我如何写一个列表文件?writelines()不插入换行符,所以我需要这样做:
f.writelines([f"{line}\n" for line in lines])
我如何写一个列表文件?writelines()不插入换行符,所以我需要这样做:
f.writelines([f"{line}\n" for line in lines])
当前回答
另一种迭代和添加换行符的方法:
for item in items:
filewriter.write(f"{item}" + "\n")
其他回答
with open ("test.txt","w")as fp:
for line in list12:
fp.write(line+"\n")
你为什么不试试
file.write(str(list))
你还可以通过以下步骤:
例子:
my_list=[1,2,3,4,5,"abc","def"]
with open('your_file.txt', 'w') as file:
for item in my_list:
file.write("%s\n" % item)
输出:
在your_file.txt中,项目的保存方式如下:
1
2
3
4
5
abc
def
您的脚本也按上述方式保存。
否则,你可以用泡菜
import pickle
my_list=[1,2,3,4,5,"abc","def"]
#to write
with open('your_file.txt', 'wb') as file:
pickle.dump(my_list, file)
#to read
with open ('your_file.txt', 'rb') as file:
Outlist = pickle.load(file)
print(Outlist)
输出: [1,2,3,4,5, 'abc', 'def']
它保存转储列表,就像一个列表,当我们加载它时,我们能够读取。
同样由simplejson可能输出与上面相同的结果
import simplejson as sj
my_list=[1,2,3,4,5,"abc","def"]
#To write
with open('your_file.txt', 'w') as file:
sj.dump(my_list, file)
#To save
with open('your_file.txt', 'r') as file:
mlist=sj.load(file)
print(mlist)
这个逻辑首先将list中的项转换为字符串(str)。有时列表包含一个元组,如
alist = [(i12,tiger),
(113,lion)]
这个逻辑将把每个元组写入一个新行。我们可以在读取文件时加载每个元组时使用eval:
outfile = open('outfile.txt', 'w') # open a file in write mode
for item in list_to_persistence: # iterate over the list items
outfile.write(str(item) + '\n') # write to the file
outfile.close() # close the file
简单:
with open("text.txt", 'w') as file:
file.write('\n'.join(yourList))