如何验证一个电子邮件地址在swift?

有人知道如何在Swift中验证电子邮件地址吗?我找到了这个代码:

- (BOOL) validEmail:(NSString*) emailString {

    if([emailString length]==0){
        return NO;
    }

    NSString *regExPattern = @"[A-Z0-9a-z._%+-]+@[A-Za-z0-9.-]+\\.[A-Za-z]{2,4}";

    NSRegularExpression *regEx = [[NSRegularExpression alloc] initWithPattern:regExPattern options:NSRegularExpressionCaseInsensitive error:nil];
    NSUInteger regExMatches = [regEx numberOfMatchesInString:emailString options:0 range:NSMakeRange(0, [emailString length])];

    NSLog(@"%i", regExMatches);
    if (regExMatches == 0) {
        return NO;
    } else {
        return YES;
    }
}

但我无法翻译成斯威夫特。

当前回答

斯威夫特5

 func isValidEmailAddress(emailAddressString: String) -> Bool {

 var returnValue = true
 let emailRegEx = "[A-Z0-9a-z.-_]+@[A-Za-z0-9.-]+\\.[A-Za-z]{2,3}"

 do {
        let regex = try NSRegularExpression(pattern: emailRegEx)
        let nsString = emailAddressString as NSString
        let results = regex.matches(in: emailAddressString, range: NSRange(location: 0, length: nsString.length))

        if results.count == 0
        {
            returnValue = false
        }

    } catch let error as NSError {
        print("invalid regex: \(error.localizedDescription)")
        returnValue = false
    }

    return  returnValue
}

然后:

let validEmail = isValidEmailAddress(emailAddressString: "your@email.com")
print(validEmail)

2019-06-25 17:17:11

其他回答

这是一个最新的游乐场兼容版本，使用标准库，所以你不需要维护一个正则表达式:

import Foundation

func isValid(email: String) -> Bool {
  do {
    let detector = try NSDataDetector(types: NSTextCheckingResult.CheckingType.link.rawValue)
    let range = NSRange(location: 0, length: email.count)
    let matches = detector.matches(in: email, options: .anchored, range: range)
    guard matches.count == 1 else { return false }
    return matches[0].url?.scheme == "mailto"
  } catch {
    return false
  }
}

extension String {
  var isValidEmail: Bool {
    isValid(email: self)
  }
}

let email = "test@mail.com"
isValid(email: email) // prints 'true'
email.isValidEmail // prints 'true'

2021-11-17 11:47:09

Swift 5中最简单的方法

extension String {
    var isValidEmail: Bool {
        NSPredicate(format: "SELF MATCHES %@", "[A-Z0-9a-z._%+-]+@[A-Za-z0-9.-]+\\.[A-Za-z]{2,}").evaluate(with: self)
    }
}

例子

"kenmueller0@gmail.com".isValidEmail

返回……

true

2019-06-16 07:38:02

对于Swift 3:

extension String {
    func isValidEmail() -> Bool {
        let regex = try? NSRegularExpression(pattern: "^[a-zA-Z0-9.!#$%&'*+/=?^_`{|}~-]+@[a-zA-Z0-9](?:[a-zA-Z0-9-]{0,61}[a-zA-Z0-9])?(?:\\.[a-zA-Z0-9](?:[a-zA-Z0-9-]{0,61}[a-zA-Z0-9])?)*$", options: .caseInsensitive)
        return regex?.firstMatch(in: self, options: [], range: NSMakeRange(0, self.characters.count)) != nil
    }
}

2016-10-14 14:06:07

如果你正在寻找一个干净简单的解决方案，你应该看看https://github.com/nsagora/validation-components。

它包含一个电子邮件验证谓词，很容易集成在你的代码:

let email = "test@example.com"
let rule = EmailValidationPredicate()
let isValidEmail = rule.evaluate(with: email)

在引擎盖后面，它使用RFC 5322 regex (http://emailregex.com):

let regex = "(?:[\\p{L}0-9!#$%\\&'*+/=?\\^_`{|}~-]+(?:\\.[\\p{L}0-9!#$%\\&'*+/=?\\^_`{|}" +
    "~-]+)*|\"(?:[\\x01-\\x08\\x0b\\x0c\\x0e-\\x1f\\x21\\x23-\\x5b\\x5d-\\" +
    "x7f]|\\\\[\\x01-\\x09\\x0b\\x0c\\x0e-\\x7f])*\")@(?:(?:[\\p{L}0-9](?:[a-" +
    "z0-9-]*[\\p{L}0-9])?\\.)+[\\p{L}0-9](?:[\\p{L}0-9-]*[\\p{L}0-9])?|\\[(?:(?:25[0-5" +
    "]|2[0-4][0-9]|[01]?[0-9][0-9]?)\\.){3}(?:25[0-5]|2[0-4][0-9]|[01]?[0-" +
    "9][0-9]?|[\\p{L}0-9-]*[\\p{L}0-9]:(?:[\\x01-\\x08\\x0b\\x0c\\x0e-\\x1f\\x21" +
    "-\\x5a\\x53-\\x7f]|\\\\[\\x01-\\x09\\x0b\\x0c\\x0e-\\x7f])+)\\])"

2016-09-17 19:11:20

//Email validation
func validateEmail(enterEmail:String) -> Bool{
    let emailFormat = "[A-Z0-9a-z._%+-]+@[A-Za-z0-9.-]+\\.[A-Za-z]{2,64}"
    let emailPredicate = NSPredicate(format:"SELF MATCHES %@",emailFormat)
    return emailPredicate.evaluate(with:enterEmail)
}

100%工作和测试

2018-03-08 09:24:07

如何验证一个电子邮件地址在swift?

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