在SQL Server中,可以使用insert将行插入到表中。。SELECT语句:

INSERT INTO Table (col1, col2, col3)
SELECT col1, col2, col3 
FROM other_table 
WHERE sql = 'cool'

是否也可以使用SELECT更新表?我有一个包含这些值的临时表,并希望使用这些值更新另一个表。也许是这样的:

UPDATE Table SET col1, col2
SELECT col1, col2 
FROM other_table 
WHERE sql = 'cool'
WHERE Table.id = other_table.id

当前回答

选项1:使用内部联接:

UPDATE
    A
SET
    A.col1 = B.col1,
    A.col2 = B.col2
FROM
    Some_Table AS A
    INNER JOIN Other_Table AS B
        ON A.id = B.id
WHERE
    A.col3 = 'cool'

选项2:共同相关子查询

UPDATE table 
SET Col1 = B.Col1, 
    Col2 = B.Col2 
FROM (
    SELECT ID, Col1, Col2 
    FROM other_table) B
WHERE 
    B.ID = table.ID

其他回答

UPDATE
    Table_A
SET
    Table_A.col1 = Table_B.col1,
    Table_A.col2 = Table_B.col2
FROM
    Some_Table AS Table_A
    INNER JOIN Other_Table AS Table_B
        ON Table_A.id = Table_B.id
WHERE
    Table_A.col3 = 'cool'
declare @tblStudent table (id int,name varchar(300))
declare @tblMarks table (std_id int,std_name varchar(300),subject varchar(50),marks int)

insert into @tblStudent Values (1,'Abdul')
insert into @tblStudent Values(2,'Rahim')

insert into @tblMarks Values(1,'','Math',50)
insert into @tblMarks Values(1,'','History',40)
insert into @tblMarks Values(2,'','Math',30)
insert into @tblMarks Values(2,'','history',80)


select * from @tblMarks

update m
set m.std_name=s.name
 from @tblMarks as m
left join @tblStudent as s on s.id=m.std_id

select * from @tblMarks

简单的方法是:

UPDATE
    table_to_update,
    table_info
SET
    table_to_update.col1 = table_info.col1,
    table_to_update.col2 = table_info.col2

WHERE
    table_to_update.ID = table_info.ID

这样地;但是您必须确保更新表和from之后的表是相同的。

UPDATE Table SET col1, col2
FROM table
inner join other_table Table.id = other_table.id
WHERE sql = 'cool'

在SQL Server 2008(或更高版本)中,使用MERGE

MERGE INTO YourTable T
   USING other_table S 
      ON T.id = S.id
         AND S.tsql = 'cool'
WHEN MATCHED THEN
   UPDATE 
      SET col1 = S.col1, 
          col2 = S.col2;

或者:

MERGE INTO YourTable T
   USING (
          SELECT id, col1, col2 
            FROM other_table 
           WHERE tsql = 'cool'
         ) S
      ON T.id = S.id
WHEN MATCHED THEN
   UPDATE 
      SET col1 = S.col1, 
          col2 = S.col2;