有人知道如何在Swift中验证电子邮件地址吗?我找到了这个代码:

- (BOOL) validEmail:(NSString*) emailString {

    if([emailString length]==0){
        return NO;
    }

    NSString *regExPattern = @"[A-Z0-9a-z._%+-]+@[A-Za-z0-9.-]+\\.[A-Za-z]{2,4}";

    NSRegularExpression *regEx = [[NSRegularExpression alloc] initWithPattern:regExPattern options:NSRegularExpressionCaseInsensitive error:nil];
    NSUInteger regExMatches = [regEx numberOfMatchesInString:emailString options:0 range:NSMakeRange(0, [emailString length])];

    NSLog(@"%i", regExMatches);
    if (regExMatches == 0) {
        return NO;
    } else {
        return YES;
    }
}

但我无法翻译成斯威夫特。


当前回答

Swift 5 -可伸缩的验证层

使用此层,您将轻松地在任何文本字段上获得惊人的验证。

只需遵循以下流程即可。

1. 添加这些枚举:

import Foundation

enum ValidatorType
{
    case email
    case name
    // add more cases ...
}

enum ValidationError: Error, LocalizedError
{
    case invalidUserName
    case invalidEmail
    // add more cases ...

    var localizedDescription: String
    {
        switch self
        {
        case .invalidEmail:
            return "Please kindly write a valid email"    
        case .invalidUserName:
            return "Please kindly write a valid user name"
        }
    }
}

2. 将此功能添加到String:

extension String
{
    // MARK:- Properties

    var isValidEmail: Bool
    {
        let emailFormat = "[A-Z0-9a-z._%+-]+@[A-Za-z0-9.-]+\\.[A-Za-z]{2,64}"
        let emailPredicate = NSPredicate(format:"SELF MATCHES %@", emailFormat)
        return emailPredicate.evaluate(with: self)
    }

    // MARK:- Methods

    func validatedText(_ validationType: ValidatorType) throws
    {
        switch validationType
        {
            case .name:
                try validateUsername()
            case .email:
                try validateEmail()
        }
    }

    // MARK:- Private Methods

    private func validateUsername() throws
    {
        if isEmpty
        {
            throw ValidationError.invalidUserName
        }
    }

    private func validateEmail() throws
    {
        if !isValidEmail 
        {
            throw ValidationError.invalidEmail
        }

        // add more validations if you want like empty email
    }
}

3.添加以下功能到UITextField:

import UIKit

extension UITextField
{
    func validatedText(_ validationType: ValidatorType) throws
    {
        do
        {
            try text?.validatedText(validationType)
        }
        catch let validationError
        {
            shake()
            throw validationError
        }
    }

    // MARK:- Private Methods

    private func shake()
    {
        let animation = CABasicAnimation(keyPath: "position")
        animation.duration = 0.1
        animation.repeatCount = 5
        animation.fromValue = NSValue(cgPoint: CGPoint(x: center.x + 6, y: center.y))
        animation.toValue = NSValue(cgPoint: CGPoint(x: center.x - 6, y: center.y))
        layer.add(animation, forKey: "position")
    }
}

使用

import UIKit

class LoginVC: UIViewController
{
    // MARK: Outlets

    @IBOutlet weak var textFieldEmail: UITextField!

    // MARK: View Controller Life Cycle

    override func viewDidLoad()
    {
        super.viewDidLoad()
    }

    // MARK: Methods

    private func checkEmail() -> Bool
    {
        do
        {
            try textFieldEmail.validatedText(.email)
        }
        catch let error
        {
            let validationError = error as! ValidationError
            // show alert to user with: validationError.localizedDescription
            return false
        }

        return true
    }

    // MARK: Actions

    @IBAction func loginTapped(_ sender: UIButton)
    {
        if checkEmail()
        {
            let email = textFieldEmail.text!
            // move safely ...
        }
    }
}

其他回答

我为输入验证设计了一个库,其中一个“模块”可以让你轻松地验证一堆东西…

例如,要验证一封电子邮件:

let emailTrial = Trial.Email
let trial = emailTrial.trial()

if(trial(evidence: "test@test.com")) {
   //email is valid
}

SwiftCop是图书馆…希望能有所帮助!

