它并不完美，但我用c#写了这个帮助程序:

using System;
using System.Collections.Generic;
using System.Threading;
using System.Threading.Tasks;

namespace Proto.Promises.Tests.Threading
{
    public class ThreadHelper
    {
        public static readonly int multiThreadCount = Environment.ProcessorCount * 100;
        private static readonly int[] offsets = new int[] { 0, 10, 100, 1000 };

        private readonly Stack<Task> _executingTasks = new Stack<Task>(multiThreadCount);
        private readonly Barrier _barrier = new Barrier(1);
        private int _currentParticipants = 0;
        private readonly TimeSpan _timeout;

        public ThreadHelper() : this(TimeSpan.FromSeconds(10)) { } // 10 second timeout should be enough for most cases.

        public ThreadHelper(TimeSpan timeout)
        {
            _timeout = timeout;
        }

        /// <summary>
        /// Execute the action multiple times in parallel threads.
        /// </summary>
        public void ExecuteMultiActionParallel(Action action)
        {
            for (int i = 0; i < multiThreadCount; ++i)
            {
                AddParallelAction(action);
            }
            ExecutePendingParallelActions();
        }

        /// <summary>
        /// Execute the action once in a separate thread.
        /// </summary>
        public void ExecuteSingleAction(Action action)
        {
            AddParallelAction(action);
            ExecutePendingParallelActions();
        }

        /// <summary>
        /// Add an action to be run in parallel.
        /// </summary>
        public void AddParallelAction(Action action)
        {
            var taskSource = new TaskCompletionSource<bool>();
            lock (_executingTasks)
            {
                ++_currentParticipants;
                _barrier.AddParticipant();
                _executingTasks.Push(taskSource.Task);
            }
            new Thread(() =>
            {
                try
                {
                    _barrier.SignalAndWait(); // Try to make actions run in lock-step to increase likelihood of breaking race conditions.
                    action.Invoke();
                    taskSource.SetResult(true);
                }
                catch (Exception e)
                {
                    taskSource.SetException(e);
                }
            }).Start();
        }

        /// <summary>
        /// Runs the pending actions in parallel, attempting to run them in lock-step.
        /// </summary>
        public void ExecutePendingParallelActions()
        {
            Task[] tasks;
            lock (_executingTasks)
            {
                _barrier.SignalAndWait();
                _barrier.RemoveParticipants(_currentParticipants);
                _currentParticipants = 0;
                tasks = _executingTasks.ToArray();
                _executingTasks.Clear();
            }
            try
            {
                if (!Task.WaitAll(tasks, _timeout))
                {
                    throw new TimeoutException($"Action(s) timed out after {_timeout}, there may be a deadlock.");
                }
            }
            catch (AggregateException e)
            {
                // Only throw one exception instead of aggregate to try to avoid overloading the test error output.
                throw e.Flatten().InnerException;
            }
        }

        /// <summary>
        /// Run each action in parallel multiple times with differing offsets for each run.
        /// <para/>The number of runs is 4^actions.Length, so be careful if you don't want the test to run too long.
        /// </summary>
        /// <param name="expandToProcessorCount">If true, copies each action on additional threads up to the processor count. This can help test more without increasing the time it takes to complete.
        /// <para/>Example: 2 actions with 6 processors, runs each action 3 times in parallel.</param>
        /// <param name="setup">The action to run before each parallel run.</param>
        /// <param name="teardown">The action to run after each parallel run.</param>
        /// <param name="actions">The actions to run in parallel.</param>
        public void ExecuteParallelActionsWithOffsets(bool expandToProcessorCount, Action setup, Action teardown, params Action[] actions)
        {
            setup += () => { };
            teardown += () => { };
            int actionCount = actions.Length;
            int expandCount = expandToProcessorCount ? Math.Max(Environment.ProcessorCount / actionCount, 1) : 1;
            foreach (var combo in GenerateCombinations(offsets, actionCount))
            {
                setup.Invoke();
                for (int k = 0; k < expandCount; ++k)
                {
                    for (int i = 0; i < actionCount; ++i)
                    {
                        int offset = combo[i];
                        Action action = actions[i];
                        AddParallelAction(() =>
                        {
                            for (int j = offset; j > 0; --j) { } // Just spin in a loop for the offset.
                            action.Invoke();
                        });
                    }
                }
                ExecutePendingParallelActions();
                teardown.Invoke();
            }
        }

