问题是如何将JavaScript Date格式化为一个字符串,声明时间经过,类似于您在Stack Overflow上看到的时间显示方式。
e.g.
1分钟前 1小时前 1天前 1个月前 一年前
问题是如何将JavaScript Date格式化为一个字符串,声明时间经过,类似于您在Stack Overflow上看到的时间显示方式。
e.g.
1分钟前 1小时前 1天前 1个月前 一年前
当前回答
回答10年的老问题,帮助新人。
我们可以将这个包用于javascript时间之前
// Load locale-specific relative date/time formatting rules.
import en from 'javascript-time-ago/locale/en'
// Add locale-specific relative date/time formatting rules.
TimeAgo.addLocale(en)
// Create relative date/time formatter.
const timeAgo = new TimeAgo('en-US')
timeAgo.format(new Date())
// "just now"
timeAgo.format(Date.now() - 60 * 1000)
// "a minute ago"
timeAgo.format(Date.now() - 2 * 60 * 60 * 1000)
// "2 hours ago"
timeAgo.format(Date.now() - 24 * 60 * 60 * 1000)
// "a day ago"
其他回答
我修改了Sky Sanders的版本。Math.floor(…)操作在if块中计算
var timeSince = function(date) {
var seconds = Math.floor((new Date() - date) / 1000);
var months = ["January", "February", "March", "April", "May", "June", "July", "August", "September", "October", "November", "December"];
if (seconds < 5){
return "just now";
}else if (seconds < 60){
return seconds + " seconds ago";
}
else if (seconds < 3600) {
minutes = Math.floor(seconds/60)
if(minutes > 1)
return minutes + " minutes ago";
else
return "1 minute ago";
}
else if (seconds < 86400) {
hours = Math.floor(seconds/3600)
if(hours > 1)
return hours + " hours ago";
else
return "1 hour ago";
}
//2 days and no more
else if (seconds < 172800) {
days = Math.floor(seconds/86400)
if(days > 1)
return days + " days ago";
else
return "1 day ago";
}
else{
//return new Date(time).toLocaleDateString();
return date.getDate().toString() + " " + months[date.getMonth()] + ", " + date.getFullYear();
}
}
将上面的函数更改为
function timeSince(date) {
var seconds = Math.floor(((new Date().getTime()/1000) - date)),
interval = Math.floor(seconds / 31536000);
if (interval > 1) return interval + "y";
interval = Math.floor(seconds / 2592000);
if (interval > 1) return interval + "m";
interval = Math.floor(seconds / 86400);
if (interval >= 1) return interval + "d";
interval = Math.floor(seconds / 3600);
if (interval >= 1) return interval + "h";
interval = Math.floor(seconds / 60);
if (interval > 1) return interval + "m ";
return Math.floor(seconds) + "s";
}
否则它会显示“75分钟”(介于1到2小时之间)。它现在还假定输入日期是Unix时间戳。
回答10年的老问题,帮助新人。
我们可以将这个包用于javascript时间之前
// Load locale-specific relative date/time formatting rules.
import en from 'javascript-time-ago/locale/en'
// Add locale-specific relative date/time formatting rules.
TimeAgo.addLocale(en)
// Create relative date/time formatter.
const timeAgo = new TimeAgo('en-US')
timeAgo.format(new Date())
// "just now"
timeAgo.format(Date.now() - 60 * 1000)
// "a minute ago"
timeAgo.format(Date.now() - 2 * 60 * 60 * 1000)
// "2 hours ago"
timeAgo.format(Date.now() - 24 * 60 * 60 * 1000)
// "a day ago"
function dateToHowManyAgo(stringDate){
var currDate = new Date();
var diffMs=currDate.getTime() - new Date(stringDate).getTime();
var sec=diffMs/1000;
if(sec<60)
return parseInt(sec)+' second'+(parseInt(sec)>1?'s':'')+' ago';
var min=sec/60;
if(min<60)
return parseInt(min)+' minute'+(parseInt(min)>1?'s':'')+' ago';
var h=min/60;
if(h<24)
return parseInt(h)+' hour'+(parseInt(h)>1?'s':'')+' ago';
var d=h/24;
if(d<30)
return parseInt(d)+' day'+(parseInt(d)>1?'s':'')+' ago';
var m=d/30;
if(m<12)
return parseInt(m)+' month'+(parseInt(m)>1?'s':'')+' ago';
var y=m/12;
return parseInt(y)+' year'+(parseInt(y)>1?'s':'')+' ago';
}
console.log(dateToHowManyAgo('2019-11-07 19:17:06'));
I achieve this by following method
timeAgo = (date) => {
var ms = (new Date()).getTime() - date.getTime();
var seconds = Math.floor(ms / 1000);
var minutes = Math.floor(seconds / 60);
var hours = Math.floor(minutes / 60);
var days = Math.floor(hours / 24);
var months = Math.floor(days / 30);
var years = Math.floor(months / 12);
if (ms === 0) {
return 'Just now';
} if (seconds < 60) {
return seconds + ' seconds Ago';
} if (minutes < 60) {
return minutes + ' minutes Ago';
} if (hours < 24) {
return hours + ' hours Ago';
} if (days < 30) {
return days + ' days Ago';
} if (months < 12) {
return months + ' months Ago';
} else {
return years + ' years Ago';
}
}
console.log(timeAgo(new Date()));
console.log(timeAgo(new Date('Jun 27 2020 10:12:19')));
console.log(timeAgo(new Date('Jun 27 2020 00:12:19')));
console.log(timeAgo(new Date('May 28 2020 13:12:19')));
console.log(timeAgo(new Date('May 28 2017 13:12:19')));