我为输入验证设计了一个库，其中一个“模块”可以让你轻松地验证一堆东西…

例如，要验证一封电子邮件:

let emailTrial = Trial.Email
let trial = emailTrial.trial()

if(trial(evidence: "test@test.com")) {
   //email is valid
}

SwiftCop是图书馆…希望能有所帮助!

我唯一添加到响应列表的是，对于Linux, NSRegularExpression不存在，它实际上是RegularExpression

    func isEmail() -> Bool {

    let patternNormal = "[A-Z0-9a-z._%+-]+@[A-Za-z0-9.-]+\\.[A-Za-z]{2,6}"

    #if os(Linux)
        let regex = try? RegularExpression(pattern: patternNormal, options: .caseInsensitive)
    #else
        let regex = try? NSRegularExpression(pattern: patternNormal, options: .caseInsensitive)
    #endif

    return regex?.firstMatch(in: self, options: [], range: NSMakeRange(0, self.characters.count)) != nil

在macOS和Ubuntu上都能成功编译。

我改进了@Azik的答案。我允许使用准则允许的更多特殊字符，并返回一些无效的额外边缘情况。

小组认为这里只允许本地部分的。_%+-是不正确的。参见@Anton Gogolev对这个问题的回答或参见下文:

The local-part of the email address may use any of these ASCII characters: uppercase and lowercase Latin letters A to Z and a to z; digits 0 to 9; special characters !#$%&'*+-/=?^_`{|}~; dot ., provided that it is not the first or last character unless quoted, and provided also that it does not appear consecutively unless quoted (e.g. John..Doe@example.com is not allowed but "John..Doe"@example.com is allowed); space and "(),:;<>@[\] characters are allowed with restrictions (they are only allowed inside a quoted string, as described in the paragraph below, and in addition, a backslash or double-quote must be preceded by a backslash); comments are allowed with parentheses at either end of the local-part; e.g. john.smith(comment)@example.com and (comment)john.smith@example.com are both equivalent to john.smith@example.com;

我使用的代码将不允许限制性的特殊字符，但将允许比这里的大多数答案更多的选项。我更喜欢更宽松的验证，而不是谨慎的错误。

if enteredText.contains("..") || enteredText.contains("@@") 
   || enteredText.hasPrefix(".") || enteredText.hasSuffix(".con"){
       return false
}

let emailFormat = "[A-Z0-9a-z.!#$%&'*+-/=?^_`{|}~]+@[A-Za-z0-9.-]+\\.[A-Za-z]{2,64}"
let emailPredicate = NSPredicate(format:"SELF MATCHES %@", emailFormat)     
return emailPredicate.evaluate(with: enteredText)

完美的正则表达式，如谷歌电子邮件

"^[A-Z0-9a-z][a-zA-Z0-9_.-]+@[A-Za-z0-9.-]+\\.[A-Za-z]{2,}"

对于那些还在寻找答案的人，请看看下面的框架;

ATGvalidator

它是一个基于规则的验证框架，可以处理大部分开箱即用的验证。最重要的是，它有表单验证器，支持同时验证多个文本字段。

要验证电子邮件字符串，请使用以下方法;

"abcd.hhs@some.com".satisfyAll(rules: [StringRegexRule.email]).status

如果你想验证从文本字段的电子邮件，尝试下面的代码;

textfield.validationRules = [StringRegexRule.email]
textfield.validationHandler = { result in
    // This block will be executed with relevant result whenever validation is done.
    print(result.status, result.errors)
}
// Below line is to manually trigger validation.
textfield.validateTextField()

如果您想在文本框中输入或当焦点更改到另一个字段时验证它，请添加以下行之一;

textfield.validateOnInputChange(true)
// or
textfield.validateOnFocusLoss(true)

请在链接处查看自述文件以获取更多用例。

@JeffersonBe的答案是接近的，但如果字符串是“包含someone@something.com一个有效的电子邮件”，这不是我们想要的。下面是String上的一个扩展，它工作得很好(并且允许测试有效的phoneNumber和其他数据检测器来引导。

/// Helper for various data detector matches.
/// Returns `true` iff the `String` matches the data detector type for the complete string.
func matchesDataDetector(type: NSTextCheckingResult.CheckingType, scheme: String? = nil) -> Bool {
    let dataDetector = try? NSDataDetector(types: type.rawValue)
    guard let firstMatch = dataDetector?.firstMatch(in: self, options: NSRegularExpression.MatchingOptions.reportCompletion, range: NSRange(location: 0, length: length)) else {
        return false
    }
    return firstMatch.range.location != NSNotFound
        // make sure the entire string is an email, not just contains an email
        && firstMatch.range.location == 0
        && firstMatch.range.length == length
        // make sure the link type matches if link scheme
        && (type != .link || scheme == nil || firstMatch.url?.scheme == scheme)
}
/// `true` iff the `String` is an email address in the proper form.
var isEmail: Bool {
    return matchesDataDetector(type: .link, scheme: "mailto")
}
/// `true` iff the `String` is a phone number in the proper form.
var isPhoneNumber: Bool {
    return matchesDataDetector(type: .phoneNumber)
}
/// number of characters in the `String` (required for above).
var length: Int {
    return self.characters.count
}