)
time_normal = min(timeit.repeat(get_fn(obj, 'name'), repeat=20))
print(time_normal) # 0.12550550000000005
time_slot = min(timeit.repeat(get_fn(obj_slot, 'name'), repeat=20))
print(time_slot) # 0.1368690000000008
time_tuple = min(timeit.repeat(get_fn(obj_tuple, 'name'), repeat=20))
print(time_tuple) # 0.16006120000000124
print(time_tuple/time_slot) # 1.1694481584580898 # The slot is almost 17% faster than NamedTuple on Windows. (Python 3.7.7)
如果你的__dict__没有被使用,请在__slots__(更高的性能和存储)和NamedTuple(清晰的阅读和使用)之间选择。
您可以查看此链接(插槽的使用 )来获取更多的__slots__信息。
一本字典怎么样?
就像这样:
myStruct = {'field1': 'some val', 'field2': 'some val'}
然后你可以使用这个来操作值:
print myStruct['field1']
myStruct['field2'] = 'some other values'
值不一定是字符串。它们可以是其他任何物体。