我如何写一个列表文件?writelines()不插入换行符,所以我需要这样做:

f.writelines([f"{line}\n" for line in lines])

当前回答

我想你在寻找这样的答案。

f = open('output.txt','w')
list = [3, 15.2123, 118.3432, 98.2276, 118.0043]
f.write('a= {:>3d}, b= {:>8.4f}, c= {:>8.4f}, d= {:>8.4f}, e= 
{:>8.4f}\n'.format(*list))
f.close()

其他回答

在一般情况下

下面是writelines()方法的语法

fileObject.writelines( sequence )

例子

#!/usr/bin/python

# Open a file
fo = open("foo.txt", "rw+")
seq = ["This is 6th line\n", "This is 7th line"]

# Write sequence of lines at the end of the file.
line = fo.writelines( seq )

# Close opend file
fo.close()

参考

http://www.tutorialspoint.com/python/file_writelines.htm

序列化列表到文本文件与逗号分隔值

mylist = dir()
with open('filename.txt','w') as f:
    f.write( ','.join( mylist ) )
file.write('\n'.join(list))

你为什么不试试

file.write(str(list))

在Python 3中,你可以使用print和*进行参数解包:

with open("fout.txt", "w") as fout:
    print(*my_list, sep="\n", file=fout)