在SQL Server中,可以使用insert将行插入到表中。。SELECT语句:

INSERT INTO Table (col1, col2, col3)
SELECT col1, col2, col3 
FROM other_table 
WHERE sql = 'cool'

是否也可以使用SELECT更新表?我有一个包含这些值的临时表,并希望使用这些值更新另一个表。也许是这样的:

UPDATE Table SET col1, col2
SELECT col1, col2 
FROM other_table 
WHERE sql = 'cool'
WHERE Table.id = other_table.id

当前回答

Use:

drop table uno
drop table dos

create table uno
(
    uid int,
    col1 char(1),
    col2 char(2)
)
create table dos
(
    did int,
    col1 char(1),
    col2 char(2),
    [sql] char(4)
)
insert into uno(uid) values (1)
insert into uno(uid) values (2)
insert into dos values (1,'a','b',null)
insert into dos values (2,'c','d','cool')

select * from uno 
select * from dos

或者:

update uno set col1 = (select col1 from dos where uid = did and [sql]='cool'), 
col2 = (select col2 from dos where uid = did and [sql]='cool')

OR:

update uno set col1=d.col1,col2=d.col2 from uno 
inner join dos d on uid=did where [sql]='cool'

select * from uno 
select * from dos

如果两个表中的ID列名相同,则只需将表名放在要更新的表之前,并为所选表使用别名,即:

update uno set col1 = (select col1 from dos d where uno.[id] = d.[id] and [sql]='cool'),
col2  = (select col2 from dos d where uno.[id] = d.[id] and [sql]='cool')

其他回答

UPDATE TQ
SET TQ.IsProcessed = 1, TQ.TextName = 'bla bla bla'
FROM TableQueue TQ
INNER JOIN TableComment TC ON TC.ID = TQ.TCID
WHERE TQ.IsProcessed = 0

要确保正在更新所需内容,请先选择

SELECT TQ.IsProcessed, 1 AS NewValue1, TQ.TextName, 'bla bla bla' AS NewValue2
FROM TableQueue TQ
INNER JOIN TableComment TC ON TC.ID = TQ.TCID
WHERE TQ.IsProcessed = 0

在SQL Server 2008(或更高版本)中,使用MERGE

MERGE INTO YourTable T
   USING other_table S 
      ON T.id = S.id
         AND S.tsql = 'cool'
WHEN MATCHED THEN
   UPDATE 
      SET col1 = S.col1, 
          col2 = S.col2;

或者:

MERGE INTO YourTable T
   USING (
          SELECT id, col1, col2 
            FROM other_table 
           WHERE tsql = 'cool'
         ) S
      ON T.id = S.id
WHEN MATCHED THEN
   UPDATE 
      SET col1 = S.col1, 
          col2 = S.col2;

最佳实践:更新行并保存在公司使用的SQL Server中

 WITH t AS
         (
           SELECT UserID, EmailAddress, Password, Gender, DOB, Location,
           Active  FROM Facebook.Users
         )
 UPDATE t SET Active = 0

这是更新记录的最安全的方式,这是您可以看到我们将要更新的内容的方式。来源:URL

同样的解决方案可以用稍微不同的方式编写,因为我只想设置一次列。这两张桌子我都写过了。它在MySQL中工作。

UPDATE Table t,
(SELECT col1, col2 FROM other_table WHERE sql = 'cool' ) o
SET t.col1 = o.col1, t.col2=o.col2
WHERE t.id = o.id

在接受的答案中,在以下内容之后:

SET
Table_A.col1 = Table_B.col1,
Table_A.col2 = Table_B.col2

我想补充一句:

OUTPUT deleted.*, inserted.*

我通常做的是将所有内容放入回滚事务中,并使用“OUTPUT”:这样我就可以看到即将发生的一切。当我对所看到的感到满意时,我将ROLLBACK更改为COMMIT。

我通常需要记录我所做的事情,所以我在运行回滚查询时使用“results to Text”选项,并保存脚本和OUTPUT的结果。(当然,如果我更改了太多行,这是不可行的)