我如何写一个列表文件?writelines()不插入换行符,所以我需要这样做:

f.writelines([f"{line}\n" for line in lines])

当前回答

with open ("test.txt","w")as fp:
   for line in list12:
       fp.write(line+"\n")

其他回答

另一种迭代和添加换行符的方法:

for item in items:
    filewriter.write(f"{item}" + "\n")

你还可以通过以下步骤:

例子:

my_list=[1,2,3,4,5,"abc","def"]
with open('your_file.txt', 'w') as file:
    for item in my_list:
        file.write("%s\n" % item)

输出:

在your_file.txt中,项目的保存方式如下:

1

2

3

4

5

abc

def

您的脚本也按上述方式保存。

否则,你可以用泡菜

import pickle
my_list=[1,2,3,4,5,"abc","def"]
#to write
with open('your_file.txt', 'wb') as file:
    pickle.dump(my_list, file)
#to read
with open ('your_file.txt', 'rb') as file:
    Outlist = pickle.load(file)
print(Outlist)

输出: [1,2,3,4,5, 'abc', 'def']

它保存转储列表,就像一个列表,当我们加载它时,我们能够读取。

同样由simplejson可能输出与上面相同的结果

import simplejson as sj
my_list=[1,2,3,4,5,"abc","def"]
#To write
with open('your_file.txt', 'w') as file:
    sj.dump(my_list, file)

#To save
with open('your_file.txt', 'r') as file:
    mlist=sj.load(file)
print(mlist)
with open ("test.txt","w")as fp:
   for line in list12:
       fp.write(line+"\n")

使用循环:

with open('your_file.txt', 'w') as f:
    for line in lines:
        f.write(f"{line}\n")

对于Python <3.6:

with open('your_file.txt', 'w') as f:
    for line in lines:
        f.write("%s\n" % line)

对于Python 2,还可以使用:

with open('your_file.txt', 'w') as f:
    for line in lines:
        print >> f, line

如果您热衷于单个函数调用,至少要删除方括号[],以便每次生成一个要打印的字符串(genexp而不是listcomp)——没有理由占用物化整个字符串列表所需的所有内存。

使用Python 3和Python 2.6+语法:

with open(filepath, 'w') as file_handler:
    for item in the_list:
        file_handler.write("{}\n".format(item))

这是平台独立的。它还使用换行符结束最后一行,这是UNIX的最佳实践。

从Python 3.6开始,"{}\n".format(item)可以用f-string替换:f"{item}\n"。