在SQL Server中，可以使用insert将行插入到表中。。SELECT语句：
INSERT INTO Table (col1, col2, col3)
SELECT col1, col2, col3
FROM other_table
WHERE sql = 'cool'
是否也可以使用SELECT更新表？我有一个包含这些值的临时表，并希望使用这些值更新另一个表。也许是这样的：
UPDATE Table SET col1, col2
SELECT col1, col2
FROM other_table
WHERE sql = 'cool'
WHERE Table.id = other_table.id
当前回答
从select语句更新的另一种方法：
UPDATE A
SET A.col = A.col,B.col1 = B.col1
FROM first_Table AS A
INNER JOIN second_Table AS B ON A.id = B.id WHERE A.col2 = 'cool'
其他回答
如果使用MySQL而不是SQL Server，语法为：
UPDATE Table1
INNER JOIN Table2
ON Table1.id = Table2.id
SET Table1.col1 = Table2.col1,
Table1.col2 = Table2.col2
选项1：使用内部联接：
UPDATE
A
SET
A.col1 = B.col1,
A.col2 = B.col2
FROM
Some_Table AS A
INNER JOIN Other_Table AS B
ON A.id = B.id
WHERE
A.col3 = 'cool'
选项2：共同相关子查询
UPDATE table
SET Col1 = B.Col1,
Col2 = B.Col2
FROM (
SELECT ID, Col1, Col2
FROM other_table) B
WHERE
B.ID = table.ID
declare @tblStudent table (id int,name varchar(300))
declare @tblMarks table (std_id int,std_name varchar(300),subject varchar(50),marks int)
insert into @tblStudent Values (1,'Abdul')
insert into @tblStudent Values(2,'Rahim')
insert into @tblMarks Values(1,'','Math',50)
insert into @tblMarks Values(1,'','History',40)
insert into @tblMarks Values(2,'','Math',30)
insert into @tblMarks Values(2,'','history',80)
select * from @tblMarks
update m
set m.std_name=s.name
from @tblMarks as m
left join @tblStudent as s on s.id=m.std_id
select * from @tblMarks
Oracle SQL（使用别名）：
UPDATE Table T
SET T.col1 = (SELECT OT.col1 WHERE OT.id = T.id),
T.col2 = (SELECT OT.col2 WHERE OT.id = T.id);
甚至还有一种更短的方法，可能会让你感到惊讶：
示例数据集：
CREATE TABLE #SOURCE ([ID] INT, [Desc] VARCHAR(10));
CREATE TABLE #DEST ([ID] INT, [Desc] VARCHAR(10));
INSERT INTO #SOURCE VALUES(1,'Desc_1'), (2, 'Desc_2'), (3, 'Desc_3');
INSERT INTO #DEST VALUES(1,'Desc_4'), (2, 'Desc_5'), (3, 'Desc_6');
代码：
UPDATE #DEST
SET #DEST.[Desc] = #SOURCE.[Desc]
FROM #SOURCE
WHERE #DEST.[ID] = #SOURCE.[ID];
