根据Stacktrace

Exception in thread "main" java.lang.NullPointerException
at java.util.HashMap.merge(HashMap.java:1216)
at java.util.stream.Collectors.lambda$toMap$148(Collectors.java:1320)
at java.util.stream.Collectors$$Lambda$5/391359742.accept(Unknown Source)
at java.util.stream.ReduceOps$3ReducingSink.accept(ReduceOps.java:169)
at java.util.ArrayList$ArrayListSpliterator.forEachRemaining(ArrayList.java:1359)
at java.util.stream.AbstractPipeline.copyInto(AbstractPipeline.java:512)
at java.util.stream.AbstractPipeline.wrapAndCopyInto(AbstractPipeline.java:502)
at java.util.stream.ReduceOps$ReduceOp.evaluateSequential(ReduceOps.java:708)
at java.util.stream.AbstractPipeline.evaluate(AbstractPipeline.java:234)
at java.util.stream.ReferencePipeline.collect(ReferencePipeline.java:499)
at com.guice.Main.main(Main.java:28)
at sun.reflect.NativeMethodAccessorImpl.invoke0(Native Method)
at sun.reflect.NativeMethodAccessorImpl.invoke(NativeMethodAccessorImpl.java:62)
at sun.reflect.DelegatingMethodAccessorImpl.invoke(DelegatingMethodAccessorImpl.java:43)
at java.lang.reflect.Method.invoke(Method.java:483)
at com.intellij.rt.execution.application.AppMain.main(AppMain.java:134)

什么时候叫做map。merge

        BiConsumer<M, T> accumulator
            = (map, element) -> map.merge(keyMapper.apply(element),
                                          valueMapper.apply(element), mergeFunction);

它首先会做一个空检查

if (value == null)
    throw new NullPointerException();

我不经常使用Java 8，所以我不知道是否有更好的方法来修复它，但修复它有点困难。

你可以这样做:

使用过滤器过滤所有的NULL值，并在Javascript代码中检查服务器是否没有为这个id发送任何答案，这意味着他没有回复它。

就像这样:

Map<Integer, Boolean> answerMap =
        answerList
                .stream()
                .filter((a) -> a.getAnswer() != null)
                .collect(Collectors.toMap(Answer::getId, Answer::getAnswer));

或者使用peek，它用来改变流元素的元素。使用peek你可以将答案更改为更适合map的东西，但这意味着编辑你的逻辑。

听起来，如果你想保持当前的设计，你应该避免使用collections . tomap

保留所有问题id与小调整

Map<Integer, Boolean> answerMap = 
  answerList.stream()
            .collect(Collectors.toMap(Answer::getId, a -> 
                       Boolean.TRUE.equals(a.getAnswer())));

如果值是一个字符串，那么这可能会起作用: .stream map.entrySet () () .collect(收藏者。toMap(e -> e.getKey()， e -> Optional.ofNullable(e.getValue()).orElse(""))))

我写了一个Collector，不像默认的java，当你有空值时不会崩溃:

public static <T, K, U>
        Collector<T, ?, Map<K, U>> toMap(Function<? super T, ? extends K> keyMapper,
                Function<? super T, ? extends U> valueMapper) {
    return Collectors.collectingAndThen(
            Collectors.toList(),
            list -> {
                Map<K, U> result = new HashMap<>();
                for (T item : list) {
                    K key = keyMapper.apply(item);
                    if (result.putIfAbsent(key, valueMapper.apply(item)) != null) {
                        throw new IllegalStateException(String.format("Duplicate key %s", key));
                    }
                }
                return result;
            });
}

只需将collections . tomap()调用替换为对该函数的调用，它就会解决这个问题。

public static <T, K, V> Collector<T, HashMap<K, V>, HashMap<K, V>> toHashMap(
        Function<? super T, ? extends K> keyMapper,
        Function<? super T, ? extends V> valueMapper
)
{
    return Collector.of(
            HashMap::new,
            (map, t) -> map.put(keyMapper.apply(t), valueMapper.apply(t)),
            (map1, map2) -> {
                map1.putAll(map2);
                return map1;
            }
    );
}

public static <T, K> Collector<T, HashMap<K, T>, HashMap<K, T>> toHashMap(
        Function<? super T, ? extends K> keyMapper
)
{
    return toHashMap(keyMapper, Function.identity());
}

为了完整起见，我发布了一个带有mergeFunction参数的toMapOfNullables版本:

public static <T, K, U> Collector<T, ?, Map<K, U>> toMapOfNullables(Function<? super T, ? extends K> keyMapper, Function<? super T, ? extends U> valueMapper, BinaryOperator<U> mergeFunction) {
    return Collectors.collectingAndThen(Collectors.toList(), list -> {
        Map<K, U> result = new HashMap<>();
        for(T item : list) {
            K key = keyMapper.apply(item);
            U newValue = valueMapper.apply(item);
            U value = result.containsKey(key) ? mergeFunction.apply(result.get(key), newValue) : newValue;
            result.put(key, value);
        }
        return result;
    });
}