        // Input: [1, 2, 3], 3
        // Ouput: [
        //          [1, 1, 1],
        //          [2, 1, 1],
        //          [3, 1, 1],
        //          [1, 2, 1],
        //          [2, 2, 1],
        //          [3, 2, 1],
        //          [1, 3, 1],
        //          [2, 3, 1],
        //          [3, 3, 1],
        //          [1, 1, 2],
        //          [2, 1, 2],
        //          [3, 1, 2],
        //          [1, 2, 2],
        //          [2, 2, 2],
        //          [3, 2, 2],
        //          [1, 3, 2],
        //          [2, 3, 2],
        //          [3, 3, 2],
        //          [1, 1, 3],
        //          [2, 1, 3],
        //          [3, 1, 3],
        //          [1, 2, 3],
        //          [2, 2, 3],
        //          [3, 2, 3],
        //          [1, 3, 3],
        //          [2, 3, 3],
        //          [3, 3, 3]
        //        ]
        private static IEnumerable<int[]> GenerateCombinations(int[] options, int count)
        {
            int[] indexTracker = new int[count];
            int[] combo = new int[count];
            for (int i = 0; i < count; ++i)
            {
                combo[i] = options[0];
            }
            // Same algorithm as picking a combination lock.
            int rollovers = 0;
            while (rollovers < count)
            {
                yield return combo; // No need to duplicate the array since we're just reading it.
                for (int i = 0; i < count; ++i)
                {
                    int index = ++indexTracker[i];
                    if (index == options.Length)
                    {
                        indexTracker[i] = 0;
                        combo[i] = options[0];
                        if (i == rollovers)
                        {
                            ++rollovers;
                        }
                    }
                    else
                    {
                        combo[i] = options[index];
                        break;
                    }
                }
            }
        }
    }
}

使用示例:

[Test]
public void DeferredMayBeBeResolvedAndPromiseAwaitedConcurrently_void0()
{
    Promise.Deferred deferred = default(Promise.Deferred);
    Promise promise = default(Promise);

    int invokedCount = 0;

    var threadHelper = new ThreadHelper();
    threadHelper.ExecuteParallelActionsWithOffsets(false,
        // Setup
        () =>
        {
            invokedCount = 0;
            deferred = Promise.NewDeferred();
            promise = deferred.Promise;
        },
        // Teardown
        () => Assert.AreEqual(1, invokedCount),
        // Parallel Actions
        () => deferred.Resolve(),
        () => promise.Then(() => { Interlocked.Increment(ref invokedCount); }).Forget()
    );
}

听着，要做到这一点并不容易。我正在做一个本来就是多线程的项目。事件来自操作系统，我必须并发地处理它们。

处理测试复杂的多线程应用程序代码的最简单方法是:如果它太复杂而无法测试，那么您做错了。如果您有一个单独的实例，其中有多个线程作用于它，并且您无法测试这些线程相互踩在一起的情况，那么您的设计需要重做。它既简单又复杂。

有许多方法可以为多线程编程，以避免线程同时通过实例运行。最简单的方法是使所有对象都是不可变的。当然，这通常是不可能的。因此，您必须在设计中确定线程与同一实例交互的地方，并减少这些地方的数量。通过这样做，您可以隔离多线程实际发生的几个类，从而降低测试系统的总体复杂性。

但是您必须意识到，即使这样做，您仍然不能测试两个线程相互践踏的每一种情况。要做到这一点，您必须在同一个测试中并发地运行两个线程，然后准确地控制它们在任何给定时刻执行的行。你能做的就是模拟这种情况。但这可能需要您专门为测试编写代码，这充其量是迈向真正解决方案的半步。

测试代码是否存在线程问题的最好方法可能是对代码进行静态分析。如果您的线程代码没有遵循有限的线程安全模式集，那么您可能会遇到问题。我相信VS中的代码分析确实包含了一些线程的知识，但可能不多。

看，就目前的情况来看(可能还会持续很长一段时间)，测试多线程应用程序的最佳方法是尽可能降低线程代码的复杂性。最小化线程交互的区域，尽可能地进行测试，并使用代码分析来识别危险区域。

(如果可能的话)不要使用线程，使用actor /活动对象。易于测试。

Testing MT code for correctness is, as already stated, quite a hard problem. In the end it boils down to ensuring that there are no incorrectly synchronised data races in your code. The problem with this is that there are infinitely many possibilities of thread execution (interleavings) over which you do not have much control (be sure to read this article, though). In simple scenarios it might be possible to actually prove correctness by reasoning but this is usually not the case. Especially if you want to avoid/minimize synchronization and not go for the most obvious/easiest synchronization option.

我遵循的一种方法是编写高度并发的测试代码，以使潜在的未检测到的数据竞争有可能发生。然后我运行这些测试一段时间:)我曾经无意中看到一个演讲，一些计算机科学家展示了一个这样做的工具(根据规格随机设计测试，然后疯狂地运行它们，同时检查定义的不变量是否被破坏)。

顺便说一下，我认为测试MT代码的这一方面在这里还没有提到:确定可以随机检查的代码不变量。不幸的是，找到这些不变量也是一个相当困难的问题。此外，它们在执行期间可能不会一直保持，因此您必须找到/强制执行可以期望它们为真的执行点。将代码执行到这样的状态也是一个难题(并且本身可能会引起并发性问题)。呼，这太难了!

一些有趣的链接可供阅读:

确定性交错:允许强制执行某些线程交错，然后检查不变量的框架 jMock Blitzer:压力测试同步 assertConcurrent:压力测试同步的JUnit版本 测试并发代码:简要介绍两种主要方法:蛮力(压力测试)或确定性(使用不变量)

对于Java，请参阅JCIP的第12章。有一些具体的例子，可以编写确定性的多线程单元测试，以至少测试并发代码的正确性和不变量。

用单元测试“证明”线程安全要危险得多。我相信在各种平台/配置上进行自动化集成测试会更好。

您可以使用EasyMock。使测试实例线程安全