有人知道如何在Swift中验证电子邮件地址吗?我找到了这个代码:
- (BOOL) validEmail:(NSString*) emailString {
if([emailString length]==0){
return NO;
}
NSString *regExPattern = @"[A-Z0-9a-z._%+-]+@[A-Za-z0-9.-]+\\.[A-Za-z]{2,4}";
NSRegularExpression *regEx = [[NSRegularExpression alloc] initWithPattern:regExPattern options:NSRegularExpressionCaseInsensitive error:nil];
NSUInteger regExMatches = [regEx numberOfMatchesInString:emailString options:0 range:NSMakeRange(0, [emailString length])];
NSLog(@"%i", regExMatches);
if (regExMatches == 0) {
return NO;
} else {
return YES;
}
}
但我无法翻译成斯威夫特。
这是Swift 2.0 - 2.2的更新版本
var isEmail: Bool {
do {
let regex = try NSRegularExpression(pattern: "^[a-zA-Z0-9.!#$%&'*+/=?^_`{|}~-]+@[a-zA-Z0-9](?:[a-zA-Z0-9-]{0,61}[a-zA-Z0-9])?(?:\\.[a-zA-Z0-9](?:[a-zA-Z0-9-]{0,61}[a-zA-Z0-9])?)*$", options: .CaseInsensitive)
return regex.firstMatchInString(self, options: NSMatchingOptions(rawValue: 0), range: NSMakeRange(0, self.characters.count)) != nil
} catch {
return false
}
}
对于swift 2.1:这可以通过电子邮件foo@bar正常工作
extension String {
func isValidEmail() -> Bool {
do {
let regex = try NSRegularExpression(pattern: "[A-Z0-9a-z._%+-]+@[A-Za-z0-9.-]+\\.[A-Za-z]{2,6}", options: .CaseInsensitive)
return regex.firstMatchInString(self, options: NSMatchingOptions(rawValue: 0), range: NSMakeRange(0, self.characters.count)) != nil
} catch {
return false
}
}
}
作为String类扩展
斯威夫特4
extension String {
func isValidEmail() -> Bool {
// here, `try!` will always succeed because the pattern is valid
let regex = try! NSRegularExpression(pattern: "^[a-zA-Z0-9.!#$%&'*+/=?^_`{|}~-]+@[a-zA-Z0-9](?:[a-zA-Z0-9-]{0,61}[a-zA-Z0-9])?(?:\\.[a-zA-Z0-9](?:[a-zA-Z0-9-]{0,61}[a-zA-Z0-9])?)*$", options: .caseInsensitive)
return regex.firstMatch(in: self, options: [], range: NSRange(location: 0, length: count)) != nil
}
}
使用
if "rdfsdsfsdfsd".isValidEmail() {
}
以下是目前Swiftmailer中一个非常简单的方法。其他大多数答案都是老掉牙的。
根据Swiftmailer文档:
https://swiftmailer.symfony.com/docs/messages.html#quick-reference
use Egulias\EmailValidator\EmailValidator;
use Egulias\EmailValidator\Validation\RFCValidation;
$validator = new EmailValidator();
$validator->isValid("example@example.com", new RFCValidation()); //true
在我看来，这是迄今为止最简单、最健壮的方法。只需通过Composer安装egalias \EmailValidator库，它应该已经作为SwiftMailer的依赖项引入了。
我改进了@Azik的答案。我允许使用准则允许的更多特殊字符，并返回一些无效的额外边缘情况。
小组认为这里只允许本地部分的。_%+-是不正确的。参见@Anton Gogolev对这个问题的回答或参见下文:
The local-part of the email address may use any of these ASCII
characters:
uppercase and lowercase Latin letters A to Z and a to z;
digits 0 to 9;
special characters !#$%&'*+-/=?^_`{|}~;
dot ., provided that it is not the first or last character unless quoted, and provided also that it does not appear consecutively unless quoted (e.g.
John..Doe@example.com is not allowed but "John..Doe"@example.com is
allowed);
space and "(),:;<>@[\] characters are allowed with
restrictions (they are only allowed inside a quoted string, as
described in the paragraph below, and in addition, a backslash or
double-quote must be preceded by a backslash);
comments are allowed
with parentheses at either end of the local-part; e.g.
john.smith(comment)@example.com and (comment)john.smith@example.com
are both equivalent to john.smith@example.com;
我使用的代码将不允许限制性的特殊字符，但将允许比这里的大多数答案更多的选项。我更喜欢更宽松的验证，而不是谨慎的错误。
if enteredText.contains("..") || enteredText.contains("@@")
|| enteredText.hasPrefix(".") || enteredText.hasSuffix(".con"){
return false
}
let emailFormat = "[A-Z0-9a-z.!#$%&'*+-/=?^_`{|}~]+@[A-Za-z0-9.-]+\\.[A-Za-z]{2,64}"
let emailPredicate = NSPredicate(format:"SELF MATCHES %@", emailFormat)
return emailPredicate.evaluate(with: enteredText)
