有人知道如何在Swift中验证电子邮件地址吗?我找到了这个代码:
- (BOOL) validEmail:(NSString*) emailString {
if([emailString length]==0){
return NO;
}
NSString *regExPattern = @"[A-Z0-9a-z._%+-]+@[A-Za-z0-9.-]+\\.[A-Za-z]{2,4}";
NSRegularExpression *regEx = [[NSRegularExpression alloc] initWithPattern:regExPattern options:NSRegularExpressionCaseInsensitive error:nil];
NSUInteger regExMatches = [regEx numberOfMatchesInString:emailString options:0 range:NSMakeRange(0, [emailString length])];
NSLog(@"%i", regExMatches);
if (regExMatches == 0) {
return NO;
} else {
return YES;
}
}
但我无法翻译成斯威夫特。
@JeffersonBe的答案是接近的，但如果字符串是“包含someone@something.com一个有效的电子邮件”，这不是我们想要的。下面是String上的一个扩展，它工作得很好(并且允许测试有效的phoneNumber和其他数据检测器来引导。
/// Helper for various data detector matches.
/// Returns `true` iff the `String` matches the data detector type for the complete string.
func matchesDataDetector(type: NSTextCheckingResult.CheckingType, scheme: String? = nil) -> Bool {
let dataDetector = try? NSDataDetector(types: type.rawValue)
guard let firstMatch = dataDetector?.firstMatch(in: self, options: NSRegularExpression.MatchingOptions.reportCompletion, range: NSRange(location: 0, length: length)) else {
return false
}
return firstMatch.range.location != NSNotFound
// make sure the entire string is an email, not just contains an email
&& firstMatch.range.location == 0
&& firstMatch.range.length == length
// make sure the link type matches if link scheme
&& (type != .link || scheme == nil || firstMatch.url?.scheme == scheme)
}
/// `true` iff the `String` is an email address in the proper form.
var isEmail: Bool {
return matchesDataDetector(type: .link, scheme: "mailto")
}
/// `true` iff the `String` is a phone number in the proper form.
var isPhoneNumber: Bool {
return matchesDataDetector(type: .phoneNumber)
}
/// number of characters in the `String` (required for above).
var length: Int {
return self.characters.count
}
创建简单的扩展:
extension NSRegularExpression {
convenience init(pattern: String) {
try! self.init(pattern: pattern, options: [])
}
}
extension String {
var isValidEmail: Bool {
return isMatching(expression: NSRegularExpression(pattern: "^[A-Z0-9a-z\\._%+-]+@([A-Za-z0-9-]+\\.)+[A-Za-z]{2,4}$"))
}
//MARK: - Private
private func isMatching(expression: NSRegularExpression) -> Bool {
return expression.numberOfMatches(in: self, range: NSRange(location: 0, length: characters.count)) > 0
}
}
例子:
"b@bb.pl".isValidEmail //true
"b@bb".isValidEmail //false
你可以扩展以下扩展到任何你需要的:isValidPhoneNumber, isValidPassword等…
在Swift 5.7中，在Regex类的帮助下，我们可以以简单有效的方式验证电子邮件地址
private func isValidEmail(_ email: String) -> Bool {
guard let emailRegex = try? Regex("[A-Z0-9a-z._%+-]+@[A-Za-z0-9.-]+\\.[A-Za-z]{2,64}")
else { return false }
return email.firstMatch(of: emailRegex) != nil
}
我们还可以使用属性包装器来提高效率:
@propertyWrapper
struct EmailPropertyWrapper {
private var _value: String
var wrappedValue: String {
get { return isValidEmail(_value) ? _value : String() }
set { _value = newValue }
}
init(email: String) {
_value = email
}
private func isValidEmail(_ email: String) -> Bool {
guard let emailRegex = try? Regex("[A-Z0-9a-z._%+-]+@[A-Za-z0-9.-]+\\.[A-Za-z]{2,64}")
else { return false }
return email.firstMatch(of: emailRegex) != nil
}
}
struct User {
var name: String
@EmailPropertyWrapper var email: String
func validateProperty() -> Bool {
if name.isEmpty || email.isEmpty { return false }
return true
}
}
let user = User(name: "Sy", email: .init(email: "wwdc@icloud.com"))
print(user.validateProperty())
更新答案@Arsonik对Swift 2.2的回答，使用比其他提供的解决方案更少的冗长代码:
extension String {
func isValidEmail() -> Bool {
let regex = try? NSRegularExpression(pattern: "^[a-zA-Z0-9.!#$%&'*+/=?^_`{|}~-]+@[a-zA-Z0-9](?:[a-zA-Z0-9-]{0,61}[a-zA-Z0-9])?(?:\\.[a-zA-Z0-9](?:[a-zA-Z0-9-]{0,61}[a-zA-Z0-9])?)*$", options: .CaseInsensitive)
return regex?.firstMatchInString(self, options: [], range: NSMakeRange(0, self.characters.count)) != nil
}
}
