我如何写一个列表文件?writelines()不插入换行符,所以我需要这样做:

f.writelines([f"{line}\n" for line in lines])

当前回答

因为我很懒....

import json
a = [1,2,3]
with open('test.txt', 'w') as f:
    f.write(json.dumps(a))

#Now read the file back into a Python list object
with open('test.txt', 'r') as f:
    a = json.loads(f.read())

其他回答

设avg为列表,则:

In [29]: a = n.array((avg))
In [31]: a.tofile('avgpoints.dat',sep='\n',dtype = '%f')

您可以根据自己的需求使用%e或%s。

因为我很懒....

import json
a = [1,2,3]
with open('test.txt', 'w') as f:
    f.write(json.dumps(a))

#Now read the file back into a Python list object
with open('test.txt', 'r') as f:
    a = json.loads(f.read())

简单:

with open("text.txt", 'w') as file:
    file.write('\n'.join(yourList))

你还可以通过以下步骤:

例子:

my_list=[1,2,3,4,5,"abc","def"]
with open('your_file.txt', 'w') as file:
    for item in my_list:
        file.write("%s\n" % item)

输出:

在your_file.txt中,项目的保存方式如下:

1

2

3

4

5

abc

def

您的脚本也按上述方式保存。

否则,你可以用泡菜

import pickle
my_list=[1,2,3,4,5,"abc","def"]
#to write
with open('your_file.txt', 'wb') as file:
    pickle.dump(my_list, file)
#to read
with open ('your_file.txt', 'rb') as file:
    Outlist = pickle.load(file)
print(Outlist)

输出: [1,2,3,4,5, 'abc', 'def']

它保存转储列表,就像一个列表,当我们加载它时,我们能够读取。

同样由simplejson可能输出与上面相同的结果

import simplejson as sj
my_list=[1,2,3,4,5,"abc","def"]
#To write
with open('your_file.txt', 'w') as file:
    sj.dump(my_list, file)

#To save
with open('your_file.txt', 'r') as file:
    mlist=sj.load(file)
print(mlist)

在一般情况下

下面是writelines()方法的语法

fileObject.writelines( sequence )

例子

#!/usr/bin/python

# Open a file
fo = open("foo.txt", "rw+")
seq = ["This is 6th line\n", "This is 7th line"]

# Write sequence of lines at the end of the file.
line = fo.writelines( seq )

# Close opend file
fo.close()

参考

http://www.tutorialspoint.com/python/file_writelines.htm