在Java中将列表转换为集的最简单的方法是什么?


当前回答

使用java 8你可以使用stream:

List<Integer> mylist = Arrays.asList(100, 101, 102);
Set<Integer> myset = mylist.stream().collect(Collectors.toSet()));

其他回答

Set<E> alphaSet  = new HashSet<E>(<your List>);

或者完整的例子

import java.util.ArrayList;
import java.util.HashSet;
import java.util.List;
import java.util.Set;

public class ListToSet
{
    public static void main(String[] args)
    {
        List<String> alphaList = new ArrayList<String>();
        alphaList.add("A");
        alphaList.add("B");
        alphaList.add("C");
        alphaList.add("A");
        alphaList.add("B");
        System.out.println("List values .....");
        for (String alpha : alphaList)
        {
            System.out.println(alpha);
        }
        Set<String> alphaSet = new HashSet<String>(alphaList);
        System.out.println("\nSet values .....");
        for (String alpha : alphaSet)
        {
            System.out.println(alpha);
        }
    }
}

请记住,从List转换到Set将从集合中删除重复项,因为List支持重复项,而Set在Java中不支持重复项。

直接转换:将List转换为Set的最常见和最简单的方法

// Creating a list of strings
List<String> list = Arrays.asList("One", "Two", "Three", "Four");

// Converting a list to set
Set<String> set = new HashSet<>(list);

Apache Commons Collections:你也可以使用Commons Collections API将一个List转换为一个Set

// Creating a list of strings
List<String> list = Arrays.asList("One", "Two", "Three", "Four");

// Creating a set with the same number of members in the list 
Set<String> set = new HashSet<>(4);

// Adds all of the elements in the list to the target set
CollectionUtils.addAll(set, list);

使用流:另一种方法是将给定的列表转换为流,然后将流转换为集:-

// Creating a list of strings 
List<String> list = Arrays.asList("One", "Two", "Three", "Four"); 

// Converting to set using stream 
Set<String> set = list.stream().collect(Collectors.toSet()); 

可以将List<>转换为Set<>

Set<T> set=new HashSet<T>();

//Added dependency -> If list is null then it will throw NullPointerExcetion.

Set<T> set;
if(list != null){
    set = new HashSet<T>(list);
}
Set<Foo> foo = new HashSet<Foo>(myList);

在Java 1.8中,流API可用于将列表转换为集合。例如,下面的代码显示了一个列表到一个集合的转换:

List<String> empList = Arrays.asList("java", "python", ".net", "javaScript", "php");
Set<String> set = empList.stream().collect(Collectors.toSet());
set.forEach(value -> System.out.printf("%s ", value));

如果列表包含对象,我想创建一个集合:

List<Employee> empList = Arrays.asList(new Employee(1, 1000, "Chandra Shekhar", 6000),
new Employee(2, 1000, "Rajesh", 8000), new Employee(3, 1004, "Rahul", 9000),
new Employee(4, 1001, "Suresh", 12000), new Employee(5, 1004, "Satosh", 7000));

Set<String> set = empList.stream().map(emp -> emp.getName()).collect(Collectors.toSet());
System.out.println(set);