给定下面的2个toString()实现,哪个是首选的:
public String toString(){
return "{a:"+ a + ", b:" + b + ", c: " + c +"}";
}
or
public String toString(){
StringBuilder sb = new StringBuilder(100);
return sb.append("{a:").append(a)
.append(", b:").append(b)
.append(", c:").append(c)
.append("}")
.toString();
}
?
更重要的是,鉴于我们只有3个属性,它可能不会有什么不同,但在什么时候你会从+ concat切换到StringBuilder?
关键在于你是在一个地方写一个连接,还是在一段时间内把它积累起来。
对于您给出的示例,显式使用StringBuilder是没有意义的。(请查看第一个案例的编译代码。)
但是如果你正在构建一个字符串,例如在一个循环中,使用StringBuilder。
为了澄清,假设hugeArray包含数千个字符串,代码如下:
...
String result = "";
for (String s : hugeArray) {
result = result + s;
}
与以下相比非常浪费时间和内存:
...
StringBuilder sb = new StringBuilder();
for (String s : hugeArray) {
sb.append(s);
}
String result = sb.toString();
使用最新版本的Java(1.8)的反汇编(javap -c)显示了编译器引入的优化。+以及sb.append()将生成非常相似的代码。然而,如果我们在for循环中使用+,检查行为将是值得的。
在for循环中使用+添加字符串
Java:
public String myCatPlus(String[] vals) {
String result = "";
for (String val : vals) {
result = result + val;
}
return result;
}
ByteCode:(用于循环摘录)
12: iload 5
14: iload 4
16: if_icmpge 51
19: aload_3
20: iload 5
22: aaload
23: astore 6
25: new #3 // class java/lang/StringBuilder
28: dup
29: invokespecial #4 // Method java/lang/StringBuilder."<init>":()V
32: aload_2
33: invokevirtual #5 // Method java/lang/StringBuilder.append:(Ljava/lang/String;)Ljava/lang/StringBuilder;
36: aload 6
38: invokevirtual #5 // Method java/lang/StringBuilder.append:(Ljava/lang/String;)Ljava/lang/StringBuilder;
41: invokevirtual #6 // Method java/lang/StringBuilder.toString:()Ljava/lang/String;
44: astore_2
45: iinc 5, 1
48: goto 12
使用stringbuilder.append添加字符串
Java:
public String myCatSb(String[] vals) {
StringBuilder sb = new StringBuilder();
for(String val : vals) {
sb.append(val);
}
return sb.toString();
}
ByteCdoe:(循环摘录)
17: iload 5
19: iload 4
21: if_icmpge 43
24: aload_3
25: iload 5
27: aaload
28: astore 6
30: aload_2
31: aload 6
33: invokevirtual #5 // Method java/lang/StringBuilder.append:(Ljava/lang/String;)Ljava/lang/StringBuilder;
36: pop
37: iinc 5, 1
40: goto 17
43: aload_2
不过,两者还是有一些明显的区别。在第一种情况下,使用了+,为每次for循环迭代创建新的StringBuilder,并通过执行toString()调用存储生成的结果(29到41)。所以当你在for循环中使用+运算符时,你会生成你真正不需要的中间字符串。
我也和我的老板在使用append还是+的问题上发生了冲突。因为他们正在使用追加(我仍然不能弄清楚,因为他们说每次创建一个新对象)。
所以我想做些研究。虽然我喜欢Michael Borgwardt的解释,但只是想展示一个解释,如果将来有人真的需要知道的话。
/**
*
* @author Perilbrain
*/
public class Appc {
public Appc() {
String x = "no name";
x += "I have Added a name" + "We May need few more names" + Appc.this;
x.concat(x);
// x+=x.toString(); --It creates new StringBuilder object before concatenation so avoid if possible
//System.out.println(x);
}
public void Sb() {
StringBuilder sbb = new StringBuilder("no name");
sbb.append("I have Added a name");
sbb.append("We May need few more names");
sbb.append(Appc.this);
sbb.append(sbb.toString());
// System.out.println(sbb.toString());
}
}
而上述类的拆卸出来为
.method public <init>()V //public Appc()
.limit stack 2
.limit locals 2
met001_begin: ; DATA XREF: met001_slot000i
.line 12
aload_0 ; met001_slot000
invokespecial java/lang/Object.<init>()V
.line 13
ldc "no name"
astore_1 ; met001_slot001
.line 14
met001_7: ; DATA XREF: met001_slot001i
new java/lang/StringBuilder //1st object of SB
dup
invokespecial java/lang/StringBuilder.<init>()V
aload_1 ; met001_slot001
invokevirtual java/lang/StringBuilder.append(Ljava/lang/String;)Ljava/lan\
g/StringBuilder;
ldc "I have Added a nameWe May need few more names"
invokevirtual java/lang/StringBuilder.append(Ljava/lang/String;)Ljava/lan\
g/StringBuilder;
aload_0 ; met001_slot000
invokevirtual java/lang/StringBuilder.append(Ljava/lang/Object;)Ljava/lan\
g/StringBuilder;
invokevirtual java/lang/StringBuilder.toString()Ljava/lang/String;
astore_1 ; met001_slot001
.line 15
aload_1 ; met001_slot001
aload_1 ; met001_slot001
invokevirtual java/lang/String.concat(Ljava/lang/String;)Ljava/lang/Strin\
g;
pop
.line 18
return //no more SB created
met001_end: ; DATA XREF: met001_slot000i ...
; ===========================================================================
;met001_slot000 ; DATA XREF: <init>r ...
.var 0 is this LAppc; from met001_begin to met001_end
;met001_slot001 ; DATA XREF: <init>+6w ...
.var 1 is x Ljava/lang/String; from met001_7 to met001_end
.end method
;44-1=44
; ---------------------------------------------------------------------------
; Segment type: Pure code
.method public Sb()V //public void Sb
.limit stack 3
.limit locals 2
met002_begin: ; DATA XREF: met002_slot000i
.line 21
new java/lang/StringBuilder
dup
ldc "no name"
invokespecial java/lang/StringBuilder.<init>(Ljava/lang/String;)V
astore_1 ; met002_slot001
.line 22
met002_10: ; DATA XREF: met002_slot001i
aload_1 ; met002_slot001
ldc "I have Added a name"
invokevirtual java/lang/StringBuilder.append(Ljava/lang/String;)Ljava/lan\
g/StringBuilder;
pop
.line 23
aload_1 ; met002_slot001
ldc "We May need few more names"
invokevirtual java/lang/StringBuilder.append(Ljava/lang/String;)Ljava/lan\
g/StringBuilder;
pop
.line 24
aload_1 ; met002_slot001
aload_0 ; met002_slot000
invokevirtual java/lang/StringBuilder.append(Ljava/lang/Object;)Ljava/lan\
g/StringBuilder;
pop
.line 25
aload_1 ; met002_slot001
aload_1 ; met002_slot001
invokevirtual java/lang/StringBuilder.toString()Ljava/lang/String;
invokevirtual java/lang/StringBuilder.append(Ljava/lang/String;)Ljava/lan\
g/StringBuilder;
pop
.line 28
return
met002_end: ; DATA XREF: met002_slot000i ...
;met002_slot000 ; DATA XREF: Sb+25r
.var 0 is this LAppc; from met002_begin to met002_end
;met002_slot001 ; DATA XREF: Sb+9w ...
.var 1 is sbb Ljava/lang/StringBuilder; from met002_10 to met002_end
.end method
;96-49=48
; ---------------------------------------------------------------------------
从上面的两个代码你可以看出Michael是对的。每种情况下只创建一个SB对象。