在SQL Server中,可以使用insert将行插入到表中。。SELECT语句:

INSERT INTO Table (col1, col2, col3)
SELECT col1, col2, col3 
FROM other_table 
WHERE sql = 'cool'

是否也可以使用SELECT更新表?我有一个包含这些值的临时表,并希望使用这些值更新另一个表。也许是这样的:

UPDATE Table SET col1, col2
SELECT col1, col2 
FROM other_table 
WHERE sql = 'cool'
WHERE Table.id = other_table.id

当前回答

最佳实践:更新行并保存在公司使用的SQL Server中

 WITH t AS
         (
           SELECT UserID, EmailAddress, Password, Gender, DOB, Location,
           Active  FROM Facebook.Users
         )
 UPDATE t SET Active = 0

这是更新记录的最安全的方式,这是您可以看到我们将要更新的内容的方式。来源:URL

其他回答

以下示例使用派生表(FROM子句后的SELECT语句)返回旧值和新值以供进一步更新:

UPDATE x
SET    x.col1 = x.newCol1,
       x.col2 = x.newCol2
FROM   (SELECT t.col1,
               t2.col1 AS newCol1,
               t.col2,
               t2.col2 AS newCol2
        FROM   [table] t
               JOIN other_table t2
                 ON t.ID = t2.ID) x

您可以使用以下内容在SQL Server中进行更新:

UPDATE
    T1
SET
   T1.col1 = T2.col1,
   T1.col2 = T2.col2
FROM
   Table1 AS T1
INNER JOIN Table2 AS T2
    ON T1.id = T2.id
WHERE
    T1.col3 = 'cool'

我以前使用过INSERT SELECT。对于那些想使用新东西的人来说,这里有一个类似的解决方案,但它要短得多:

UPDATE table1                                          // Table that's going to be updated.
LEFT JOIN                                              // Type of join.
    table2 AS tb2                                      // Second table and rename for easy.
ON
    tb2.filedToMatchTables = table1.fieldToMatchTables // Fields to connect both tables.
SET
    fieldFromTable1 = tb2.fieldFromTable2;             // Field to be updated on table1.

    field1FromTable1 = tb2.field1FromTable2,           // This is in the case you need to
    field1FromTable1 = tb2.field1FromTable2,           // update more than one field.
    field1FromTable1 = tb2.field1FromTable2;           // Remember to put ; at the end.

Use:

drop table uno
drop table dos

create table uno
(
    uid int,
    col1 char(1),
    col2 char(2)
)
create table dos
(
    did int,
    col1 char(1),
    col2 char(2),
    [sql] char(4)
)
insert into uno(uid) values (1)
insert into uno(uid) values (2)
insert into dos values (1,'a','b',null)
insert into dos values (2,'c','d','cool')

select * from uno 
select * from dos

或者:

update uno set col1 = (select col1 from dos where uid = did and [sql]='cool'), 
col2 = (select col2 from dos where uid = did and [sql]='cool')

OR:

update uno set col1=d.col1,col2=d.col2 from uno 
inner join dos d on uid=did where [sql]='cool'

select * from uno 
select * from dos

如果两个表中的ID列名相同,则只需将表名放在要更新的表之前,并为所选表使用别名,即:

update uno set col1 = (select col1 from dos d where uno.[id] = d.[id] and [sql]='cool'),
col2  = (select col2 from dos d where uno.[id] = d.[id] and [sql]='cool')

我添加这个只是为了让你可以看到一个快速的方法来编写它,这样你就可以在更新之前检查将要更新的内容。

UPDATE Table 
SET  Table.col1 = other_table.col1,
     Table.col2 = other_table.col2 
--select Table.col1, other_table.col,Table.col2,other_table.col2, *   
FROM     Table 
INNER JOIN     other_table 
    ON     Table.id = other_table.id