我改进了@Azik的答案。我允许使用准则允许的更多特殊字符,并返回一些无效的额外边缘情况。

小组认为这里只允许本地部分的。_%+-是不正确的。参见@Anton Gogolev对这个问题的回答或参见下文:

The local-part of the email address may use any of these ASCII characters: uppercase and lowercase Latin letters A to Z and a to z; digits 0 to 9; special characters !#$%&'*+-/=?^_`{|}~; dot ., provided that it is not the first or last character unless quoted, and provided also that it does not appear consecutively unless quoted (e.g. John..Doe@example.com is not allowed but "John..Doe"@example.com is allowed); space and "(),:;<>@[\] characters are allowed with restrictions (they are only allowed inside a quoted string, as described in the paragraph below, and in addition, a backslash or double-quote must be preceded by a backslash); comments are allowed with parentheses at either end of the local-part; e.g. john.smith(comment)@example.com and (comment)john.smith@example.com are both equivalent to john.smith@example.com;

我使用的代码将不允许限制性的特殊字符,但将允许比这里的大多数答案更多的选项。我更喜欢更宽松的验证,而不是谨慎的错误。

if enteredText.contains("..") || enteredText.contains("@@") 
   || enteredText.hasPrefix(".") || enteredText.hasSuffix(".con"){
       return false
}

let emailFormat = "[A-Z0-9a-z.!#$%&'*+-/=?^_`{|}~]+@[A-Za-z0-9.-]+\\.[A-Za-z]{2,64}"
let emailPredicate = NSPredicate(format:"SELF MATCHES %@", emailFormat)     
return emailPredicate.evaluate(with: enteredText)

下面是两个投票最多的答案与正确的正则表达式的融合:一个使用谓词的字符串扩展,因此您可以调用String . isemail

    extension String {
        var isEmail: Bool {
           let emailRegEx = "[A-Z0-9a-z._%+-]+@[A-Za-z0-9.-]+\\.[A-Za-z]{2,20}"            
           let emailTest  = NSPredicate(format:"SELF MATCHES %@", emailRegEx)
           return emailTest.evaluateWithObject(self)
        }
    }

创建简单的扩展:

extension NSRegularExpression {

    convenience init(pattern: String) {
        try! self.init(pattern: pattern, options: [])
    }
}

extension String {

    var isValidEmail: Bool {
        return isMatching(expression: NSRegularExpression(pattern: "^[A-Z0-9a-z\\._%+-]+@([A-Za-z0-9-]+\\.)+[A-Za-z]{2,4}$"))
    }

    //MARK: - Private

    private func isMatching(expression: NSRegularExpression) -> Bool {
        return expression.numberOfMatches(in: self, range: NSRange(location: 0, length: characters.count)) > 0
    }
}

例子:

"b@bb.pl".isValidEmail //true
"b@bb".isValidEmail //false

你可以扩展以下扩展到任何你需要的:isValidPhoneNumber, isValidPassword等…

@JeffersonBe的答案是接近的,但如果字符串是“包含someone@something.com一个有效的电子邮件”,这不是我们想要的。下面是String上的一个扩展,它工作得很好(并且允许测试有效的phoneNumber和其他数据检测器来引导。

/// Helper for various data detector matches.
/// Returns `true` iff the `String` matches the data detector type for the complete string.
func matchesDataDetector(type: NSTextCheckingResult.CheckingType, scheme: String? = nil) -> Bool {
    let dataDetector = try? NSDataDetector(types: type.rawValue)
    guard let firstMatch = dataDetector?.firstMatch(in: self, options: NSRegularExpression.MatchingOptions.reportCompletion, range: NSRange(location: 0, length: length)) else {
        return false
    }
    return firstMatch.range.location != NSNotFound
        // make sure the entire string is an email, not just contains an email
        && firstMatch.range.location == 0
        && firstMatch.range.length == length
        // make sure the link type matches if link scheme
        && (type != .link || scheme == nil || firstMatch.url?.scheme == scheme)
}
/// `true` iff the `String` is an email address in the proper form.
var isEmail: Bool {
    return matchesDataDetector(type: .link, scheme: "mailto")
}
/// `true` iff the `String` is a phone number in the proper form.
var isPhoneNumber: Bool {
    return matchesDataDetector(type: .phoneNumber)
}
/// number of characters in the `String` (required for above).
var length: Int {
    return self.characters.count
}