有人知道如何在Swift中验证电子邮件地址吗?我找到了这个代码:
- (BOOL) validEmail:(NSString*) emailString {
if([emailString length]==0){
return NO;
}
NSString *regExPattern = @"[A-Z0-9a-z._%+-]+@[A-Za-z0-9.-]+\\.[A-Za-z]{2,4}";
NSRegularExpression *regEx = [[NSRegularExpression alloc] initWithPattern:regExPattern options:NSRegularExpressionCaseInsensitive error:nil];
NSUInteger regExMatches = [regEx numberOfMatchesInString:emailString options:0 range:NSMakeRange(0, [emailString length])];
NSLog(@"%i", regExMatches);
if (regExMatches == 0) {
return NO;
} else {
return YES;
}
}
但我无法翻译成斯威夫特。
如果你正在寻找一个干净简单的解决方案,你应该看看https://github.com/nsagora/validation-components。
它包含一个电子邮件验证谓词,很容易集成在你的代码:
let email = "test@example.com"
let rule = EmailValidationPredicate()
let isValidEmail = rule.evaluate(with: email)
在引擎盖后面,它使用RFC 5322 regex (http://emailregex.com):
let regex = "(?:[\\p{L}0-9!#$%\\&'*+/=?\\^_`{|}~-]+(?:\\.[\\p{L}0-9!#$%\\&'*+/=?\\^_`{|}" +
"~-]+)*|\"(?:[\\x01-\\x08\\x0b\\x0c\\x0e-\\x1f\\x21\\x23-\\x5b\\x5d-\\" +
"x7f]|\\\\[\\x01-\\x09\\x0b\\x0c\\x0e-\\x7f])*\")@(?:(?:[\\p{L}0-9](?:[a-" +
"z0-9-]*[\\p{L}0-9])?\\.)+[\\p{L}0-9](?:[\\p{L}0-9-]*[\\p{L}0-9])?|\\[(?:(?:25[0-5" +
"]|2[0-4][0-9]|[01]?[0-9][0-9]?)\\.){3}(?:25[0-5]|2[0-4][0-9]|[01]?[0-" +
"9][0-9]?|[\\p{L}0-9-]*[\\p{L}0-9]:(?:[\\x01-\\x08\\x0b\\x0c\\x0e-\\x1f\\x21" +
"-\\x5a\\x53-\\x7f]|\\\\[\\x01-\\x09\\x0b\\x0c\\x0e-\\x7f])+)\\])"
以下是目前Swiftmailer中一个非常简单的方法。其他大多数答案都是老掉牙的。
根据Swiftmailer文档:
https://swiftmailer.symfony.com/docs/messages.html#quick-reference
use Egulias\EmailValidator\EmailValidator;
use Egulias\EmailValidator\Validation\RFCValidation;
$validator = new EmailValidator();
$validator->isValid("example@example.com", new RFCValidation()); //true
在我看来,这是迄今为止最简单、最健壮的方法。只需通过Composer安装egalias \EmailValidator库,它应该已经作为SwiftMailer的依赖项引入了。
我唯一添加到响应列表的是,对于Linux, NSRegularExpression不存在,它实际上是RegularExpression
func isEmail() -> Bool {
let patternNormal = "[A-Z0-9a-z._%+-]+@[A-Za-z0-9.-]+\\.[A-Za-z]{2,6}"
#if os(Linux)
let regex = try? RegularExpression(pattern: patternNormal, options: .caseInsensitive)
#else
let regex = try? NSRegularExpression(pattern: patternNormal, options: .caseInsensitive)
#endif
return regex?.firstMatch(in: self, options: [], range: NSMakeRange(0, self.characters.count)) != nil
在macOS和Ubuntu上都能成功编译。
以上大多数正则表达式示例在电子邮件存在基本问题时都无法捕获错误。例如
h..1@nyu.edu -连续的点
ab1234@.nyu.edu - @后面的点
a.bcdnle12.@email.com - @前的点
.abc@email.com -以一个点开始
这是一个字符串扩展,我使用了更严格的规则使用正则表达式。
extension String {
func isValidEmail() -> Bool {
let emailRegEx = "^(?!\\.)([A-Z0-9a-z_%+-]?[\\.]?[A-Z0-9a-z_%+-])+@[A-Za-z0-9-]{1,20}(\\.[A-Za-z0-9]{1,15}){0,10}\\.[A-Za-z]{2,20}$"
let emailPred = NSPredicate(format:"SELF MATCHES %@", emailRegEx)
return emailPred.evaluate(with: self)
}
}
下面是我们如何为它编写测试用例。
XCTAssertFalse("ab1234@.nyu.edu".isValidEmail())
XCTAssertTrue("valid_email@email.com".isValidEmail())
在Swift 4.2和Xcode 10.1中
//Email validation
func isValidEmail(email: String) -> Bool {
let emailRegex = "[A-Z0-9a-z._%+-]+@[A-Za-z0-9.-]+\\.[A-Za-z]{2,4}"
var valid = NSPredicate(format: "SELF MATCHES %@", emailRegex).evaluate(with: email)
if valid {
valid = !email.contains("Invalid email id")
}
return valid
}
//Use like this....
let emailTrimmedString = emailTF.text?.trimmingCharacters(in: .whitespaces)
if isValidEmail(email: emailTrimmedString!) == false {
SharedClass.sharedInstance.alert(view: self, title: "", message: "Please enter valid email")
}
如果你想使用SharedClass。
//This is SharedClass
import UIKit
class SharedClass: NSObject {
static let sharedInstance = SharedClass()
//Email validation
func isValidEmail(email: String) -> Bool {
let emailRegex = "[A-Z0-9a-z._%+-]+@[A-Za-z0-9.-]+\\.[A-Za-z]{2,4}"
var valid = NSPredicate(format: "SELF MATCHES %@", emailRegex).evaluate(with: email)
if valid {
valid = !email.contains("Invalid email id")
}
return valid
}
private override init() {
}
}
并调用这样的函数....
if SharedClass.sharedInstance. isValidEmail(email: emailTrimmedString!) == false {
SharedClass.sharedInstance.alert(view: self, title: "", message: "Please enter correct email")
//Your code here
} else {
//Code here
}