我改进了@Azik的答案。我允许使用准则允许的更多特殊字符，并返回一些无效的额外边缘情况。

小组认为这里只允许本地部分的。_%+-是不正确的。参见@Anton Gogolev对这个问题的回答或参见下文:

The local-part of the email address may use any of these ASCII characters: uppercase and lowercase Latin letters A to Z and a to z; digits 0 to 9; special characters !#$%&'*+-/=?^_`{|}~; dot ., provided that it is not the first or last character unless quoted, and provided also that it does not appear consecutively unless quoted (e.g. John..Doe@example.com is not allowed but "John..Doe"@example.com is allowed); space and "(),:;<>@[\] characters are allowed with restrictions (they are only allowed inside a quoted string, as described in the paragraph below, and in addition, a backslash or double-quote must be preceded by a backslash); comments are allowed with parentheses at either end of the local-part; e.g. john.smith(comment)@example.com and (comment)john.smith@example.com are both equivalent to john.smith@example.com;

我使用的代码将不允许限制性的特殊字符，但将允许比这里的大多数答案更多的选项。我更喜欢更宽松的验证，而不是谨慎的错误。

if enteredText.contains("..") || enteredText.contains("@@") 
   || enteredText.hasPrefix(".") || enteredText.hasSuffix(".con"){
       return false
}

let emailFormat = "[A-Z0-9a-z.!#$%&'*+-/=?^_`{|}~]+@[A-Za-z0-9.-]+\\.[A-Za-z]{2,64}"
let emailPredicate = NSPredicate(format:"SELF MATCHES %@", emailFormat)     
return emailPredicate.evaluate(with: enteredText)

//Email validation
func validateEmail(enterEmail:String) -> Bool{
    let emailFormat = "[A-Z0-9a-z._%+-]+@[A-Za-z0-9.-]+\\.[A-Za-z]{2,64}"
    let emailPredicate = NSPredicate(format:"SELF MATCHES %@",emailFormat)
    return emailPredicate.evaluate(with:enterEmail)
}

100%工作和测试

下面是两个投票最多的答案与正确的正则表达式的融合:一个使用谓词的字符串扩展，因此您可以调用String . isemail

    extension String {
        var isEmail: Bool {
           let emailRegEx = "[A-Z0-9a-z._%+-]+@[A-Za-z0-9.-]+\\.[A-Za-z]{2,20}"            
           let emailTest  = NSPredicate(format:"SELF MATCHES %@", emailRegEx)
           return emailTest.evaluateWithObject(self)
        }
    }

以下是目前Swiftmailer中一个非常简单的方法。其他大多数答案都是老掉牙的。

根据Swiftmailer文档: https://swiftmailer.symfony.com/docs/messages.html#quick-reference

use Egulias\EmailValidator\EmailValidator;
use Egulias\EmailValidator\Validation\RFCValidation;

$validator = new EmailValidator();
$validator->isValid("example@example.com", new RFCValidation()); //true

在我看来，这是迄今为止最简单、最健壮的方法。只需通过Composer安装egalias \EmailValidator库，它应该已经作为SwiftMailer的依赖项引入了。

以上大多数正则表达式示例在电子邮件存在基本问题时都无法捕获错误。例如

h..1@nyu.edu -连续的点 ab1234@.nyu.edu - @后面的点 a.bcdnle12.@email.com - @前的点 .abc@email.com -以一个点开始

这是一个字符串扩展，我使用了更严格的规则使用正则表达式。

extension String {
    func isValidEmail() -> Bool {
        let emailRegEx = "^(?!\\.)([A-Z0-9a-z_%+-]?[\\.]?[A-Z0-9a-z_%+-])+@[A-Za-z0-9-]{1,20}(\\.[A-Za-z0-9]{1,15}){0,10}\\.[A-Za-z]{2,20}$"
        let emailPred = NSPredicate(format:"SELF MATCHES %@", emailRegEx)
        return emailPred.evaluate(with: self)
   }
}

下面是我们如何为它编写测试用例。

XCTAssertFalse("ab1234@.nyu.edu".isValidEmail())
XCTAssertTrue("valid_email@email.com".isValidEmail())

对于swift 2.1:这可以通过电子邮件foo@bar正常工作

extension String {
    func isValidEmail() -> Bool {
        do {
            let regex = try NSRegularExpression(pattern: "[A-Z0-9a-z._%+-]+@[A-Za-z0-9.-]+\\.[A-Za-z]{2,6}", options: .CaseInsensitive)
            return regex.firstMatchInString(self, options: NSMatchingOptions(rawValue: 0), range: NSMakeRange(0, self.characters.count)) != nil
        } catch {
                return false
        }
    }
}